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16.6: Trisubstituted Benzenes- Additivity of Effects

  • Page ID
    448714
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    Electrophilic substitution of a disubstituted benzene ring is governed by the same resonance and inductive effects that influence monosubstituted rings. The only difference is that it’s necessary to consider the additive effects of two different groups. In practice, this isn’t as difficult as it sounds; three rules are usually sufficient.

    RULE 1
    If the directing effects of the two groups reinforce each other, the situation is straightforward. In p-nitrotoluene, for example, both the methyl and the nitro group direct further substitution to the same position (ortho to the methyl = meta to the nitro). A single product is thus formed on electrophilic substitution.

    Para-nitrotoluene reacts with molecular bromine in the presence of iron tribromide to form 2-bromo-4-nitrotoluene. The directing effects of the methyl and nitro groups are labeled.

    RULE 2
    If the directing effects of the two groups oppose each other, the more powerful activating group has the dominant influence, but mixtures of products are often formed. For example, bromination of p-methylphenol yields primarily 2-bromo-4-methylphenol because –OH is a more powerful activator than –CH3.

    Para-methylphenol reacts with molecular bromine in the presence of iron tribromide to yield 2-bromo-4-methylphenol. The directing effects of the methyl and nitro groups are labeled.

    RULE 3
    Further substitution rarely occurs between the two groups in a meta-disubstituted compound because this site is too hindered. Aromatic rings with three adjacent substituents must therefore be prepared by some other route, such as by substitution of an ortho-disubstituted compound.

    Meta-chlorotoluene reacts with chlorine and iron trichloride to yield 3,4-dichlorotoluene and 2,5-dichlorotoluene. C 2 of reactant is too hindered for reaction to occur. Ortho-nitrotoluene reacts with chlorine and iron trichloride forming 2-chloro-6-nitrotoluene and 4-chloro-2-nitrotoluene.

    Worked Example 16.3

    Predicting the Product of Substitution on a Disubstituted Benzene

    What product would you expect from bromination of p-methylbenzoic acid?

    Strategy

    Identify the two substituents present on the ring, decide the directing effect of each and, if necessary, decide which substituent is the stronger activator. In the present case, the carboxyl group (–CO2H) is a meta director and the methyl group is an ortho and para director. Both groups direct bromination to the position next to the methyl group, yielding 3-bromo-4-methylbenzoic acid.

    Solution

    Para-methylbenzoic acid reacts with molecular bromine in the presence of iron tribromide to yield 3-bromo-4-methylbenzoic acid.

    Problem 16-14 At what position would you expect electrophilic substitution to occur in each of the following substances: (a)

    In a benzene ring, C 1 and C 3 are bonded to a bromine atom and a methoxy group, respectively. (b)

    In a benzene ring, C 1 and C 2 are bonded to a bromine atom and an amino group, respectively. (c)

    In a benzene ring, C 1 and C 2 are bonded to a chlorine atom and a nitro group, respectively.

    Problem 16-15 Show the major product(s) from reaction of the following substances with (1) CH3CH2Cl, AlCl3 and (2) HNO3, H2SO4: (a)

    The ball-and-stick model has a benzene ring. C 1 is bonded to a large red sphere. C 2 is bonded to a methyl group. (b)

    The ball-and-stick model has a benzene ring. C 1 is bonded to a small red sphere, which is bonded to a methyl group. C 2 is bonded to methyl group.


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