5.6: Solutions for Selected Problems
- Page ID
- 148703
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Template:HideTOCProblem NF1.1.
- 0
- 3-
- 3-
- 3+
- 5+
Problem NF1.2.
- O2
- NO2-
- 2 e-
Problem NF3.1.
- S: 4 x 2- = 8- ; Fe: 2 x 2+ + 2 x 3+ = 10+ ; total = 2+
- S: 4 x 2- = 8- ; Fe: 1 x 2+ + 2 x 3+ = 8+ ; total = 0
- S: 2 x 2- = 4- ; Fe: 2+ + 3+ = 5+ ; total = 1+
Problem NF3.2.
Problem NF3.3.
Problem NF3.4.
Problem NF4.1.
d) As the Fe becomes more reduced, the N-N stretching frequency decreases. That's because the more electron density there is on the Fe, the more it is able to backbond to the N2 (N2 is a π acceptor).