Turnover Number

In enzyme kinetics, we are interested to know how many maximum molecules of substrate can be converted into product per catalytic site of a given concentration of enzyme per unit time.

\[ k_{cat} =\dfrac{ V_{max}}{E_t} \]

with

• \(k_{cat}\) = Turnover number,
• \(V_{max}\) = Maximum rate of reaction when all the enzyme catalytic sites are saturated with substrate and
• \(E_t\) =Total enzyme concentration or concentration of total enzyme catalytic sites.

The units of Turn over number (kcat) are \(k_{cat}\) = (moles of product/sec)/ (moles of enzyme) or sec^-1.

Contributors and Attributions

• Kiranpreet Kaur