# Solutions to Chapter 1 Exercises

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E1.1:

a) The atomic number of P (phosphorus) is 15, meaning there are 15 protons. The mass number for the 31P isotope is 31, so:

15 protons + 16 neutrons = mass number 31

(recall that mass number is number of protons and neutrons).

(for parts b-d, use the same reasoning as above)

b) 15 protons + 17 neutrons = mass number 32

c) 17 protons + 20 neutrons = mass number 37

d) 1 proton + 2 neutrons = mass number 3

e) 6 protons + 8 neutrons = mass number 14

E1.2:

a) 1s22s22p3

b) 1s22s22p4

c) 1s22s22p5

d) 1s22s22p63s2

e) 1s22s22p6 (same as Neon atom)

f) 1s22s22p63s23p64s1

g) 1s22s22p63s23p6 (same as Argon atom)

h) 1s22s22p63s23p6 (same as Argon atom)

i) 1s22s22p63s23p4

j) 1s2 (same as Helium atom)

k) 1s22s22p63s23p6 (same as Argon atom)

E1.3:

E1.4:

E1.6: Below are full structural drawings, showing all carbons and hydrogens:

E1.8:

E1.10: There is only one constitutional isomer of ethanol: dimethyl ether CH3OCH3

E1.11:

E1.12:

a) carboxylate, sulfide, aromatic, two amide groups (one of which is cyclic)

b) tertiary alcohol, thioester

c) carboxylate, ketone

d) ether, primary amine, alkene

E1.14:

acetic acid: ethanoic acid

chloroform: trichloromethane

acetone: propanone (not 2-propanone, because the '2' in this case would be redundant: if the carbonyl carbon were not in the #2 position, the compound would be an aldehyde not a ketone)

E1.17: The linking group is a phosphate diester

This page titled Solutions to Chapter 1 Exercises is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.

This page titled Solutions to Chapter 1 Exercises is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by Tim Soderberg via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.