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Solution to Exercise 7-2-5

  • Page ID
    43266

    \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

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    The molecule contains three functional groups: an amine, and carboxylic acid and an amide.

    The amine would be protonated (an ammonium cation) at pH 7

    The carboxylic acid would be deprotonated (a carboxylate) at pH 7

    The amide is incorrectly drawn in the protonated state. Remember that amides are NOT basic, so this state is not reasonable. The amide group should be drawn as an uncharged group (with only one hydrogen)


    This page titled Solution to Exercise 7-2-5 is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by via source content that was edited to the style and standards of the LibreTexts platform.


    This page titled Solution to Exercise 7-2-5 is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by Tim Soderberg via source content that was edited to the style and standards of the LibreTexts platform.