8.E: Exercises
- Page ID
- 83105
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How many grams of oxygen gas are needed to fill a 25.0 L container at 0.966 atm and 22°C?
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The balanced chemical equation for the combustion of propane is as follows:
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(ℓ)
A) If 100.0 g of propane are combusted, how many moles of oxygen gas are necessary for the reaction to occur? B) At STP, how many liters of oxygen gas would that be? -
At 20°C, 1.000 g of liquid H2O has a volume of 1.002 mL. What volume will 1 g of water vapor occupy at 20°C if its pressure is 17.54 mmHg? By what factor has the water expanded in going from the liquid phase to the gas phase?
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Predict whether HCl or LiCl will have the higher melting point. Explain. (Hint: consider the relative strengths of the intermolecular interactions of the two compounds.)
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A standard automobile tire has a volume of about 3.2 ft3 (where 1 ft3 equals 28.32 L). Tires are typically inflated to an absolute pressure of 45.0 pounds per square inch (psi), where 1 atm equals 14.7 psi. Using this information with the ideal gas law, determine the number of moles of air needed to fill a tire if the air temperature is 18.0°C.
Answers
- 31.9 g
- A) 11.4 mol; B) 255 L
- 57.81 L; an expansion of 57,700 times
- LiCl; the attractions between full charges (ionic bonds) are stronger than those between the partial charges of HCl (London-dispersion and dipole-dipole forces)
- 12 mol