Browse through a biochemistry textbook and you will see any number of molecules with cyclic structures. Many of these cyclic structures are aromatic, and therefore planar. Many others, though, are composed of sp3-hybridized atoms, and it is these cyclic structures that are the topic of discussion in this section.
When discussing cyclic organic molecules, we will often use sugars as examples, because they are such important molecules in biological chemistry. It is important to recall that many sugars exist in aqueous solution as both open-chain and cyclic forms.
One thing that you should notice in the cyclic structure shown above is that atoms or groups bonded to tetrahedral ring carbons are either pointing up (out of the plane of the page) or down (into the plane of the page), as indicated by the use of dashed or solid wedge bonds. When two substituents on the same ring are both pointing toward the same side of the ring, they are said to be cis to each other. When they are pointed to opposite sides, they are said to be trans to each other.
Cyclopropane, cyclobutane, cyclopentane
Ring structures in organic molecules are usually five-membered or six-membered. Three-and four-membered rings are occasionally found in nature, but are significantly higher in energy. The relative instability of these smaller ring structures can be explained by a concept called angle strain, in which the four bonds around the sp3-hybridized carbons are forced out of their preferred tetrahedral angles. This strain is partially overcome by using so-called “banana bonds”, where the overlap between orbitals is no longer directly in a line between the two nuclei, as shown here in three representations of the bonding in cyclopropane:
Cyclopropane, showing the formation of “banana bonds”. Images courtesy of Wikimedia Commons, CC-BY-SA license
Rings larger than 3 carbons have 3 dimensional shapes that relieve this bond strain, but it’s important to note that bond strain does affect stability. For cyclopropane and cyclobutane, the strain energy is about 110 kJ/mol. Cyclobutane can enter a “puckered” formation that slightly relieves some torsional strain. Cyclopentane, which is non-planar can remove some of the strain and has only about 25 kJ/mol of strain.
If one of the carbon-carbon bonds is broken, the ring will ‘spring’ open, releasing energy as the bonds reassume their preferred tetrahedral geometry. The effectiveness of two antibiotic drugs, fosfomycin and penicillin, is due in large part to the high reactivity of the three- and four-membered rings in their structures.
The lowest energy conformation of cyclopentane and other five-membered rings is known as the ‘envelope’, with four of the ring atoms in the same plane and one out of plane (notice that this shape resembles an envelope with the flap open). The out-of-plane carbon is said to be in the endo position (‘endo’ means ‘inside’).
The ‘equatorial’ vs ‘axial’ distinction discussed in the context of 6-membered rings does not apply to five-membered rings.
At room temperature, cyclopentane undergoes a rapid pseudorotation process in which each of the five carbons takes turns being in the endo position.
One of the most important five-membered rings in nature is a sugar called ribose – DNA and RNA are both constructed upon ‘backbones’ derived from ribose. Pictured below is one thymidine (T) deoxy-nucleotide from a stretch of DNA:
The lowest-energy conformations for ribose are envelope forms in which either C3 or C2 are endo, on the same side as the C5 substituent.
Cyclohexane and its derivatives
In six-membered cycloalkane structures, bonding angles are close to tetrahedral, and thus ring strain is not a factor – these rings are in fact very stable. However, the ‘flat’ drawings we have been using up to now do not accurately show the actual three-dimensional shape of a five- or six-membered ring. If cyclohexane were indeed flat, the bond angles would have to be distorted from 109.5 ° to 120 ° . If you build a model, though, you will find that when you rotate the carbon-carbon bonds so as to put the ring into a shape that resembles a reclining beach chair, all of the carbon-carbon bonds are able to assume tetrahedral bonding angles.
This chair conformation is the lowest energy conformation for cyclohexane and other six-membered rings.
An alternate conformation for a six-membered ring is called the ‘boat’:
In the boat conformation, two of the substituents – those on the ‘bow’ and the ‘stern’ if you will – are brought close enough to each other to cause steric strain. An additional cause of the higher energy of the boat conformation is that adjacent hydrogen atoms on the ‘bottom of the boat’ are forced into eclipsed positions. For these reasons, the boat conformation is a high energy conformation of cyclohexane, about 30 kJ/mol less stable than the chair conformation.
If you look carefully at your model of cyclohexane in the chair conformation, you will see that all twelve hydrogens are not equivalent in terms of their three-dimensional arrangement in space. Six hydrogens are axial – that is, they are pointing either straight up or straight down relative to the ring. The other six hydrogens are equatorial, meaning that they are pointing away from the perimeter of the ring, either slightly up or slightly down. (The equatorial vs axial distinction is often hard to see at first – it would be a very good idea at this point to sit down with your instructor or tutor and work with a modeling kit).
This is not the only possible chair conformation for cyclohexane. On your model, rotate one of the ‘up’ carbons down, and one of the ‘down’ carbons up. You now have a new, alternate chair conformation – this process is called ring inversion.
What you should recognize here is that, as a result of the ring inversion process, all of the axial and equatorial hydrogens have traded positions – axial hydrogens have become equatorial, and vice-versa. Notice, however, that the ‘down’ hydrogens are still pointing down, and the ‘up’ hydrogens are still pointing up regardless of whether they are axial or equatorial. At room temperature, cyclohexane is constantly inverting between two chair forms of equal energy – it is a rapid equilibrium situation. Thus, except at very low temperatures, we are not able to distinguish between axial and equatorial hydrogens, as they are constantly switching back and forth.
Axial/equatorial vs cis/trans
A very common error made by organic chemistry students as they begin to learn about chair conformations is to confuse the terms axial and equatorial with the terms cis and trans. These are completely different things! For example, when two substituents on a ring are cis in relation to one another, it means that they are pointed to the same side of the ring (both up or both down). Depending on their positions on the ring, they might both be axial, both be equatorial, or one of each.
Do not make the mistake of calling two substituents trans to each other merely because one is equatorial and one is axial, or cis because the are both axial or both equatorial.
How to draw the cyclohexane chair conformation
As an organic chemistry student, you will be expected to be able to draw an accurate representation of the chair conformations of six-membered cycloalkanes, which includes being able to draw axial and equatorial substituents with their correct orientations. Here, then, are some guidelines to follow:
How not to draw the chair:
What happens to the relative energies of chair conformations when the ring has a large substituent, such as a methyl group? Now, the two chair conformations are quite different: in one, the methyl group is equatorial and in the other it is axial.
When the methyl group is in the axial position, it is brought close enough to the axial hydrogens on carbons two bonds away to cause destabilizing steric repulsion: this is referred to as 1,3-diaxial repulsion.
When in the equatorial position, the methyl group is pointing up and away from the rest of the ring, eliminating the unfavorable 1,3-diaxial interaction. As a consequence, the conformation in which the methyl group is in the equatorial position is more stable, by approximately 7 kJ/mol. At room temperature, methylcyclohexane exists as a rapid equilibrium between the two chair forms (and many other intermediate conformations), but the equilibrium constant (Keq) favors the conformation where the methyl group is equatorial.
Here’s some General Chemistry review: what is the value of Keq at 25 oC for the axial to equatorial interconversion of methylcyclohexane as shown in the previous figure?
[reveal-answer q=”830121″]Show Solution[/reveal-answer]
[hidden-answer a=”830121″]Recall from your General Chemistry course that DG0, the standard Gibbs Free Energy change of a reaction (or in this case, a conformational change) is related to the equilibrium constant Keq by:
D G0 = RTlnKeq or Keq = e^(- D G0/RT)
. . . where R is the gas constant 8.314 J mol-1 K-1
Using T = 298K (25oC) and DG0 = -7.0 kJ/mol, we calculate Keq = 17.
Note that D G0 has a negative value because the methyl-axial to methyl-equatorial ring flip is an energetically downhill process. Because the equatorial conformation is more stable, it makes sense that the equilibrium constant for the ring flip is greater than 1.
