8.9: Exercises
- Page ID
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- What are all the conversion factors that can be constructed from the balanced chemical reaction: 2 S(s) + 3 O2(g) → 2 SO3(g)?
- Answer
-
\(\dfrac{2\;\mathrm{mol}\;{\mathrm S}}{3\;\mathrm{mol}\;{\mathrm O}_2}\); \(\dfrac{3\;\mathrm{mol}\;{\mathrm O}_2}{2\;\mathrm{mol}\;{\mathrm S}}\); \(\dfrac{1\;\mathrm{mol}\;{\mathrm S}}{1\;\mathrm{mol}\;{\mathrm S}{\mathrm O}_3}\); \(\dfrac{1\;\mathrm{mol}\;{\mathrm S}{\mathrm O}_3}{1\;\mathrm{mol}\;{\mathrm S}}\); \(\dfrac{3\;\mathrm{mol}\;{\mathrm O}_2}{2\;\mathrm{mol}\;{\mathrm S}{\mathrm O}_3}\); \(\dfrac{2\;\mathrm{mol}\;{\mathrm S}{\mathrm O}_3}{3\;\mathrm{mol}\;{\mathrm O}_2}\)
- Construct the three independent conversion factors possible for these two reactions:
- 2 H2 + O2 → 2 H2O
- H2 + O2 → H2O2
Why are the ratios between H2 and O2 different?
- Answer
-
The conversion factors are different because the stoichiometries of the balanced chemical reactions are different.
8.4: Molar Ratios and Mole-to-Mole Conversions
- Given the chemical equation: Na(s) + H2O(l) → NaOH(aq) + H2(g)
- Balance the equation.
- How many moles of H2 are produced when 332 moles of Na react?
- Answer
-
- 2 Na(s) + 2 H2O(l) → 2 NaOH(aq) + H2(g)
- 166 mol H2
- Given the chemical equation: S(s) + O2(g) → SO3(g)
- Balance the equation.
- How many moles of O2 are needed when 38 moles of S react?
- Answer
-
- 2 S(s) + 3 O2(g) → 2 SO3(g)
- 57 mol O2
- For the balanced chemical equation:
6 H+(aq) + 2 MnO4−(aq) + 5 H2O2(l) → 2 Mn2+(aq) + 5 O2(g) + 8 H2O(l)
how many moles of H2O are produced when 75 moles of H2O2 react?
- Answer
-
120 mol H2O
-
For the balanced chemical reaction:
2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(l)
how many moles of CO2 are produced when 56 moles of C6H6 react?
- Answer
-
3.4 × 102 mol CO2
-
For the balanced chemical equation:
Fe2O3 + 3 SO3 → Fe2(SO4)3
suppose we need to make 145 moles of Fe2(SO4)3. How many moles of SO3 do we need?
- Answer
-
435 mol SO3
- One way to make sulfur hexafluoride is to react thioformaldehyde, CH2S, with elemental fluorine:
CH2S + 6 F2 → CF4 + 2 HF + SF6
If 45.8 moles of SF6 are needed, how many moles of F2 are required?
- Answer
-
275 mol F2
-
For the balanced chemical equation:
3 Cu(s) + 2 NO3−(aq) + 8 H+(aq) → 3 Cu2+(aq) + 4 H2O(l) + 2 NO(g)
how many moles of Cu2+ are formed when 55.7 mol of H+ are reacted?
- Answer
-
20.9 mol Cu2+
-
For the balanced chemical equation:
Al(s) + 3 Ag+(aq) → Al3+(aq) + 3 Ag(s)
how many moles of Ag are produced when 0.661 mol of Al are reacted?
- Answer
-
1.98 mol Ag
-
For the balanced chemical reaction:
4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l)
how many moles of H2O are produced when 0.669 mol of NH3 react?
- Answer
-
1.00 mol H2O
-
For the balanced chemical reaction:
4 NaOH(aq) + 2 S(s) + 3 O2(g) → 2 Na2SO4(aq) + 2 H2O(l)
how many moles of Na2SO4 are formed when 1.22 mol of O2 react?
- Answer
-
0.813 mol Na2SO4
-
For the balanced chemical reaction:
4 KO2(s) + 2 CO2(g) → 2 K2CO3(s) + 3 O2(g)
determine the number of moles of both products formed when 6.88 mol of KO2 react.
- Answer
-
3.44 mol K2CO3; 5.16 mol O2
- For the balanced chemical reaction
- Answer
-
0.0276 mol Al2O3; 0.166 mol HCl
8.5: Mass-to-Mass Conversions
- What mass of CO2 is produced by the combustion of 1.00 mol of CH4?
