17.4: Super Leaving Groups
- Page ID
- 375452
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Now, let’s go back to the reactivity series. We’ve said that with the appropriate nucleophile, anything to the left can be made from something on the right. This should make you uncomfortable – if acid chlorides are all the way to the right, how do we make them? The answer is that we take a carboxylic acid and then turn the –OH into a “super leaving group” that then reacts with chloride. There are primarily two ways of doing this:
A) Reaction with thionyl chloride (SOCl2)
B) Reaction with oxalyl chloride ((COCl)2)
So, if we update our reactivity series, we should have the following:
Coupling Reagents
Recall that the reaction between carboxylic acids and amines does not yield an amide because the amine simply protonates to become an ammonium salt which is non-nucleophilic and a carboxylate which is non-electrophilic. We coud convert the carboxylic acid into an acid chloride, but larger, more complicated substrates may not behave well under the harsh reaction conditions (SOCl2 or (COCl)2). So, in order to directly promote the formation of an amide from these two substrates, which are commercially available, we use an activating agent, or coupling agent. The activating agent essentially converts the carboxylic acid into an intermediate that has “super leaving group”-like reactivity. For example, consider the reaction sequence below with the coupling agent, dicyclohexylcarbodiimide:
Coupling agents are also useful in the synthesis of esters, especially those that are large macrocyclic lactones. Consider the following esterification with the coupling agent EDCI: