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10.12: Solutions to Selected Problems

  • Page ID
    149201
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    Name: ______________________________

    Section: _____________________________

    Student ID#:__________________________

    Problem OC1.1.

    PRbutrieneorbs.png

    Problem OC1.2.

    PRhextrieneorbs.png

    Problem OC2.2.

    PRCopedrillsoln.png

    Problem OC2.3.

    PRClaisendrillsoln.png

    Problem OC3.1.

    PRDAarrowsoln.png

    Problem OC3.2.

    PRdielsTS.png

    Problem OC3.3.

    PRDielsAlderinterSoln.png

    Problem OC3.4.

    PRDielsAlderintrasoln.png

    Problem OC3.5.

    Problem OC3.6.

    The retro-Diels Alder reaction is entropically favoured, because two molecules are made from one molecule. As a result, energy becomes partitioned into additional states because the degrees of freedom are increasing. Internal entropy increases during this reaction. Mathematically, the entropy term is negative in the expression for free energy, so as entropy increases the free energy becomes lower. Because that term is actually a product of entropy and temperature, an increase in temperature has the effect of amplifying the influence of entropy on the free energy of the reaction. Hence, this reaction is favoured by internal entropy factors, which come to dominate at elevated temperature.

    Problem OC3.7.

    PRDielsAlderReverseSoln.png

    Problem OC3.8.

    PRdielsNaphtholsoln.png

    Problem OC4.1.

    The maleic anhydride is polarized, with electron density drawn toward the anhydride functional group on one side of the ring. As a result, the other side of the ring is left more positive, and will attract the polarizable electron density from the diene.

    PRmaleicpolarsoln.png

    Problem OC4.2.

    Lewis acids frequently activate carbonyl compounds towards interaction with nucleophiles. They do so by binding to the lone pairs on the carbonyl oxygen, drawing electron density away from the oxygen and, inductively, away from the neighbouring portion of the molecule.

    PRmaleicLAsoln.png

    Problem OC4.3.

    PRenolenonesoln.png

    Problem OC4.4.

    PRMethoxyplusNitro.png

    Problem OC4.5.

    PRMethoxyplusNitro2.png

    Problem OC4.6.

    PRDApolarproductsoln.png

    Problem OC4.7.

    PRDanishefskyPrepSoln.png

    Problem OC4.8.

    PRdansihefskySoln.png

    Problem OC4.9.

    PRdanishefskyhydrsoln.png

    Problem OC4.10.

    PRheteroDAsoln.png

    Problem OC4.11.

    PRinversedemandsoln.png

    Problem OC4.12.

    PRDielsregiosoln.png

    Problem OC4.13.

    The drawings indicate the two electron-donating groups are operating at cross purposes. One directs electron density toward one end of the diene, whereas the other directs the electron desnity toward the other end.

    PRwrongMethoxyNu.png

    Problem OC5.1.

    PREndootherstereo.png

    Problem PR5.2.

    Problem OC8.3.

    1. OsO4, H2O
    2. mCPBA
    3. 1. O3; 2. Me2S or Zn
    4. 1. O3; 2. Me2S or Zn
    5. OsO4, H2O
    6. mCPBA

    Problem OC8.6.

    DedihydrosemofalinOverman03soln.png

    Problem OC9.1.

    -

    Problem OC9.2.

    PRdecarboxsynthsoln.png

    Problem OC9.3.

    PRdecarboxothersoln.png

    Problem OC9.4.

    PRCarrollsoln.png

    Problem OC10.1.

    olefmetdrillsoln.png

    Problem OC10.2.

    olefmetpolydrillsoln.png

    Problem OC10.3.

    olefmetrcmdrillsoln.png

    Problem OC10.4.

    burkebryostatinsoln.png


    This page titled 10.12: Solutions to Selected Problems is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by Kate Graham.

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