16.14 The Arrhenius Equation (Video)
- Page ID
- 342539
This project was preformed to supply Libretext authors with videos on General Chemistry topics which can be used to enhance their projects. Also, these videos are meant to act as a learning resource for all General Chemistry students.
Video Topics
From collision theory we get: Rate = CPe-Ea/RT[A][BC]
These relations are summarized by The Arrhenius Equation k = Ae-Ea/RT
The Arrhenius Equation shows that k changes with Ea and T
To look at how k changes with temperature use the integrated form of the Arrhenius equation.
Ln(k2/k1) = (Ea/R)(1/T1 - 1/T2)
This video contains the solution to the followed problem:
If k = 2.15 x 10-8 1/M∙s at 650 K and the activation energy is 182 kJ/mol what would be k at 700 K?
Link to Video
The Arrhenius Equation: https://youtu.be/qu3x0z8sqjw
Attribution
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Prof. Steven Farmer (Sonoma State University)