5: Chemical Reactions
- Page ID
- 281552
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\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)Introduction to Chemical Reactions
Exercise \(\PageIndex{1a}\)
From the statement “nitrogen and hydrogen react to produce ammonia,” identify the reactants and the products.
- Answer
-
reactants: nitrogen (N2) and hydrogen (H2)
product: ammonia (NH3)
Exercise \(\PageIndex{1b}\)
From the statement “sodium hydroxide and water are produced when sodium metal reacts with water” identify the reactants and the products.
- Answer
-
reactants: sodium (Na) and water (H2O)
products: sodium hydroxide (NaOH) and hydrogen (H2)
Exercise \(\PageIndex{1c}\)
What does it mean to say an equation is balanced? Why is it important for an equation to be balanced?
- Answer
-
An equation is balanced when the same number of each element is represented on the reactant and product sides. Equations must be balanced to accurately reflect the law of conservation of matter.
Types of Chemical Reactions
Exercise \(\PageIndex{2a}\)
Identify the type of reaction
- 2C2H6 + 7O2 → 4CO2 + 6H3O
- 2HCl + Na2S → 2NaCl + H2S
- 2SO2 + O2 → 2SO3
- Zn + Fe(NO3)2 → Zn(NO3)2 + Fe
- Answer a
-
combustion
- Answer b
-
double displacement
- Answer c
-
formation (synthesis)
- Answer d
-
Single displacement
Balancing Chemical Equations
Exercise \(\PageIndex{3a}\)
Balance the following equations
- PCl5(s)+H2O(l) → POCl3(l)+HCl(aq)
- Cu(s)+HNO3(aq) → Cu(NO3)2(aq)+H2O(l)+NO(g)
- H2(g)+I2(s) → HI(s)
- Fe(s)+O2(g) → Fe2O3(s)
- Answer a
-
PCl5(s)+H2O(l)→POCl3(l)+2HCl(aq)
- Answer b
-
3Cu(s)+8HNO3(aq)→3Cu(NO3)2(aq)+4H2O(l)+2NO(g)
- Answer c
-
H2(g)+I2(s)→2HI(s)
- Answer d
-
4Fe(s)+3O2(g)→2Fe2O3(s)
Exercise \(\PageIndex{3b}\)
Balance the following equations
- Na(s)+H2O(l) → NaOH(aq)+H2(g)
- (NH4)2Cr2O7(s) → Cr2O3(s)+N2(g)+H2O(g)
- P4(s)+Cl2(g) → PCl3(l)
- PtCl4(s) → Pt(s)+Cl2(g)
- Answer a
-
2Na(s)+2H2O(l) → 2NaOH(aq)+H2(g)
- Answer b
-
(NH4)2Cr52O7(s) → Cr2O3(s)+N2(g)+4H2O(g)
- Answer c
-
P4(s)+6Cl2(g) → 4PCl3(l)
- Answer d
-
PtCl4(s) → Pt(s)+2Cl2(g)
Exercise \(\PageIndex{3c}\)
Balance the following equations
- Ag(s)+H2S(g)+O2(g) → Ag2S(s)+H2O(l)
- P4(s)+O2(g)→P4O10(s)
- Pb(s)+H2O(l)+O2(g)→Pb(OH)2(s)
- Fe(s)+H2O(l)→Fe3O4(s)+H2(g)
- Answer a
-
4Ag(s)+2H2S(g)+O2(g) → 2Ag2S(s)+2H2O(l)
- Answer b
-
P4(s)+5O2(g)→P4O10(s)
- Answer c
-
2Pb(s)+2H2O(l)+O2(g)→2Pb(OH)2(s)
- Answer d
-
3Fe(s)+4H2O(l)→Fe3O4(s)+4H2(g)
Exercise \(\PageIndex{3c}\)
Balance the following equations
- Sc2O3(s)+SO3(l)→Sc2(SO4)3(s)
- Ca3(PO4)2(aq)+H3PO4(aq)→Ca(H2PO4)2(aq)
- Al(s)+H2SO4(aq)→Al2(SO4)3(s)+H2(g)
- TiCl4(s)+H2O(g)→TiO2(s)+HCl(g)
- Answer a
-
Sc2O3(s)+3SO3(l)→Sc2(SO4)3(s)
- Answer b
-
Ca3(PO4)2(aq)+4H3PO4(aq)→3Ca(H2PO4)2(aq)
- Answer c
-
2Al(s)+3H2SO4(aq)→Al2(SO4)3(s)+3H2(g)
- Answer d
-
TiCl4(s)+2H2O(g)→TiO2(s)+4HCl(g)
Aqueous Reactions
Solubility Rules
Exercise \(\PageIndex{4a}\)
Use the solubility rules to determine if the following compounds are soluble or insoluble. Indicate answer by writing formula followed by (aq) for soluble and (s) for insoluble.
