1.8.8: Enthalpies- Solutions- Simple Solutes- Interaction Parameters
The excess Gibbs energy \(\mathrm{G}^{\mathrm{E}}\) for a dilute aqueous solution containing a simple solute \(j\) prepared using \(1 \mathrm{~kg}\) of solvent, water is given by equation (a).
\[\mathrm{G}^{\mathrm{E}}=\mathrm{R} \, \mathrm{T} \, \mathrm{m}_{\mathrm{j}} \,\left[1-\phi+\ln \left(\gamma_{\mathrm{j}}\right)\right] \nonumber \]
In terms of Gibbs energies pairwise solute-solute interaction parameters,
\[\mathrm{G}^{\mathrm{E}}=\mathrm{g}_{\mathrm{jj}} \,\left[\mathrm{m}_{\mathrm{j}} / \mathrm{m}^{0}\right]^{2} \nonumber \]
The excess enthalpy[1]
\[\mathrm{H}^{\mathrm{E}}=\mathrm{h}_{\mathrm{ij}} \,\left[\mathrm{m}_{\mathrm{j}} / \mathrm{m}^{0}\right]^{2} \nonumber \]
where [cf. Gibbs –Helmholtz Equation],
\[\mathrm{h}_{\mathrm{ij}}=-\mathrm{T}^{2} \,\left\{\partial\left[\mathrm{g}_{\mathrm{jj}} / \mathrm{T}\right] / \partial \mathrm{T}\right\}_{\mathrm{p}} \nonumber \]
Here \(\mathrm{h}_{\mathrm{jj}}\) is the pairwise solute-solute enthalpic interaction parameter. For the solvent,
\[\mu_{1}(\mathrm{aq})=\mu_{1}^{*}(\lambda)-\mathrm{R} \, \mathrm{T} \, \mathrm{M}_{1} \, \mathrm{m}_{\mathrm{j}}-\mathrm{M}_{1} \, \mathrm{g}_{\mathrm{j}} \,\left(\mathrm{m}_{\mathrm{j}} / \mathrm{m}^{0}\right)^{2} \nonumber \]
Using the Gibbs-Helmholtz Equation,
\[\mathrm{H}_{1}(\mathrm{aq})=\mathrm{H}_{1}^{*}(\lambda)-\mathrm{M}_{1} \, \mathrm{h}_{\mathrm{ij}} \,\left(\mathrm{m}_{\mathrm{j}} / \mathrm{m}^{0}\right)^{2} \nonumber \]
For the solute,
\[\mu_{\mathrm{j}}(\mathrm{aq})=\mu_{\mathrm{j}}^{0}(\mathrm{aq})+\mathrm{R} \, \mathrm{T} \, \ln \left(\mathrm{m}_{\mathrm{j}} / \mathrm{m}^{0}\right)+2 \, \mathrm{g}_{\mathrm{ij}} \,\left(\mathrm{m}^{0}\right)^{-2} \, \mathrm{m}_{\mathrm{j}} \nonumber \]
Then using the Gibbs-Helmholtz Equation [2]
\[\mathrm{H}_{\mathrm{j}}(\mathrm{aq})=\mathrm{H}_{\mathrm{j}}^{\infty}(\mathrm{aq})+2 \, \mathrm{h}_{\mathrm{ij}} \,\left(\mathrm{m}^{0}\right)^{-2} \, \mathrm{m}_{\mathrm{j}} \nonumber \]
Alternatively we may express the enthalpy of the solution in terms of the apparent molar enthalpy of the solute, \(\phi\left(\mathrm{H}_{\mathrm{j}}\right)\).
\[\mathrm{H}\left(\mathrm{aq} ; \mathrm{w}_{1}=1 \mathrm{~kg}\right)=\left(1 / \mathrm{M}_{1}\right) \, \mathrm{H}_{1}^{*}(\lambda)+\mathrm{m}_{\mathrm{j}} \, \phi\left(\mathrm{H}_{\mathrm{j}}\right) \nonumber \]
For the ideal solution,
\[\mathrm{H}\left(\mathrm{aq} ; \mathrm{id} ; \mathrm{w}_{1}=1 \mathrm{~kg}\right)=\left(1 / \mathrm{M}_{1}\right) \, \mathrm{H}_{1}^{*}(\lambda)+\mathrm{m}_{\mathrm{j}} \, \phi\left(\mathrm{H}_{\mathrm{j}}\right)^{\infty} \nonumber \]
where \(\phi\left(\mathrm{H}_{\mathrm{j}}\right)^{\infty}=\mathrm{H}_{\mathrm{j}}^{\infty}(\mathrm{aq})\). Then
\[\mathrm{H}^{\mathrm{E}}=\mathrm{m}_{\mathrm{j}} \,\left[\phi\left(\mathrm{H}_{\mathrm{j}}\right)-\phi\left(\mathrm{H}_{\mathrm{j}}\right)^{\infty}\right] \nonumber \]
Hence using equation (c),
\[\phi\left(\mathrm{H}_{\mathrm{j}}\right)=\phi\left(\mathrm{H}_{\mathrm{j}}\right)^{\infty}+\mathrm{h}_{\mathrm{ji}} \,\left(\mathrm{m}^{0}\right)^{-2} \, \mathrm{m}_{\mathrm{j}} \nonumber \]
We use these equations in the analysis of a calorimetric data where a given solution is diluted. The solution is prepared using \(\mathrm{n}_{1}\) moles of solvent (water) and \(\mathrm{n}_{j}\) moles of a simple solute \(j\). Then
