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6.7: Periodic Trends, Lewis Dot Diagrams, and Formal Charge

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    Periodic trends

    Inside an atom, negatively-charged electrons are attracted to the positively-charged nucleus, but they repel each other. Electrons close to the nucleus can shield the outermost electrons from Coulomb forces between the electrons and the nucleus.

    Going across a row in the periodic table, each element has one extra electron and one extra proton. The additional proton has a strong effect on the electrons, as the number of inner shielding electrons does not change. However, when going down a period, there are more and more shells of electrons with increasing energy and average radius from the nucleus. Therefore, atomic radius decreases from left to right across the rows of the periodic table, and increases from top to bottom.

    When atoms become ionized, their atomic radius changes as the charge state balance changes. If an atom gains electrons to become negatively charged, it is called an anion. If an atom loses electrons to become positively charged, it is called a cation. Cations are typically smaller than the neutral version of the atom, while anions are typically larger. An ionic solid contains cations and anions in a ratio that maintains charge neutrality.

    Example: Arrange \(\mathrm{Al}, \mathrm{C}\), and \(\mathrm{Si}\) in order of increasing atomic radius.

    Answer

    Carbon is in the second period of the periodic table, while \(\mathrm{Al}\) and \(\mathrm{Si}\) are in the third: \(\mathrm{C}\) must be the smallest. \(\mathrm{Al}\) is in group III, while \(\mathrm{Si}\) is in group IV, so \(\mathrm{Al}\) is likely larger than \(\mathrm{Si}\) due to relatively strong effect of the extra proton \(\mathrm{Si}\) has.

    (smallest) \(\quad \mathrm{C} \rightarrow \mathrm{Si} \rightarrow \mathrm{Al} \quad\) (largest)

    Lewis Dot Diagrams

    Lewis dot diagrams are a tool used to visualize the valence electrons in atoms. Then, by pairing up electrons, we can visualize possible ways that bonds can be formed between two atoms.

    There are a couple of rules of thumb that come in handy when drawing Lewis dot diagrams. The octet rule tells us that atoms gain, lose, or share electrons in order to have a full valence shell of 8 electrons (2 for \(\mathrm{H}\) and \(\mathrm{He}\) ). Also, the number of valence electrons in an atom is equal to the group number. We can generally start by following these steps:

    1. Determine the number of valence electrons in each atom in the compound
    2. Place a bonding pair between adjacent atoms
    3. Starting from terminal atoms, add electrons to form octets

    Example: Draw Lewis dot diagrams for the following compounds: \(\mathrm{CH}_4, \mathrm{CCl}_4, \mathrm{CO}_2\), and \(\mathrm{OH}^{-}\)

    Answer

    \(\mathrm{CH}_4\): \(\mathrm{C}\) has 4 valence electrons (group IV), while hydrogen just has one. Sharing four electrons between the \(\mathrm{C}\) and \(\mathrm{H}\)'s yields an octet on the carbon atom and a complete shell of two electrons on the hydrogen. Note that it's often convenient to put the atom that has the most unpaired electrons in the middle.

    Screen Shot 2022-09-06 at 10.46.11 PM.png

    \(\mathrm{CCl}_4\): Again, \(\mathrm{C}\) has \(4\) valence electrons, and \(\mathrm{Cl}\) has \(7\). \(\mathrm{Cl}\) can only gain one additional electron to have a full octet, so each \(\mathrm{Cl}\) only makes one bond. Therefore, we can put \(\mathrm{C}\) in the middle again and surround it with \(\mathrm{Cl}\) atoms, and every atom has a full octet.

    Screen Shot 2022-09-06 at 10.54.04 PM.png

    \(\mathrm{CO}_2\): \(\mathrm{C}\) has 4 valence electrons, while \(\mathrm{O}\) has 6. We can start by placing the \(\mathrm{C}\) in the middle and forming a bond with each \(\mathrm{O}\). The structure that results is unstable, because each \(\mathrm{O}\) is left with an unpaired electron. \(\mathrm{C}\) also has two unpaired electrons leftover. We can use them to form double bonds between the \(\mathrm{C}\) and each \(\mathrm{O}\) without violating the octet rule. Note that each \(\mathrm{O}\) is left with two lone pairs.

    Screen Shot 2022-09-06 at 10.56.01 PM.png

    \(\mathrm{OH}^{-}\): Here, the oxygen brings 6 valence electrons and the \(\mathrm{H}\) brings just one, but there is an additional electron in play because of the structure's overall negative charge. After forming a single bond between the \(\mathrm{O}\) and the \(\mathrm{H}\), we're left with unpaired electrons, so we need to rearrange some more. We can't make a double bond to the hydrogen, as it can only support two electrons. Moving the extra electron to the oxygen to join a lone pair does the trick.

    Screen Shot 2022-09-06 at 10.57.20 PM.png

    Formal charge

    Above, we discussed the steps for constructing Lewis dot diagrams: by following these rules, we can determine stable electronic configurations of molecules. We can also quantify this stability by calculating the formal charge.

    \(\text { Formal Charge }=\# \text { valence } e^{-} \mathrm{s}-\left(N+\dfrac{b}{2}\right)\)

    where the number of valence electrons refers to the neutral atom in isolation, \(N=\) the number of nonbonding valence electrons and \(b=\) the number of valence electrons participating in bonds. Formal charge should be calculated for each atom in the molecule.

    Example: Determine the formal charge of \(\mathrm{CO}_2\).

    Answer

    Oxygen: the neutral oxygen atom in isolation has 6 valence electrons. Each oxygen in \(\mathrm{CO}_2\) has 4 nonbonding electrons and 4 electrons stored in bonds.

    \[\text { Formal Charge (Oxygen) }=6-\left(4+\dfrac{4}{2}\right)=0 \nonumber\]

    Carbon: the neutral carbon atom in isolation has 4 valence electrons. Each carbon in \(\mathrm{CO}_2\) has 8 electrons stored in bonds.

    \[\text { Formal Charge }(\text { Carbon })=4-\left(\dfrac{8}{2}\right)=0 \nonumber\]


    6.7: Periodic Trends, Lewis Dot Diagrams, and Formal Charge is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by LibreTexts.