- NaCl(?)
- Pb(OH)2(?)
- MgF2(?)
- K2SO4(?)
- Answer a
-
NaCl(aq)
- Answer b
-
Pb(OH)2(s)
- Answer c
-
MgF2(s)
- Answer d
-
K2SO4(aq)
Exercise \(\PageIndex{4b}\)
Use the solubility rules to determine if the following compounds are soluble or insoluble. Indicate answer by writing formula followed by (aq) for soluble and (s) for insoluble.
- AgCl(?)
- PbCl2(?)
- Ba(OH)2(?)
- Pb3(PO4)2(?)
- Answer a
-
AgCl(s)
- Answer b
-
PbCl2(s)
- Answer c
-
Ba(OH)2(aq)
- Answer d
-
Pb3(PO4)2(s)
Exercise \(\PageIndex{4c}\)
Identify the following as a strong electrolyte, a weak electrolyte, or a non-electrolyte, and why
- NaCl(aq)
- Na2SO4(aq)
- C6H12O6(aq) (sugar)
- AgCl(s)
- Answer a
-
strong electrolyte, soluble salt
- Answer b
-
strong electrolyte, soluble salt
- Answer c
-
nonelectrolyte, soluble molecule
- Answer d
-
nonelectrolyte, insoluble salt
Predicting Products and Balancing Eqs
Exercise \(\PageIndex{4d}\)
Predict products and balance the equation
- Al(NO3)3(aq) + Na2(CO3)(aq)
- Pb(ClO4)2(aq) + Na2SO4(aq)
- (NH4)3PO4(aq) + NaOH(aq)
- (NH4)3PO3(aq) + CaSO4(aq)
- Answer a
-
2 Al(NO3)3(aq) + 3 Na2(CO3)(aq) -> Al2(CO3)3(s) + 6 NaNO3(aq)
- Answer b
-
Pb(ClO4)2(aq) + Na2SO4(aq) -> PbSO4(s) + 2 NaClO4(aq)
- Answer c
-
(NH4)3PO4(aq) + 3 NaOH(aq) -> 3NH4OH(aq) + Na3PO4(aq)
- Answer d
-
2(NH4)3PO4(aq) + 3 CaSO4(aq) -> 3(NH4)2SO4(aq) + Ca3(PO4)2(S)
f
Exercise \(\PageIndex{4e}\)
Predict products and balance the equation
- (NH4)2SO4(aq) + CaCl2(aq)
- AgCH3CO2 (aq) + KCl(aq)
- Pb(NO3)2(aq) + Na2SO4(aq)
- NaOH + CaCl2(aq)
- Answer a
-
(NH4)2SO4(aq) + CaCl2(aq) -> CaSO4(s) + 2 NH4Cl(aq)
- Answer b
-
AgCH3CO2 (aq) + KCl(aq) -> AgCl(s) + KCH3CO2(aq)
- Answer c
-
Pb(NO3)2(aq) + Na2SO4(aq) -> PbSO4(s)+ 2 NaNO3(aq)
- Answer d
-
2 NaOH + CaCl2(aq) -> 2 NaCl(aq) + Ca(OH)2
Exercise \(\PageIndex{4f}\)
Predict products and balance the equation
- BaI2(aq) + H2SO4 (aq)
- Mg(s) + FeCl3(aq)
- AgNO3(aq) + Ca(s)
- Na(s) + HCl(aq)
- Na(s) + H2O(l)
- Answer a
-
BaI2 + H2SO4(aq) -> 2 HI(aq) + BaSO4(s)
- Answer b
-
3 Mg(s) + 2 FeCl3(aq) -> 2 Fe(s) + 3 MgCl2(aq)
- Answer c
-
2 AgNO3(aq) + Ca(s)-> 2 Ag(s) + Ca(NO3)2(aq)
- Answer d
-
2 Na(s) + 2 HCl(aq) -> H2(g) + 2 NaCl(aq)
- Answer e
-
2 Na(s) + 2 H2O(l) -> H2(g) + 2 NaOH(aq)
Net, Total and General Ionic Eqs
Exercise \(\PageIndex{4g}\)
Predict products, write general, total ionic and net ionic equations (this is problem 5.4d above)
- Al(NO3)3(aq) + Na2(CO3)(aq)
- Pb(ClO4)2(aq) + Na2SO4(aq)