In the case of a disubstituted cyclohexane ring in which both substituents cannot be equatorial, the lower energy conformation generally places the bulkier substituent in the equatorial position.
As a general rule, the most stable chair conformation of a six-membered ring will be that in which the bulkiest groups are in the equatorial position .
Draw the lower energy chair conformations of a) trans-1,2-dimethylcyclohexane, and b) trans-1-isopropyl-3-methylcyclohexane. Draw all substituents on all carbons (including hydrogens), being sure that the axial or equatorial orientation is clear. Be sure to check your drawing with your instructor or tutor.
[reveal-answer q=”78441″]Show Solution[/reveal-answer]
Note in (b) that one of the substituents must be in the axial position. In the lower energy chair conformation, it is the smaller methyl group that assumes the axial position.
Predict which of the following disubstituted hexanes has a greater energy difference between its two chair conformations, and state your reasons for your choices.
a) cis-1,3-dimethylcyclohexane or cis-1,4-dimethylcyclohexane
b) cis-1,2-dimethylcyclohexane or trans-1,2-dimethylcyclohexane
c) trans-1,2-dimethylcyclohexane or trans-1-isopropyl-2-methylcyclohexane
[reveal-answer q=”814382″]Show Solution[/reveal-answer]
To answer these questions, you will want to draw out the chair conformations of the compounds specified.
a) cis -1 ,3-dimethylcyclohexane : the two methyl groups are either both equatorial or both axial. In cis-1,4-dimethylcyclohexane, one methyl group is always axial and one equatorial, so the two conformations have the same energy.
b) trans-1,2-dimethylcyclohexane: the two methyl groups are either both equatorial or both axial. In cis-1,2-dimethylcyclohexane, one methyl group is always axial and one equatorial, so the two conformations have the same energy.
c) trans-1-isopropyl-2-methylcyclohexane: both compounds are either diaxial or diequatorial, but the larger isopropyl substituent means that the difference between the diaxial and diequatorial conformations is larger.
Can a ‘ring inversion’ change a cis-disubstituted cyclohexane to trans? Explain.
[reveal-answer q=”881822″]Show Solution[/reveal-answer]
No. In order to change the relationship of two substituents on a ring from cis to trans, you would need to break and reform two covalent bonds. Ring flips involve only rotation of single bonds[/hidden-answer]
Recall that five- and six-carbon sugars such as glucose and fructose exist in solution in open chain and cyclic forms. Glucose, in its most abundant form in solution, is a six-membered ring adopting a chair conformation with all substituents equatorial.
The most abundant form of fructose in aqueous solution is also a six-membered ring.
The lower energy chair conformation is the one with three of the five substituents (including the bulky –CH2OH group) in the equatorial position.
Draw the two chair conformations of the six-carbon sugar mannose, being sure to clearly show each non-hydrogen substituent as axial or equatorial. Predict which conformation is likely to be more stable, and explain why.[reveal-answer q=”267065″]Show Solution[/reveal-answer]
This has very important implications for oligonucleotide structure – in DNA, it is C2 that is in the endo position, while in RNA it is C3.
- Description of strain in small rings. Authored by: Pete Davis, Fayetteville, AK. Located at: https://en.wikibooks.org/wiki/Organic_Chemistry/Cycloalkanes. Project: Wikibooks. License: CC BY-SA: Attribution-ShareAlike
- 3.2: Conformations of cyclic organic molecules. Authored by: u00a0Tim Soderbergu00a0(University of Minnesota, Morris). Located at: https://chem.libretexts.org/Textbook_Maps/Organic_Chemistry/Book%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)/Chapter_03%3A_Conformations_and_Stereochemistry/03.2%3A_Conformations_of_cyclic_organic_molecules. Project: Chemistry LibreTexts. License: CC BY-NC-SA: Attribution-NonCommercial-ShareAlike