# Chapter 6 Solutions

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E6.1:

E6.2:

E6.3

## End-of-chapter problems

P6.1:

Left side: the nucleophile is an amine, the electrophile is the methyl carbon, and the leaving group is a sulfide.

Right side: The nucleophile is a thiolate ion, the electrophile is the carbon atom of an alkyl diphosphate, and diphosphate is the leaving group.

P6.2:

a)

b) In step 1, the nucleophile is the hydroxide oxygen, and the electrophile is the carbonyl carbon of the thioester.

P6.3:

a)

b)

c)

d)

e)

f) Bold dots show the two carbons that form a new bond in this reaction step.

P6.4:

The C to D step has the highest activation energy, and thus is the slowest, rate-determining step.

P6.5:

#### Contributors

• Organic Chemistry With a Biological Emphasis, Tim Soderberg (University of Minnesota, Morris)

This page titled Chapter 6 Solutions is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.

This page titled Chapter 6 Solutions is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by Tim Soderberg via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.