6.4: Chapter 6 Problem
An underlined problem number or problem-part letter indicates that the numerical answer appears in Appendix I.
6.1
Calculate the molar entropy of carbon disulfide at \(25.00\units{\(\degC\)}\) and \(1\br\) from the heat capacity data for the solid in Table 6.2 and the following data for \(p=1\br\). At the melting point, \(161.11\K\), the molar enthalpy of fusion is \(\Delsub{fus}H = 4.39\timesten{3}\units{J mol\(^{-1}\)}\). The molar heat capacity of the liquid in the range 161–300 K is described by \(\Cpm = a + bT\), where the constants have the values \(a = 74.6\units{J K\(^{-1}\) mol\(^{-1}\)}\) and \(b = 0.0034\units{J K\(^{-2}\) mol\(^{-1}\)}\).