Synthesis of Amides
There are five synthetic routes to produce amides: nitrile conversion and the acyl nucleophilic substitution reactions of acid halides, acid anhydrides, and carboxylic acids.
Nitriles can be converted to amides. This reaction can be acid or base catalyzed
Carboxylic acid can be converted to amides by using DCC as an activating agent
Direct conversion of a carboxylic acid to an amide by reaction with an amine.
Acid chlorides react with ammonia, 1o amines and 2o amines to form amides
Acid Anhydrides react with ammonia, 1o amines and 2o amines to form amides
Hydrolysis of Amides
Hydrolysis under acidic conditions
Taking acetamide (ethanamide) as a typical amide. If acetamide is heated with a dilute acid (such as dilute hydrochloric acid), acetic acid is formed together with ammonium ions. So, if you were using hydrochloric acid, the final solution would contain ammonium chloride and acetic acid.
Hydrolysis under alkaline conditions
Also, if acetamide is heated with sodium hydroxide solution, ammonia gas is given off and you are left with a solution containing sodium acetate.
Peptide hydrolysis of proteins is amide hydrolysis. What biologists and biochemists call a peptide link (in proteins, for example) is what chemists call an amide link. Apply either hydrolysis reaction above to the dipeptide below to produce two amino acids. The amines in the products are shown in their protonated form because this hydrolysis reaction was performed under acidic conditions.
Reduction of Amides into Amines
Amides can be converted to 1°, 2° or 3° amines using LiAlH4 followed by an aqueous work-up. Alkyl groups attached to the amide nitrogen do not affect the reaction. The amine classification correlates with the amide as shown in the reaction summary below.
The reductions of propanamide and N,N-dimethylpropanamide are shown as examples.
Example: Amide Reductions
The mechanism begins with nucleophilic hydride reacting with the carbonyl carbon to produce the tetrahedral intermediate. An imine forms in concert with the loss on the leaving group. A second hydride nucleophile reacts with the imine carbon to produce the final product.
1) Nucleophilic reaction by the hydride
2) Imine formation with loss of leaving group
3) Nucleophilic reaction by the hydride
11. How would you prepare the following compounds from N-Propypl benzamide?
Propose a synthesis for the following.
a) NaOH, H2O
b) NaOH, H2O, then LiAlH4