CH4(g) + 2 O2(g) → CO2(g) + 2H2O(l)
- Answer
-
44.0 g CO2
- What mass of H2O is produced by the combustion of 1.00 mol of CH4?
CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l)
- Answer
-
36.0 g H2O
- What mass of HgO is required to produce 0.692 mol of O2?
2 HgO(s) → 2 Hg(l) + O2(g)
- Answer
-
3.00 × 102 g HgO
- What mass of NaHCO3 is needed to produce 2.659 mol of CO2?
2 NaHCO3(s) → Na2CO3(s) + H2O(l) + CO2(g)
- Answer
-
446.8 g NaHCO3
- How many moles of Al can be produced from 10.87 g of Ag?
Al(NO3)3(aq)+ 3 Ag(s) → Al(s) + 3 AgNO3(aq)
- Answer
-
0.03359 mol Al
- How many moles of HCl can be produced from 0.226 g of SOCl2?
SOCl2(l) + H2O(l) → SO2(g) + 2 HCl(g)
- Answer
-
3.80 × 10−3 mol HCl
- How many moles of O2 are needed to prepare 1.00 g of Ca(NO3)2?
Ca(s) + N2(g) + 3 O2(g) → Ca(NO3)2(s)
- Answer
-
0.0183 mol O2
- How many moles of C2H5OH are needed to generate 106.7 g of H2O?
C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(l)
- Answer
-
1.974 mol C2H5OH
- What mass of O2 can be generated by the decomposition of 100.0 g of NaClO3?
2 NaClO3(s) → 2 NaCl(s) + 3 O2(g)
- Answer
-
45.10 g O2
- What mass of Li2O is needed to react with 1,060 g of CO2?
Li2O(aq) + CO2(g) → Li2CO3(aq)
- Answer
-
7.20 × 102 g Li2O
- What mass of Fe2O3 must be reacted to generate 324 g of Al2O3?
Fe2O3(s) + 2 Al(s) → 2 Fe(s) + Al2O3(s)
- Answer
-
507 g Fe2O3
- What mass of Fe is generated when 100.0 g of Al are reacted?
Fe2O3(s) + 2 Al(s) → 2 Fe(s) + Al2O3(s)
- Answer
-
207.0 g Fe
- What mass of MnO2 is produced when 445 g of H2O are reacted?
H2O(l) + 2 MnO4−(aq) + Br−(aq) → BrO3−(aq) + 2 MnO2(s) + 2 OH−(aq)
- Answer
-
4290 g MnO2
- What mass of PbSO4 is produced when 29.6 g of H2SO4 are reacted?
Pb(s) + PbO2(s) + 2 H2SO4(aq) → 2 PbSO4(s) + 2 H2O(l)
- Answer
-
91.5 g PbSO4
- If 83.9 g of ZnO are formed, what mass of Mn2O3 is formed with it?
Zn(s) + 2 MnO2(s) → ZnO(s) + Mn2O3(s)
- Answer
-
163 g Mn2O3
- If 14.7 g of NO2 are reacted, what mass of H2O is reacted with it?
3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g)
- Answer
-
1.92 g H2O
- If 88.4 g of CH2S are reacted, what mass of HF is produced?
CH2S + 6 F2 → CF4 + 2 HF + SF6
- Answer
-
76.7 g HF
- If 100.0 g of Cl2 are needed, what mass of NaOCl must be reacted?
NaOCl + HCl → NaOH + Cl2
- Answer
-
105.0 g NaOCl
- Calculate the mass of each product when 100.0 g of CuCl react according to the reaction
2 CuCl(aq) → CuCl2(aq) + Cu(s)
What do you notice about the sum of the masses of the products? What concept is being illustrated here?
- Answer
-
67.90 g CuCl2; 32.10 g Cu; the sum is 100.0 g; this agrees with the Law of Conservation of Mass
- Calculate the mass of each product when 500.0 g of SnCl2 react according to the reaction
2 SnCl2(aq) → SnCl4(aq) + Sn(s)
What do you notice about the sum of the masses of the products? What concept is being illustrated here?
- Answer
-
343.5 g SnCl4; 156.5 g Sn; the sum is 500.0 g; this agrees with the Law of Conservation of Mass
- Write the balanced equation and then determine the number of moles and the mass of chlorine, Cl2, required to react with 10.0 g of sodium metal, Na, to produce sodium chloride, NaCl.