\[\mathrm{H}(\mathrm{I} ; \mathrm{aq})=\mathrm{n}_{1} \, \mathrm{H}_{1}^{*}(\lambda)+\mathrm{n}_{\mathrm{j}} \, \phi\left(\mathrm{H}_{\mathrm{j}} ; \mathrm{I} ; \mathrm{aq}\right) \nonumber \]
A new solution is prepared by adding (in the calorimeter) \(\Delta \mathrm{n}_{1}\) moles of solvent, Then
\[\mathrm{H}(\mathrm{II} ; \mathrm{aq})=\left(\mathrm{n}_{1}+\Delta \mathrm{n}_{1}\right) \, \mathrm{H}_{1}^{*}(\lambda)+\mathrm{n}_{\mathrm{j}} \, \phi\left(\mathrm{H}_{\mathrm{j}} ; \mathrm{II} ; \mathrm{aq}\right) \nonumber \]
Thus the molality of solute \(j\) changes from \(\mathrm{m}_{j}\)(I) \(\left[=\mathrm{n}_{\mathrm{j}} / \mathrm{n}_{1} \, \mathrm{M}_{1}\right]\) to \(\mathrm{m}_{j}\)(II) \(\left[=\mathrm{n}_{\mathrm{j}} /\left(\mathrm{n}_{1}+\Delta \mathrm{n}_{1}\right) \, \mathrm{M}_{1}\right]\). Therefore,
\[\phi\left(\mathrm{H}_{\mathrm{j}} ; \mathrm{I} ; \mathrm{aq}\right)=\phi\left(\mathrm{H}_{\mathrm{j}}\right)^{\infty}+\left[\mathrm{h}_{\mathrm{ij}} \,\left(\mathrm{m}^{0}\right)^{-2} \, \mathrm{n}_{\mathrm{j}} / \mathrm{n}_{1} \, \mathrm{M}_{1}\right] \nonumber \]
And
\[\phi\left(\mathrm{H}_{\mathrm{j}} ; \mathrm{II} ; \mathrm{aq}\right)=\phi\left(\mathrm{H}_{\mathrm{j}}\right)^{\infty}+\left[\mathrm{h}_{\mathrm{j}} \,\left(\mathrm{m}^{0}\right)^{-2} \, \mathrm{n}_{\mathrm{j}} /\left(\mathrm{n}_{1}+\Delta \mathrm{n}_{1}\right) \, \mathrm{M}_{1}\right] \nonumber \]
In fact we record the heat \(\mathrm{q}\) (at constant pressure) when \(\Delta \mathrm{n}_{1}\) moles of solvent are added to solution I to form solution II. Thus,
\[\mathrm{q}=\mathrm{H}(\mathrm{II} ; \mathrm{aq})-\mathrm{H}(\mathrm{I} ; \mathrm{aq})-\Delta \mathrm{n} \, \mathrm{H}_{1}^{*}(\lambda) \nonumber \]
Footnotes
[1] From equation (a) and (b) \(\mathrm{G}^{\mathrm{E}}=\left[\mathrm{J} \mathrm{kg}^{-1}\right]\) From equation (c) \(\mathrm{H}^{\mathrm{E}}=\left[\mathrm{J} \mathrm{kg}^{-1}\right]\)
[2] A check on the equations with reference to solution prepared using \(1 \mathrm{~kg}\) of solvent.
\[\begin{aligned}
\mathrm{H}\left(\mathrm{aq} ; \mathrm{w}_{1}=1 \mathrm{~kg}\right)=\left(1 / \mathrm{M}_{1}\right) \,\left[\mathrm{H}_{1}^{*}(\lambda)-\mathrm{M}_{1} \, \mathrm{h}_{\mathrm{ji}} \,\left(\mathrm{m}_{\mathrm{j}} / \mathrm{m}^{0}\right)^{2}\right] \\
&+\mathrm{m}_{\mathrm{j}} \,\left[\mathrm{H}_{\mathrm{j}}^{\infty}(\mathrm{aq})+2 \, \mathrm{h}_{\mathrm{jj}} \,\left(\mathrm{m}^{0}\right)^{-2} \, \mathrm{m}_{\mathrm{j}}\right]
\end{aligned} \nonumber \]
Or,
\[\begin{aligned}
\mathrm{H}\left(\mathrm{aq} ; \mathrm{w}_{1}=1 \mathrm{~kg}\right)=\left(1 / \mathrm{M}_{1}\right) \, \mathrm{H}_{1}^{*} &(\lambda)-\mathrm{h}_{\mathrm{jj}} \,\left(\mathrm{m}_{\mathrm{j}} / \mathrm{m}^{0}\right)^{2} \\
&+\mathrm{m}_{\mathrm{j}} \, \mathrm{H}_{\mathrm{j}}^{\infty}(\mathrm{aq})+2 \, \mathrm{h}_{\mathrm{ij}} \,\left(\mathrm{m}_{\mathrm{j}} / \mathrm{m}^{0}\right)^{2}
\end{aligned} \nonumber \]
Then
\[\mathrm{H}\left(\mathrm{aq} ; \mathrm{w}_{1}=1 \mathrm{~kg}\right)=\left(1 / \mathrm{M}_{1}\right) \, \mathrm{H}_{1}^{*}(\lambda)+\mathrm{m}_{\mathrm{i}} \, \mathrm{H}_{\mathrm{i}}^{\infty}(\mathrm{aq})+\mathrm{H}^{\mathrm{E}} \nonumber \]