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Chemistry LibreTexts

Turnover Number

  • Page ID
    408
  • In enzyme kinetics, we are interested to know how many maximum molecules of substrate can be converted into product per catalytic site of a given concentration of enzyme per unit time.

    \[ k_{cat} =\dfrac{ V_{max}}{E_t} \]

    with

    • \(k_{cat}\) = Turnover number,
    • \(V_{max}\) = Maximum rate of reaction when all the enzyme catalytic sites are saturated with substrate and
    • \(E_t\) =Total enzyme concentration or concentration of total enzyme catalytic sites.

    The units of Turn over number (kcat) are \(k_{cat}\) = (moles of product/sec)/ (moles of enzyme) or sec-1.

    Contributors and Attributions

    • Kiranpreet Kaur