- Answer
-
2 Na + Cl2 → 2 NaCl; 0.217 mol Cl2; 15.4 g Cl2
- Write the balanced equation and then determine the number of moles and the mass of oxygen formed by the decomposition of 1.252 g of mercury(II) oxide.
- Answer
-
2 HgO → 2 Hg + O2; 2.851 × 10−3 mol O2; 0.09122 g O2
- Write the balanced equation and then determine the number of moles and the mass of sodium nitrate, NaNO3, required to produce 128 g of oxygen. (NaNO2 is the other product.)
- Answer
-
2 NaNO3 → O2 + 2 NaNO2; 8.00 mol NaNO3; 6.80 × 102 g NaNO3
- Write the balanced equation and then determine the number of moles and the mass of carbon dioxide formed by the combustion of 20.0 g of carbon in an excess of oxygen.
- Answer
-
C + O2 → CO2; 1.67 mol CO2; 73.3 g CO2
- Write the balanced equation and then determine the number of moles and the mass of Mg required to react with 5.00 g of HCl and produce MgCl2 and H2.
- Answer
-
Mg + 2 HCl → MgCl2 + H2; 0.0686 mol Mg; 1.67 g Mg
- Write the balanced equation and then determine the number of moles and the mass of oxygen formed by the decomposition of 1.252 g of silver(I) oxide.
- Answer
-
2 Ag2O → O2 + 4 Ag; 2.902 × 10−3 mol O2; 0.09285 g O2
- Write the balanced equation and then determine the number of moles and the mass of water formed by the combustion of 20.0 g of acetylene, C2H2, in an excess of oxygen.
- Answer
-
2 C2H2 + 5 O2 → 4 CO2 + 2 H2O; 0.768 g H2O; 13.8 g H2O
- Write the balanced equation and then determine the number of moles and the mass of barium peroxide, BaO2, needed to produce 2.500 g of barium oxide, BaO (O2 is the other product.)
- Answer
-
2 BaO2 → 2 BaO + O2; 0.01630 mol BaO2; 2.761 g BaO2
- I2 is produced by the reaction of 0.4235 mol of CuCl2 according to the following equation: 2 CuCl2 + 4 KI → 2 CuI + 4 KCl + I2
- How many moles of I2 are produced?
- What mass of I2 is produced?
- Answer
-
- 0.2118 mol I2
- 53.74 g I2
- Silver is often extracted from ores as K[Ag(CN)2] and then recovered by the reaction: 2 K[Ag(CN)2] + Zn → 2 Ag + Zn(CN)2 + 2 KCN
- How many moles of Zn(CN)2 are produced by the reaction of 35.27 g of K[Ag(CN)2]?
- What mass of Zn(CN)2 is produced?
- Answer
-
- 0.08861 mol Zn(CN)2
- 10.41 g Zn(CN)2
8.6: Limiting Reactants and Excess Reactants
- Given the statement “20.0 g of methane is burned in excess oxygen,” is it obvious which reactant is the limiting reactant?
- Answer
-
Yes. If oxygen is in excess, the methane must be the limiting reactant.
- Given the statement “the metal is heated in the presence of excess hydrogen,” is it obvious which substance is the limiting reactant despite not specifying any quantity of reactant?
- Answer
-
Yes. If the hydrogen is in excess, the metal must be the limiting reactant.
- Acetylene (C2H2) is formed by reacting 7.08 g of C and 4.92 g of H2.
2 C(s) + H2(g) → C2H2(g)
What is the limiting reactant? How many grams of C2H2 are produced?
- Answer
-
Limiting reactant = C; 7.67 g C2H2
- Ethane (C2H6) is formed by reacting 7.08 g of C and 4.92 g of H2.
2 C(s) + 3 H2(g) → C2H6(g)
What is the limiting reactant? How many grams of C2H6 are produced?
- Answer
-
Limiting reactant = C; 8.86 g C2H6
- If 35.6 g of P4O6 is reacted with 4.77 g of H2O, what is the limiting reactant, and what mass of H3PO3 is produced?
P4O6(s) + 6 H2O(l) → 4 H3PO3(aq)
- Answer
-
Limiting reactant = H2O; 14.5 g H3PO3
- If 377 g of NO2 is reacted with 244 g of H2O, what is the limiting reactant, and how many grams of HNO3 and NO are produced?
