# 20.1: Oxidation-Reduction Reactions

Electron transfer is one of the most basic processes that can happen in chemistry. It simply involves the movement of an electron from one atom to another. Many important biological processes rely on electron transfer, as do key industrial transformations used to make valuable products. In biology, for example, electron transfer plays a central role in respiration and the harvesting of energy from glucose, as well as the storage of energy during photosynthesis. In society, electron transfer has been used to obtain metals from ores since the dawn of civilization.

Oxidation state is a useful tool for keeping track of electron transfers. It is most commonly used in dealing with metals and especially with transition metals. Unlike metals from the first two columns of the periodic table, such as sodium or magnesium, transition metals can often transfer different numbers of electrons, leading to different metal ions (e.g., sodium is generally found as Na+ and magnesium is almost always Mg2+, but manganese could be Mn2+, Mn3+, and so on, as far as Mn7+). Oxidation state is a number assigned to an element in a compound according to some rules. This number enable us to describe oxidation-reduction reactions, and balancing redox chemical reactions. When a covalent bond forms between two atoms with different electronegativities the shared electrons in the bond lie closer to the more electronegative atom:

The oxidation number of an atom is the charge that results when the electrons in a covalent bond are assigned to the more electronegative atom and is the charge an atom would possess if the bonding were ionic. In HCl (above) the oxidation number for the hydrogen would be +1 and that of the Cl would be -1.

Example $$\PageIndex{1}$$

Determine which element is oxidized and which element is reduced in the following reactions (be sure to include the Oxidation State of each):

1. $$\ce{Zn + 2H^+ → Zn^{2+} + H2}$$
2. $$\ce{2Al + 3Cu^{2+}→2Al^{3+} +3Cu}$$
3. $$\ce{CO3^{2-} + 2H^+→ CO2 + H2O}$$

SOLUTIONS

1. Zn is oxidized (Oxidation number: 0 → +2); H+ is reduced (Oxidation number: +1 → 0)
2. Al is oxidized (Oxidation number: 0 → +3); Cu2+ is reduced (+2 → 0)
3. This is not a redox reaction because each element has the same oxidation number in both reactants and products: O= -2, H= +1, C= +4.

An atom is oxidized if its oxidation number increases, and an atom is reduced if its oxidation number decreases. The atom that is oxidized is the reducing agent, and the atom that is reduced is the oxidizing agent. (Note: the oxidizing and reducing agents can be the same element or compound).

## Oxidation Numbers and Nomenclature

Compounds of the alkali (oxidation number +1) and alkaline earth metals (oxidation number +2) are typically ionic in nature. Compounds of metals with higher oxidation numbers (e.g., tin +4) tend to form molecular compounds

• In ionic and covalent molecular compounds usually the less electronegative element is given first.
• In ionic compounds the names are given which refer to the oxidation (ionic) state
• In molecular compounds the names are given which refer to the number of molecules present in the compound
Figure $$\PageIndex{1}$$: Example of nomenclature based on oxidation states.
Ionic Molecular
MgH2 magnesium hydride H2S dihydrogen sulfide
FeF2 iron(II) fluoride OF2 oxygen difluoride
Mn2O3 manganese(III) oxide Cl2O3 dichlorine trioxide

An oxidation-reduction (redox) reaction is a type of chemical reaction that involves a transfer of electrons between two species. An oxidation-reduction reaction is any chemical reaction in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron. Redox reactions are common and vital to some of the basic functions of life, including photosynthesis, respiration, combustion, and corrosion or rusting.

## Oxidation-Reduction Reaction Examples

Redox reactions are comprised of two parts, a reduced half and an oxidized half, that always occur together. The reduced half gains electrons and the oxidation number decreases, while the oxidized half loses electrons and the oxidation number increases. Simple ways to remember this include the mnemonic devices OIL RIG, meaning "oxidation is loss" and "reduction is gain," and LEO says GER, meaning "loss of e- = oxidation" and "gain of e- = reduced." There is no net change in the number of electrons in a redox reaction. Those given off in the oxidation half reaction are taken up by another species in the reduction half reaction.

The two species that exchange electrons in a redox reaction are given special names. The ion or molecule that accepts electrons is called the oxidizing agent; by accepting electrons it causes the oxidation of another species. Conversely, the species that donates electrons is called the reducing agent; when the reaction occurs, it reduces the other species. In other words, what is oxidized is the reducing agent and what is reduced is the oxidizing agent. (Note: the oxidizing and reducing agents can be the same element or compound, as in disproportionation reactions).

A good example of a redox reaction is the thermite reaction, in which iron atoms in ferric oxide lose (or give up) O atoms to Al atoms, producing $$Al_2O_3$$ (Figure 20.1.1).

$Fe_2O_{3(s)} + 2Al_{(s)} \rightarrow Al_2O_{3(s)} + 2Fe_{(l)}$

Another example of the redox reaction is the reaction between zinc and copper sulfate.

Example $$\PageIndex{2}$$: Identifying Oxidized Elements

Using the equations from the previous examples, determine what is oxidized in the following reaction.

$\ce{Zn + 2H^+ \rightarrow Zn^{2+} + H_2} \nonumber$

SOLUTION

The Oxidation State of H changes from +1 to 0, and the Oxidation State of Zn changes from 0 to +2. Hence, Zn is oxidized and acts as the reducing agent.

Example $$\PageIndex{3}$$: Identifying Reduced Elements

What is reduced species in this reaction?

