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- https://chem.libretexts.org/Ancillary_Materials/Worksheets/Worksheets%3A_Inorganic_Chemistry/Structure_and_Reactivity_in_Organic_Biological_and_Inorganic_Chemistry/06%3A_Conformation/6.15%3A_Solutions_to_Selected_ProblemsIn the α-D-glucose isomer the dipoles of the ring oxygen and the C1 hydroxyl group opposing each other (therefore the overall effect is the molecule is less polar). In the β-D-glucose isomer, the dipo...In the α-D-glucose isomer the dipoles of the ring oxygen and the C1 hydroxyl group opposing each other (therefore the overall effect is the molecule is less polar). In the β-D-glucose isomer, the dipoles of the ring oxygen and the C1 hydroxyl group align each other (therefore the overall effect is the molecule is more polar).
- https://chem.libretexts.org/Ancillary_Materials/Worksheets/Worksheets%3A_Inorganic_Chemistry/Structure_and_Reactivity_in_Organic_Biological_and_Inorganic_Chemistry/06%3A_Conformation
- https://chem.libretexts.org/Ancillary_Materials/Worksheets/Worksheets%3A_Inorganic_Chemistry/Worksheets%3A_Structure_and_Reactivity_in_Organic_Biological_and_Inorganic_Chemistry/2%3A_Mathematical_Tools_in_Kinetics
- https://chem.libretexts.org/Ancillary_Materials/Worksheets/Worksheets%3A_Inorganic_Chemistry/Worksheets%3A_Structure_and_Reactivity_in_Organic_Biological_and_Inorganic_Chemistry/1%3A_Reaction_Kinetics/1.5%3A_Collisions_and_ConcentrationIn the following drawings, the molecules are closer together in the picture on the right than they are in the picture on the left. For example, if we need an equal number of red molecules and blue mol...In the following drawings, the molecules are closer together in the picture on the right than they are in the picture on the left. For example, if we need an equal number of red molecules and blue molecules, and red molecules weigh three times as much as blue molecules, we'll need to weigh out three times as much of the red stuff as the blue stuff.
- https://chem.libretexts.org/Ancillary_Materials/Worksheets/Worksheets%3A_Inorganic_Chemistry/Structure_and_Reactivity_in_Organic_Biological_and_Inorganic_Chemistry/05%3A_Stereochemistry/5.5%3A__Biological_Small_MoleculesAt the second bond from the chiral center, it is connected to only one H and has two bonds to another C (this is counted as two bonds to C and one to H). Since the era of thalidomide, however, a treme...At the second bond from the chiral center, it is connected to only one H and has two bonds to another C (this is counted as two bonds to C and one to H). Since the era of thalidomide, however, a tremendous amount of research in the field of synthetic organic chemistry has been devoted to methods of producing only one enantiomer of a useful compound and not the other.
- https://chem.libretexts.org/Ancillary_Materials/Worksheets/Worksheets%3A_Inorganic_Chemistry/Structure_and_Reactivity_in_Organic_Biological_and_Inorganic_Chemistry/06%3A_Conformation/6.01%3A_Introduction_to_ConformationThe sense of smell depends on thousands of different receptors in the organ, working conceptually on a lock-and-key basis: a molecule with a given shape can fit into a given receptor, and when it does...The sense of smell depends on thousands of different receptors in the organ, working conceptually on a lock-and-key basis: a molecule with a given shape can fit into a given receptor, and when it does, a signal is sent telling the nervous system that the organism has encountered that particular type of molecule, and the organism reacts appropriately.
- https://chem.libretexts.org/Ancillary_Materials/Worksheets/Worksheets%3A_Inorganic_Chemistry/Structure_and_Reactivity_in_Organic_Biological_and_Inorganic_Chemistry/04%3A_Introduction_to_Molecules
- https://chem.libretexts.org/Ancillary_Materials/Worksheets/Worksheets%3A_Inorganic_Chemistry/Structure_and_Reactivity_in_Organic_Biological_and_Inorganic_Chemistry/06%3A_Conformation/6.08%3A_Diamond_Lattice_DrawingsAt one end of the structure, we are beginning to draw the uplifted back of the chair, and at the other end is the downward footrest. Finally, remember that the equatorial hydrogens point outward, away...At one end of the structure, we are beginning to draw the uplifted back of the chair, and at the other end is the downward footrest. Finally, remember that the equatorial hydrogens point outward, away from the ring, so keep these lines pointing away from the center of the chair. This type of drawing is called a diamond lattice drawing, because the all-carbon structure of diamond can be constructed this way by extending the axial and equatorial lines into additional chairs.
- https://chem.libretexts.org/Ancillary_Materials/Worksheets/Worksheets%3A_Inorganic_Chemistry/Structure_and_Reactivity_in_Organic_Biological_and_Inorganic_Chemistry/Appendix%3A_Quick_Guide_to_Common_Organic_Structural_Features_and_Functional_Groups/FG5.__HalidesThe names of these compounds form the root names of other compounds having the same number of carbon atoms in a continuous chain. The names of these compounds are based on the names of alkanes, but th...The names of these compounds form the root names of other compounds having the same number of carbon atoms in a continuous chain. The names of these compounds are based on the names of alkanes, but the suffix of the name varies to indicate the functional group present. That is, the suffix of the compound is unchanged by the presence of the halogen, and the halogen is included as a prefix in the name.
- https://chem.libretexts.org/Ancillary_Materials/Worksheets/Worksheets%3A_Inorganic_Chemistry/Structure_and_Reactivity_in_Organic_Biological_and_Inorganic_Chemistry/02%3A_Introduction_to_Metals/2.4%3A_Application_Problems_with_Metals_(Worksheet)c) Calculate the number of atoms in the unit cell (always show work). d) Shade in selected atoms in the unit cell to give a 3:1 ratio of iron:nickel in the unit cell. e) Add a legend with shaded and n...c) Calculate the number of atoms in the unit cell (always show work). d) Shade in selected atoms in the unit cell to give a 3:1 ratio of iron:nickel in the unit cell. e) Add a legend with shaded and non-shaded circles so that it is clear which circle represents which atom. g) In the cubic diagram you made, put a letter beside each atom to indicate which of those layers (A or B or C) it is found in. h) Why does the addition of nickel to the steel make the material more difficult to bend or break?
- https://chem.libretexts.org/Ancillary_Materials/Worksheets/Worksheets%3A_Inorganic_Chemistry/Structure_and_Reactivity_in_Organic_Biological_and_Inorganic_Chemistry/04%3A_Introduction_to_Molecules/4.7%3A__Ionic_bondsAtoms in the upper right hand corner of the periodic table have a greater pull on their shared bonding electrons, while those in the lower left hand corner have a weaker attraction for the electrons i...Atoms in the upper right hand corner of the periodic table have a greater pull on their shared bonding electrons, while those in the lower left hand corner have a weaker attraction for the electrons in covalent bonds. Because it is so common that an element from the extreme left hand of the periodic table is present as a cation, and that elements on the extreme right carry negative charge, we can often assume that a compound containing an example of each will have at least one ionic bond.
