4.7: End of Chapter Problems
- Page ID
- 372588
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\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)- Explain what changes and what stays the same when 1.00 L of a solution of NaCl is diluted to 1.80 L.
- What information do we need to calculate the molarity of a sulfuric acid solution?
- What does it mean when we say that a 200-mL sample and a 400-mL sample of a solution of salt have the same molarity? In what ways are the two samples identical? In what ways are these two samples different?
- Determine the molarity for each of the following solutions:
- 0.444 mol of CoCl2 in 0.654 L of solution
- 98.0 g of phosphoric acid, H3PO4, in 1.00 L of solution
- 0.2074 g of calcium hydroxide, Ca(OH)2, in 40.00 mL of solution
- 10.5 kg of Na2SO4·10H2O in 18.60 L of solution
- 7.0 × 10−3 mol of I2 in 100.0 mL of solution
- 1.8 × 104 mg of HCl in 0.075 L of solution
- Answer
- a. 0.679 M; b. 1.00 M; c. 0.06998 M; d. 1.75 M; e. 0.070 M; f. 6.6 M
- Determine the molarity of each of the following solutions:
- 1.457 mol KCl in 1.500 L of solution
- 0.515 g of H2SO4 in 1.00 L of solution
- 20.54 g of Al(NO3)3 in 1575 mL of solution
- 2.76 kg of CuSO4·5H2O in 1.45 L of solution
- 0.005653 mol of Br2 in 10.00 mL of solution
- 0.000889 g of glycine, C2H5NO2, in 1.05 mL of solution
- Answer
- a. a. 0.9713 M; b. 5.25x10-3 M; c. 6.122x10-2 M; d. 7.62 M; e. 0.5653 M; f. 1.13x10-2 M
- Consider this question: What is the mass of the solute in 0.500 L of 0.30 M glucose, C6H12O6, used for intravenous injection?
- Outline the steps necessary to answer the question.
- Answer the question.
- Answer
- a. determine the number of moles of glucose in 0.500 L of solution; determine the molar mass of glucose; determine the mass of glucose from the number of moles and its molar mass; b. 27 g
- Consider this question: What is the mass of solute in 200.0 L of a 1.556-M solution of KBr?
- Outline the steps necessary to answer the question.
- Answer the question.
- Answer
- a. Calculate to moles of KBr by multiplying the Molarity by the amount of solution (200.0 L); then, Find the Molar Mass of KBr and convert moles of solute to grams; b. 37.03 kg
- Calculate the number of moles and the mass of the solute in each of the following solutions:
- 2.00 L of 18.5 M H2SO4, concentrated sulfuric acid
- 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum
- 5.50 L of 13.3 M H2CO, the formaldehyde used to “fix” tissue samples
- 325 mL of 1.8 × 10−6 M FeSO4, the minimum concentration of iron sulfate detectable by taste in drinking water
- Answer
- a. 37.0 mol H2SO4; 3.63 × 103 g H2SO4; (b) 3.8 × 10−6 mol NaCN; 1.9 × 10−4 g NaCN; (c) 73.2 mol H2CO; 2.20 kg H2CO; (d) 5.9 × 10−7 mol FeSO4; 8.9 × 10−5 g FeSO4
- Calculate the number of moles and the mass of the solute in each of the following solutions:
- 325 mL of 8.23 × 10−5 M KI, a source of iodine in the diet
- 75.0 mL of 2.2 × 10−5 M H2SO4, a sample of acid rain
- 0.2500 L of 0.1135 M K2CrO4, an analytical reagent used in iron assays
- 10.5 L of 3.716 M (NH4)2SO4, a liquid fertilizer
- Answer
- a. 2.67x10-5 moles KI; 4.44x10-3g KI; b. 1.7x10-6 moles H2SO4 ; 1.6x10-4 g H2SO4; c. 2.838x10-2 moles K2CrO4 ; 5.510g K2CrO4; d. 39.0 moles (NH4)2SO4 ; 5,160 g (NH4)2SO4
- Consider this question: What is the molarity of KMnO4 in a solution of 0.0908 g of KMnO4 in 0.500 L of solution?
- Outline the steps necessary to answer the question.
- Answer the question.
