# 2.10: Solutions to Selected Problems

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Exercise 2.4.1:

a) non-competitive

b) competitive

c) competitive

d) non-competitive

Exercise 2.5.1:

a) $$V_{max} = 1.8 \times 10^{-5} \frac{mol}{Ls}$$

$\frac{V_{max}}{2} = 9 \times 10^{-6} \frac{mol}{Ls} \: so \: K_{m} = 6 \frac{mol}{L} \nonumber$

b) $$V_{max} = 6.5 \times 10^{-7} \frac{mol}{Ls}$$

$\frac{V_{max}}{2} = 3.25 \times 10^{-7} \frac{mol}{Ls} \: so \: K_{m} = 7 \frac{mol}{L} \nonumber$

c) $$V_{max} = 2.6 \times 10^{-5} \frac{mol}{Ls}$$

$\frac{V_{max}}{2} = 1.3 \times 10^{-5} \frac{mol}{Ls} \: so \: K_{m} = 6 \frac{mol}{L} \nonumber$

d) $$V_{max} = 1.2 \times 10^{-5} \frac{mol}{Ls}$$

$\frac{V_{max}}{2} = 6 \times 10^{-6} \frac{mol}{Ls} \: so \: K_{m} = 6 \frac{mol}{L} \nonumber$

e)

$V_{max} = 6.0 \times 10^{-7} \frac{mol}{Ls} \nonumber$

$\frac{V_{max}}{2} = 3 \times 10^{-7} \frac{mol}{Ls} \: so \: K_{m} = 13 \frac{mol}{L} \nonumber$

Exercise 2.5.2:

a) $$\frac{1}{V_{max}} = 30 \frac{Ls}{mol} \: so \: V_{max} = 3.3 \times 10^{-2} \frac {mol}{Ls}$$

$$\frac{-1}{K_{m}} = -40 \frac{L}{mmol} \: so \: K_{m} = 2.5 \times 10^{-2} \frac{M}{L}$$

b) ​​$$\frac{1}{V_{max}} = 50 \frac{Ls}{mol} \: so \: V_{max} = 2.0 \times 10^{-2} \frac {mol}{Ls}$$

$$\frac{-1}{K_{m}} = -70 \frac{L}{mmol} \: so \: K_{m} = 1.4 \times 10^{-2} \frac{M}{L}$$

c) $$\frac{1}{V_{max}} = 60 \frac{Ls}{mol} \: so \: V_{max} = 1.7 \times 10^{-2} \frac {mol}{Ls}$$

$$\frac{-1}{K_{m}} = -70 \frac{L}{mmol} \: so \: K_{m} = 1.4 \times 10^{-2} \frac{M}{L}$$

d) $$\frac{1}{V_{max}} = 50 \frac{Ls}{mol} \: so \: V_{max} = 2.0 \times 10^{-2} \frac {mol}{Ls}$$

$$\frac{-1}{K_{m}} = -100 \frac{L}{mmol} \: so \: K_{m} = 1.0 \times 10^{-2} \frac{M}{L}$$

e) $$\frac{1}{V_{max}} = 30 \frac{Ls}{mol} \: so \: V_{max} = 3.3 \times 10^{-2} \frac {mol}{Ls}$$

$$\frac{-1}{K_{m}} = -100 \frac{L}{mmol} \: so \: K_{m} = 1.0 \times 10^{-2} \frac{M}{L}$$

a) ​​​​​​​$$\frac{1}{V_{max}} = 30 \frac{Ls}{mol} \: so \: V_{max} = 3.3 \times 10^{-2} \frac {mol}{Ls}$$

$$\frac{-1}{K_{m}} = -60 \frac{L}{mmol} \: so \: K_{m} = 1.7 \times 10^{-2} \frac{M}{L}$$

Exercise 2.5.3:

1. uncompetitive
2. mixed
3. noncompetitive
4. competitive
5. uncompetitive
6. noncompetitive
7. competitive

This page titled 2.10: Solutions to Selected Problems is shared under a CC BY-NC 3.0 license and was authored, remixed, and/or curated by Chris Schaller via source content that was edited to the style and standards of the LibreTexts platform.