Skip to main content
Chemistry LibreTexts

Exercise 5.2 solution

  • Page ID
    192008
  • 23dimethylbutanezagreb.png

    Zagreb M1

    Zagreb M2

    M1 = 12 + 32 + 32 + 12 + 12 + 12

    M1 = 1 + 9 + 9 + 1 + 1 + 1

    M1 = 22

    M2 = 1*3+1*3+3*3+3*1+3*1

    M2 = 3+3+9+3+3

    M2 = 21

    • Was this article helpful?