- Answer
- a. Determine the molar mass of KMnO4; determine the number of moles of KMnO4 in the solution; from the number of moles and the volume of solution, determine the molarity; b. 1.15 × 10−3 M
- Consider this question: What is the molarity of HCl if 35.23 mL of a solution of HCl contain 0.3366 g of HCl?
- Outline the steps necessary to answer the question.
- Answer the question.
- Answer
- a. Convert g of HCl to moles of HCl and convert mL of solution to L of solution, Divide moles of HCl by L of solution; b. 0.2621 M ;
- Calculate the molarity of each of the following solutions:
- 0.195 g of cholesterol, C27H46O, in 0.100 L of serum, the average concentration of cholesterol in human serum
- 4.25 g of NH3 in 0.500 L of solution, the concentration of NH3 in household ammonia
- 1.49 kg of isopropyl alcohol, C3H7OH, in 2.50 L of solution, the concentration of isopropyl alcohol in rubbing alcohol
- 0.029 g of I2 in 0.100 L of solution, the solubility of I2 in water at 20 °C
- Answer
- a. 5.04 × 10−3 M; b. 0.499 M; c. 9.92 M; d. 1.1 × 10−3 M
- Calculate the molarity of each of the following solutions:
- 293 g HCl in 666 mL of solution, a concentrated HCl solution
- 2.026 g FeCl3 in 0.1250 L of a solution used as an unknown in general chemistry laboratories
- 0.001 mg Cd2+ in 0.100 L, the maximum permissible concentration of cadmium in drinking water
- 0.0079 g C7H5SNO3 in one ounce (29.6 mL), the concentration of saccharin in a diet soft drink.
- There is about 1.0 g of calcium, as Ca2+, in 1.0 L of milk. What is the molarity of Ca2+ in milk? Answer: 0.025 M
- What volume of a 1.00-M Fe(NO3)3 solution can be diluted to prepare 1.00 L of a solution with a concentration of 0.250 M?
- If 0.1718 L of a 0.3556-M C3H7OH solution is diluted to a concentration of 0.1222 M, what is the volume of the resulting solution? Answer: 0.5000 L
- If 4.12 L of a 0.850 M-H3PO4 solution is be diluted to a volume of 10.00 L, what is the concentration the resulting solution?
- What volume of a 0.33-M C12H22O11 solution can be diluted to prepare 25 mL of a solution with a concentration of 0.025 M? Answer: 1.9 mL
- What is the concentration of the NaCl solution that results when 0.150 L of a 0.556-M solution is allowed to evaporate until the volume is reduced to 0.105 L?
- What is the molarity of the diluted solution when each of the following solutions is diluted to the given final volume?
- 1.00 L of a 0.250-M solution of Fe(NO3)3 is diluted to a final volume of 2.00 L
- 0.5000 L of a 0.1222-M solution of C3H7OH is diluted to a final volume of 1.250 L
- 2.35 L of a 0.350-M solution of H3PO4 is diluted to a final volume of 4.00 L
- 22.50 mL of a 0.025-M solution of C12H22O11 is diluted to 100.0 mL
- Answer
- a. 0.125 M; b. 0.04888 M; c. 0.206 M; d. 0.0056 M
- What is the final concentration of the solution produced when 225.5 mL of a 0.09988-M solution of Na2CO3 is allowed to evaporate until the solution volume is reduced to 45.00 mL?
- A 2.00-L bottle of a solution of concentrated HCl was purchased for the general chemistry laboratory. The solution contained 868.8 g of HCl. What is the molarity of the solution? Answer: 11.9 M
- An experiment in a general chemistry laboratory calls for a 2.00-M solution of HCl. How many mL of 11.9 M HCl would be required to make 250 mL of 2.00 M HCl?
- What volume of a 0.20-M K2SO4 solution contains 57 g of K2SO4? Answer: 1.6 L
- The US Environmental Protection Agency (EPA) places limits on the quantities of toxic substances that may be discharged into the sewer system. Limits have been established for a variety of substances, including hexavalent chromium, which is limited to 0.50 mg/L. If an industry is discharging hexavalent chromium as potassium dichromate (K2Cr2O7), what is the maximum permissible molarity of that substance?