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9: Sites of Unsaturation

  • Page ID
    332809
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    Calculating Sites of Unsaturation

    When trying to determine a structure, it is useful to know how many sites of unsaturation (SU) there are in the molecule. This is also referred to as degrees of unsaturation (DU).

    Saturated molecules have all single bonds and no rings. Unsaturated molecules contain double bond(s), triple bond(s) and/or ring(s).

    A saturated molecule has the maximum number of hydrogen atoms possible to be an acyclic alkane:

    \[\text{H = (2 $\times$ C) + 2}\]

    Every pi bond or ring reduces the number of hydrogens by 2.

    The sites of unsaturation (SU) can be calculated with the following formula:

    \[\text{SU} = \frac{\text{#H on a saturated system $-$ #H on your compound}}{2}\]

    N = CH

    Ignore O

    X (halides) = H

    Try a couple:

    C5H12O                         SU:

    C5H10O                         SU:

    Benzoic Acid (C7H6O2)    SU:

    C6H13N                         SU:

    C4H9Cl                          SU:


    This page titled 9: Sites of Unsaturation is shared under a not declared license and was authored, remixed, and/or curated by Kate Graham.

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