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9.7.2: Practice Solution Concentration

  • Page ID
    236056
  • Exercise \(\PageIndex{1}\)

    How many grams of glucose (molar mass = 180.18 g/mol) are dissolved in 175 mL of a 2.00 M solution?

    Answer

    63.1 g. (0.350 moles)

    Exercise \(\PageIndex{1}\)

    How many mL of 5.25 M HCl solution would be needed to react with 6.00 g of Zn in the reaction below?

    Zn (s) + 2 HCl (aq) --> ZnCl2 (aq) + H2 (g)

    Answer

    35.0 mL (0.0350 L, 0.184 moles)

    Titration Problems

    Exercise \(\PageIndex{1}\)

    You perform the titration below on 12.00 mL of H2SO4 solution. You find that it takes 26.44 mL of 0.4483 M NaOH to react completely. What is the concentration of the H2SO4 solution?

    H2SO4 (aq) + 2 NaOH (aq) \(\rightarrow\) Na2SO4 (aq) + 2 H2O (l)

    Answer

    0.4939 M H2SO4

    You perform the titration below on 20.00 mL of HCl solution. You find that it takes 18.72 mL of 0.3786 M NaOH to react completely. What is the concentration of the HCl solution?

    HCl (aq) +  NaOH (aq) \(\rightarrow\) NaCl (aq) +  H2O (l)

    Answer

    0.3544 M HCl

    You perform the titration below on 15.00 mL of HCl solution. You find that it takes 26.44 mL of 0.1352 M Ba(OH)2 to react completely. What is the concentration of the HCl solution?

    2 HCl (aq) +  Ba(OH)2 (aq) \(\rightarrow\) BaCl2 (aq) + 2 H2O (l)

    Answer

    0.4766 M HCl

    Solution Stoichiometry

    Exercise \(\PageIndex{1}\)

    In the reaction below, what volume of 0.7644 M Pb(NO3)2 solution is needed in order to make 37.06 g PbCl2? (Molar mass of PbCl2 is 278.1 g/mol. NaCl is in excess.)

    Pb(NO3)2 (aq) + 2 NaCl (aq) \(\rightarrow\) 2 NaNO3 (aq) + PbCl2 (s)

    Answer

    174.3 mL (0.1743 L)

    In the reaction below, what volume of 0.3805 M Pb(NO3)2 solution is needed to react with 455.0 mL of 0.6322 M NaCl solution?

    Pb(NO3)2 (aq) + 2 NaCl (aq) \(\rightarrow\) 2 NaNO3 (aq) + PbCl2 (s)

    Answer

    378.0 mL (0.3780 L)

     

     

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