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23.8: The Claisen Condensation Reaction

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    Esters, like aldehydes and ketones, are weakly acidic. When an ester with an α hydrogen is treated with 1 equivalent of a base such as sodium ethoxide, a reversible carbonyl condensation reaction occurs to yield a β-keto ester. For instance, ethyl acetate yields ethyl acetoacetate on base treatment. This reaction between two ester molecules is known as the Claisen condensation reaction. (We’ll use ethyl esters, abbreviated “Et,” for consistency, but other esters will also work.)

    Two ethyl acetate molecules react with sodium ethoxide in ethanol followed by hydronium to produce ethyl acetoacetate, a beta-keto ester (seventy-five percent), and ethanol.

    The mechanism of the Claisen condensation is similar to that of the aldol condensation and involves the nucleophilic addition of an ester enolate ion to the carbonyl group of a second ester molecule (Figure 23.5). The only difference between the aldol condensation of an aldehyde or ketone and the Claisen condensation of an ester involves the fate of the initially formed tetrahedral intermediate. The tetrahedral intermediate in the aldol reaction is protonated to give an alcohol product—exactly the behavior previously seen for aldehydes and ketones (Section 19.4). The tetrahedral intermediate in the Claisen reaction, however, expels an alkoxide leaving group to yield an acyl substitution product—as previously seen for esters (Section 21.6).

    Figure 23.5 MECHANISM Mechanism of the Claisen condensation reaction.

    Reversible mechanism of Claisen condensation of ethyl acetate with arrows showing electron flow: alpha proton abstraction, nucleophilic addition of enolate, ethoxide expelled, deprotonation between carbonyls, reprotonation to form ethyl acetoacetate.

    If the starting ester has more than one acidic α hydrogen, the product β-keto ester has a highly acidic, doubly activated hydrogen atom that can be abstracted by base. This deprotonation of the product requires the use of a full equivalent of base rather than a catalytic amount. Furthermore, the deprotonation serves to drive the equilibrium completely to the product side so that high yields are usually obtained in Claisen condensations.

    Worked Example 23.3

    Predicting the Product of a Claisen Condensation Reaction

    What product would you obtain from Claisen condensation of ethyl propanoate?

    Strategy

    The Claisen condensation of an ester results in loss of one molecule of alcohol and formation of a product in which an acyl group of one reactant bonds to the α carbon of the second reactant. The product is a β-keto ester.

    Solution

    The Claisen condensation of two equivalents of ethyl propanoate with sodium ethoxide followed by hydronium yields ethyl-2-methyl-3-oxopentanoate (a beta-keto ester), and ethanol.
    (CH3)2CHCH2CO2Et
    (b) Ethyl phenylacetate (c) Ethyl cyclohexylacetate

    As shown in Figure 23.5, the Claisen reaction is reversible. That is, a β-keto ester can be cleaved by base into two fragments. Using curved arrows to indicate electron flow, show the mechanism by which this cleavage occurs.

     ethyl=

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