Molarity 1 (Worksheet)
- Page ID
- 3132
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Work in groups on these problems. You should try to answer the questions without referring to your textbook. If you get stuck, try asking another group for help.
- Calculate molarity if 25.0 mL of 1.75 M HCl diluted to 65.0 mL.
- Calculate molarity by dissolving 25.0g NaOH in 325 mL of solution.
- Calculate grams of solute needed to prepare 225 mL of 0.400 M KBr solution.
- Calculate mL of 0.650M KNO_{3} needed to contain 25.0g KNO_{3}.
- Which are water soluble? Zn(NO_{3})_{2} AlCl_{3} AgBr FePO_{4} CuAc_{2 }
- Calculate grams Ca(OH)_{2} needed to completely neutralize 50.0 mL of 3.00 M HBr.
- Calculate molarity of 35.0 mL KOH solution needed to completely neutralize 22.5 mL of 1.75 M H_{2}SO_{4}.
- Calculate volume (mL) of 2.50M H_{2}SO_{4} needed to completely neutralize 10.0g NaOH_{(s)}.
Answers
- M_{1}V_{1} = M_{2}V_{2} (1.71 M)(25.0 mL) = M_{2}(65.0 mL) M_{2} = 0.658 M
- M = mol/L = (25.0/40.0) / (0.325) = 1.92 mol/L
- g = (M)(L)(FW) = (0.400)((0.225)(119) = 10.7 g
- (25.0g)(1 mol/101 g)(1000mL/0.650 mol) = 381 mL
- Zn(NO_{3})_{2} AlCl_{3} CuAc_{2}
- 2 mol Ca(OH)_{2} = mol HBr 2 (g/74) = (3.00)(0.0500) 5.55 g Ca(OH)_{2}
- mol KOH = 2 mol H_{2}SO_{4} ( M)(mL) = 2( M)(mL) (M)(35.0mL) = 2(1.75 M)(22.5 mL) 2.25M KOH
- 2 mol H_{2}SO_{4} = mol NaOH 2 ( M)(L) = g/FW 2 (2.50)(L) = 10.0/40.0 L = 0.0500 50.0 mL