6.8: Percent-By-Mass Composition
- Page ID
- 289388
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⚙️ Learning Objectives
- Determine percent composition of each element in a compound based on mass.
Packaged foods that you eat typically have nutritional information provided on the label. The label on a jar of peanut butter reveals that one serving size is considered to be \(32 \: \text{g}\). The label also gives the masses of various types of compounds that are present in each serving. One serving contains 7 g of protein, 15 g of fat, and 3 g of sugar. By calculating the fraction of protein, fat, or sugar in one serving size of peanut butter and converting to percent values, we can determine the composition of peanut butter on a percent by mass basis.
Percent Composition
Chemists often need to know what elements are present in a compound and in what percentage. In general, percentages may be found by taking the part, dividing it by the whole and multiplying by 100:
\[\%=\frac{\mathrm{part}}{\mathrm{whole}}\times100\]
The percent-by-mass composition is the percent by mass of each element in a compound. It is calculated in a similar way to that of the composition of the peanut butter.
\[\% \: \text{by mass} = \dfrac{\text{mass of element in compound}}{\text{mass of compound}} \times 100\%\]
The sample problem below shows the calculation of the percent composition of a compound based on mass data.
✅ Example \(\PageIndex{1}\): Percent Composition from Mass Data
A certain newly synthesized compound is known to contain the elements zinc and oxygen. When a 20.00 g sample of this compound is decomposed, 16.07 g of zinc remains. Determine the percent-by-mass composition of the compound.
Solution
| Steps for Problem Solving | |
|---|---|
| Identify the "given" information and what the problem is asking you to "find." | Given : Mass of compound = 20.00 g Mass of Zn = 16.07 g Find: % Composition (%Zn and %O) |
| List known relationships. | Subtract to find the mass of oxygen in the compound. Mass of oxygen = 20.00 g - 16.07 g = 3.93 g O |
| Calculate the answers. | Calculate the percent by mass of each element by dividing the mass of that element by the mass of the compound and multiplying by 100%. \(\%\:\mathrm{Zn}=\dfrac{16.07\:\text{g}\:\mathrm{Zn}}{20.00\:\text{g}}\times100\%=\boxed{80.35\%\:\mathrm{Zn}}\) \(\%\:\mathrm O=\dfrac{3.93\:\text{g}\:\mathrm O}{20.00\:\text{g}}\times100\%=\boxed{19.65\%\:\mathrm O}\) |
| Think about your result. | The calculations make sense because the sum of the two percentages adds up to 100%. By mass, the compound is mostly zinc. |
✏️ Exercise \(\PageIndex{1}\)
Sulfuric acid, H2SO4 is a very useful chemical in industrial processes. If 196.0 g of sulfuric acid contained 64.0 g of sulfur and 4.0 g of hydrogen, what is the percent composition of the compound?
- Answer
- 2.0% H, 32.7% S, and 65.31% O
Summary
- Processes are described for calculating the percent composition of a compound based on mass.
This page is shared under a CK-12 license and was authored, remixed, and/or curated by Melissa Alviar-Agnew, Henry Agnew, Vicki MacMurdo (Anoka-Ramsey Community College), and Lance S. Lund (Anoka-Ramsey Community College).