3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g)
- Answer
-
Limiting reactant = NO2; 344 g HNO3 and 82.0 g NO
- To form the precipitate PbCl2, 2.88 g of NaCl and 7.21 g of Pb(NO3)2 are mixed in solution. How much precipitate is formed? How much of which reactant is in excess?
2 NaCl(aq) + Pb(NO3)2(aq) → PbCl2(s) + 2 NaNO3(aq)
- Answer
-
6.06 g PbCl2 formed; 0.34 g excess NaCl
- In a neutralization reaction, 18.06 g of KOH are reacted with 13.43 g of HNO3. What mass of H2O is produced, and what mass of which reactant is in excess?
KOH(aq) + HNO3(aq) → KNO3(aq) + H2O(l)
- Answer
-
3.839 g H2O formed; 6.10 g excess KOH
- What is the limiting reactant in a reaction that produces sodium chloride from 8 g of sodium and 8 g of diatomic chlorine?
2 Na(s) + Cl2(g) → 2 NaCl(s)
- Answer
-
Cl2
- What is the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g)
- Answer
-
O2
- What is the limiting reactant when 0.50 g of Cr and 0.75 g of H3PO4 react according to the following chemical equation?
2 Cr(s) + 2 H3PO4(aq) → 2 CrPO4(s) + 3 H2(g)
- Answer
-
H3PO4
- What is the limiting reactant when 1.50 g of lithium and 1.50 g of nitrogen combine to form lithium nitride, a component of advanced batteries, according to the following unbalanced equation?
Li + N2 → Li3N
- Answer
-
Li
8.7: Theoretical Yield and Percent Yield
- What is the difference between the theoretical yield and the actual yield?
- Answer
-
Theoretical yield is what you expect stoichiometrically from a chemical reaction; actual yield is what you actually get from a chemical reaction.
- What is the difference between the actual yield and the percent yield?
- Answer
-
Actual yield is the measured amount of product obtained from a chemical reaction; percent yield is the ratio of the actual yield to the amount predicted from stoichiometry.
- A worker isolates 2.675 g of SiF4 after reacting 2.339 g of SiO2 with HF. What are the theoretical yield and the actual yield?
SiO2(s) + 4 HF(g) → SiF4(g) + 2 H2O(l)
- Answer
-
Theoretical yield = 4.052 g; actual yield = 2.675 g
- A worker synthesizes aspirin, C9H8O4, according to this chemical equation. If 12.66 g of C7H6O3 are reacted and 12.03 g of aspirin are isolated, what are the theoretical yield and the actual yield?
C7H6O3 + C4H6O3 → C9H8O4 + HC2H3O2
- Answer
-
Theoretical yield = 16.51 g; actual yield = 12.03 g
- A chemist decomposes 1.006 g of NaHCO3 and obtains 0.0334 g of Na2CO3. What are the theoretical yield and the actual yield?
2 NaHCO3(s) → Na2CO3(s) + H2O(l) + CO2(g)
- Answer
-
Theoretical yield = 0.6346 g; actual yield = 0.0334 g
- A chemist combusts a 3.009 g sample of C5H12 and obtains 3.774 g of H2O. What are the theoretical yield and the actual yield?
C5H12(l) + 8 O2(g) → 5 CO2(g)+ 6 H2O(l)
- Answer
-
Theoretical yield = 4.508 g; actual yield = 3.774 g
- What is the percent yield in Exercise 59?
- Answer
-
66.02%
- What is the percent yield in Exercise 60?
- Answer
-
72.86%
- What is the percent yield in Exercise 61?
- Answer
-
5.26%
- What is the percent yield in Exercise 62?
- Answer
-
83.72%
- A student isolated 25 g of a compound following a procedure that would theoretically yield 81 g. What was his percent yield?
- Answer
-
31%
- A sample of 0.53 g of carbon dioxide was obtained by heating 1.31 g of calcium carbonate. What is the percent yield for this reaction?
CaCO3(s) → CaO(s) + CO2(g)
- Answer
-
91%
- The phosphorus pentoxide used to produce phosphoric acid for cola soft drinks is prepared by burning phosphorus in oxygen.
- What is the limiting reactant when 0.200 mol of P4 and 0.200 mol of O2 react according to the reaction: P4 + 5 O2 → P4O10?
- Calculate the percent yield if 10.0 g of P4O10 is isolated from the reaction.
- Answer
-
- O2
- 87.7%
This page was adapted from "Beginning Chemistry (Ball)" by LibreTexts and is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by Vicki MacMurdo (Anoka-Ramsey Community College) and Lance S. Lund (Anoka-Ramsey Community College).