Chapter 6 Solutions
- Page ID
- 1121
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In-chapter exercises
E6.1:
E6.2:
E6.3
End-of-chapter problems
P6.1:
Left side: the nucleophile is an amine, the electrophile is the methyl carbon, and the leaving group is a sulfide.
Right side: The nucleophile is a thiolate ion, the electrophile is the carbon atom of an alkyl diphosphate, and diphosphate is the leaving group.
P6.2:
a)
b) In step 1, the nucleophile is the hydroxide oxygen, and the electrophile is the carbonyl carbon of the thioester.
P6.3:
a)
b)
c)
d)
e)
f) Bold dots show the two carbons that form a new bond in this reaction step.
P6.4:
The C to D step has the highest activation energy, and thus is the slowest, rate-determining step.
P6.5:
Contributors
- Organic Chemistry With a Biological Emphasis, Tim Soderberg (University of Minnesota, Morris)