- (NH4)3PO4(aq) + NaOH(aq)
- (NH4)3PO3(aq) + CaSO4(aq)
- Answer a
-
2 Al(NO3)3(aq) + 3 Na2(CO3)(aq) -> Al2(CO3)3(s) + 6 NaNO3(aq) (general)
2Al+3(aq) +6NO3-(aq) + 6Na+(aq)+3CO3-2(aq) -> Al2(CO3)3(s) + 6Na+(aq)+ 6NO3-(aq) (total ionic)
2Al+3(aq) +3CO3-2(aq) -> Al2(CO3)3(s) (net ionic)
- Answer b
-
Pb(ClO4)2(aq) + Na2SO4(aq) -> PbSO4(s) + 2 NaClO4(aq) (general)
Pb+2(aq) +2ClO4-(aq) + 2Na+(aq) + SO4-2(aq) -> PbSO4(s) + 2Na+(aq) + 2ClO4-(aq) (total ionic)
Pb+2(aq) + SO4-2(aq) -> PbSO4(s) (net ionic)
- Answer c
-
(NH4)3PO4(aq) + 3 NaOH(aq) -> 3NH4OH(aq) + Na3PO4(aq) (general)
3NH4+(aq)+ PO4-3(aq) + 3Na+(aq) + 3OH-(aq) -> 3NH4+(aq)+ PO4-3(aq) + 3Na+(aq) + 3OH-(aq) (total ionic)
no reaction (net ionic)
- Answer d
-
2(NH4)3PO4(aq) + 3 CaSO4(aq) -> 3(NH4)2SO4(aq) + Ca3(PO4)2(S) (general)
6NH4+(aq)+ PO4-3(aq) + 3Ca+2(aq) + SO4-2(aq) -> 6NH4+(aq)+ 3SO4-2(aq) + Ca3(PO4)2(S) (total ionic)
PO4-3(aq) + 3Ca+2(aq) -> Ca3(PO4)2(S) (total ionic)
Neutralization Reactions
Exercise \(\PageIndex{5a}\)
Answer the following
- What is the Arrhenius definition of an acid?
- What is the Arrhenius definition of an base?
- What is the Bronsted definition of an acid?
- What is the Bronsted definition of an base?
- Answer a
-
Substance which increases hydronium ion concentration in water
- Answer b
-
substance that increases hydroxide concentration in water
- Answer c
-
Proton donor
- Answer d
-
proton acceptor
Exercise \(\PageIndex{4g}\)
Predict products, write general, total ionic and net ionic equations
- HNO3(aq) + NaOH(aq)
- Ba(OH)2(aq) + H2SO4(aq)
- HC2H3O2(aq) + NaOH(aq)
- H3PO3(aq) + Ca(OH)2(aq)
- Answer a
-
HNO3(aq) + NaOH(aq) -> NaNO3(aq) + H2O(l) (general)
H+(aq) +NO3-(aq) + Na+(aq)+OH-(aq) -> H2O(l) +NO3-(aq) + Na+(aq) (total ionic)
H+(aq) +OH-(aq) -> H2O(l) (net ionic)
- Answer b
-
Ba(OH)2(aq) + H2SO4(aq) -> BaSO4(s) + 2H2O(l) (general)
Ba+2(aq) +2OH-(aq) + 2H+(aq) + SO4-2(aq) -> BaSO4(s) + 2H2O(l) (total ionic)
Ba+2(aq) +2OH-(aq) + 2H+(aq) + SO4-2(aq) -> BaSO4(s) + 2H2O(l) (net ionic)
- Answer c
-
HC2H3O2(aq) + NaOH(aq) -> NaC2H3O2(aq) + H2O(l) (general)
HC2H3O2(aq) + Na+(aq)+ OH-(aq) -> Na+(aq) + C2H3O2-(aq) + H2O(l) (total ionic)
HC2H3O2(aq) + OH-(aq) -> C2H3O2-(aq) + H2O(l) (net ionic)
- Answer d
-
H3PO4(aq) + 3NH4OH(aq) -> (NH4)3PO4(aq) + 3H2O(l) (general)
H3PO4(aq) + 3NH4+(aq) + 3OH-(aq) -> 3NH4+(aq) +PO4-3(aq) + 3H2O(l) (total ionic)
H3PO4(aq) + 3OH-(aq) -> PO4-3(aq) + 3H2O(l) (total ionic)