$\ce{Zn +​ 2H^+ \rightarrow Zn^{2+} + H_2} \nonumber$

SOLUTION

The Oxidation State of H changes from +1 to 0, and the Oxidation State of Zn changes from 0 to +2. Hence, H+ ion is reduced and acts as the oxidizing agent.

### Combination Reactions

Combination reactions are among the simplest redox reactions and, as the name suggests, involves "combining" elements to form a chemical compound. As usual, oxidation and reduction occur together. The general equation for a combination reaction is given below:

$A + B \rightarrow AB$

Example $$\PageIndex{4}$$: Combination Reaction

Equation: H2 + O2 → H2O

Calculation: 0 + 0 → (2)(+1) + (-2) = 0

Explanation:

In this equation both H2 and O2 are free elements; following Rule #1, their Oxidation States are 0. The product is H2O, which has a total Oxidation State of 0. According to Rule #6, the Oxidation State of oxygen is usually -2. Therefore, the Oxidation State of H in H2O must be +1.

### Decomposition Reactions

A decomposition reaction is the reverse of a combination reaction, the breakdown of a chemical compound into individual elements:

$AB \rightarrow A + B$

Example $$\PageIndex{5}$$: Decomposition Reaction

Identify the oxidation state of the products and reactant in the decomposition of water:

$\ce{H_2O \rightarrow H_2 + O_2}\nonumber$

Calculation

$(2)(+1) + (-2) = 0 → 0 + 0 \nonumber$

In this reaction, water is "decomposed" into hydrogen and oxygen. As in the previous example the H2O has a total Oxidation State of 0; thus, according to Rule #6 the Oxidation State of oxygen is usually -2, so the Oxidation State of hydrogen in H2O must be +1.

### Single Replacement Reactions

A single replacement reaction involves the "replacing" of an element in the reactants with another element in the products:

$A + BC \rightarrow AB + C$

Example $$\PageIndex{6}$$: Single Replacement Reaction

Equation:

$Cl_2 + Na\underline{Br} \rightarrow Na\underline{Cl} + Br_2$

Calculation: (0) + ((+1) + (-1) = 0) -> ((+1) + (-1) = 0) + 0
Explanation: In this equation, Br is replaced with Cl, and the Cl atoms in Cl2 are reduced, while the Br ion in NaBr is oxidized.

### Double Replacement Reactions

A double replacement reaction is similar to a double replacement reaction, but involves "replacing" two elements in the reactants, with two in the products:

$AB + CD \rightarrow AD + CB$

Example $$\PageIndex{7}$$: Double Replacement Reaction

The reaction of gasous hydrogen chloride and iron oxide is a double replacement reaction. Write the expected reaction for this chemistry equation.

Solution

$\ce{Fe2O3 + 6HCl → 2FeCl3 + 3H2O} \nonumber$

In this equation, Fe and H trade places, and oxygen and chlorine trade places.

### Combustion Reactions

Combustion reactions almost always involve oxygen in the form of O2, and are almost always exothermic, meaning they produce heat. Chemical reactions that give off light and heat and light are colloquially referred to as "burning."

$C_xH_y + O_2 \rightarrow CO_2 + H_2O$

Although combustion reactions typically involve redox reactions with a chemical being oxidized by oxygen, many chemicals "burn" in other environments. For example, both titanium and magnesium burn in nitrogen as well:

$2Ti_{(s)} + N_{2(g)} \rightarrow 2TiN_{(s)}$

$3 Mg_{(s)} + N_{2(g)} \rightarrow Mg_3N_{2(s)}$

Moreover, chemicals can be oxidized by other chemicals than oxygen, such as Cl2 or F2; these processes are also considered combustion reactions

### Disproportionation Reactions

Disproportionation Reactions: In some redox reactions a single substance can be both oxidized and reduced. These are known as disproportionation reactions, with the following general equation:

$2A \rightarrow A^{+n} + A^{-n}$

Where n is the number of electrons transferred. Disproportionation reactions do not need begin with neutral molecules, and can involve more than two species with differing oxidation states (but rarely).

Example $$\PageIndex{8}$$: Disproportionation Reaction

Disproportionation reactions have some practical significance in everyday life, including the reaction of hydrogen peroxide, H2O2 poured over a cut. This a decomposition reaction of hydrogen peroxide, which produces oxygen and water. Oxygen is present in all parts of the chemical equation and as a result it is both oxidized and reduced. The reaction is as follows:

$\ce{2H2O2(aq) \rightarrow 2H2O(l) + O2(g)} \nonumber$

Explanation

On the reactant side, H has an Oxidation State of +1 and O has an Oxidation State of -1, which changes to -2 for the product H2O (oxygen is reduced), and 0 in the product O2 (oxygen is oxidized).

## Summary

Oxidation signifies a loss of electrons and reduction signifies a gain of electrons. Balancing redox reactions is an important step that changes in neutral, basic, and acidic solutions. Tthe types of redox reactions: Combination and decomposition, Displacement reactions (single and double), Combustion, Disproportionation. The oxidizing agent undergoes reduction and the reducing agent undergoes oxidation.

## References

1. Petrucci, et al. General Chemistry: Principles & Modern Applications. 9th ed. Upper Saddle River, New Jersey: Pearson/Prentice Hall, 2007.
2. Sadava, et al. Life: The Science of Biology. 8th ed. New York, NY. W.H. Freeman and Company, 2007

## Contributors

• Christopher Spohrer (UCD), Christina Breitenbuecher (UCD), Luvleen Brar (UCD)