# Homework 13


2.25, 5.65

Question 2.25

A ship has a fuel tank that can hold 900 L of gasoline. The fuel has a density of .0432 g/cm3. How much weight is the ship carrying in fuel?

Strategy

First, you want to look at what the problem has given you. Look at the units and determine if you have been given the density, the mass, or the volume. Also, check to see if any of the units need to be converted to match the units of the density formula. Then you are going to plug the numbers you have into the formula and solve for what is being asked for.

Solving

The problem has given us the volume and the density of the gasoline, so now we must solve for the mass of the fuel. First, we must make sure that none of the numbers need to be converted to different units, but they do! The 900 L needs to be converted to cm3. First we must convert L to mL.$900 L = \frac{1000 ml}{1 L}$ which gives us 900000 mL. Now mL=cm3 so you do not need to convert for that. So now we have 900000 cm3 and we can plug all our numbers into the density formula. The density formula is$Density=\frac{mass}{volume}$ However, since we are looking for the mass we will switch the formula around and use it in this manner$Mass=Density*Volume$ So now we will plug our values into the second formula$Mass=\left ( .432 g/cm^{3} \right )*\left ( 900000 cm^{3} \right )$ After the cm3 cancel each other out, we are left with 3.8*104 grams of gasoline.

Question 5.65

Write the name for each molecular compound.

a. CO

b. H2S

c. SF6

d. N2O2

Strategy

First, you have to know how to name a molecular compound. To name a compound, its the prefix, name of first element, prefix and name of the second element with the suffix -ide. The prefixes are as follows:

mono=1

di=2

tri=3

tetra=4

penta=5

hexa=6

hepta=7

octa=8

nona=9

deca=10

After finding the elements and suffixes, just put it together and you have a molecular compound.

Solving

a. CO

-Since we only have one of each, the carbon does not have a suffix, so we would just use Carbon and there is only one oxygen so the suffix is mono. So the answer is Carbon Monoxide

b. H2S

-The hydrogen has a coefficient of 2, so the suffix would be di and the sulfur has no coefficients. Therefore, the answer would be dihydrogen monosulfide.

c. SF6

- The sulfur has no coefficients, so it does not change. The fluoride has a coefficient of 6. Therefore, the answer is Sulfur Hexaflouride

d. N2O3

-The nitrogen has a coefficient of 2, while the oxygen has a coefficient of 3. The compounds name is Dinitrogen trioxide.

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