Refer to your organic chemistry lecture textbook (L.G. Wade Jr. Organic Chemistry, 6th ed.), chapter 13 (p. 559) and appendices 1A, 1B, and 1C (p. 1243). Your lab textbook also has a useful discussion in Technique 26, p. 868-899, including some useful spectra that you can compare your structures to.
Refer to the structures presented on p. 502 of your lab textbook
Each proton NMR signal is split into two by each nonequivalent neighboring proton. The size of the splitting (separation between the two peaks) is determined by the coupling constant J between the two neighbors. The coupling constant for two neighboring hydrogens connected through single bonds, such as Ha and Hb is Jab, and its average value is about 6 Hz (Wade, p. 583). The coupling constant for two neighboring protons connected through a pi-bond and trand to each other, such as Hb and Hc is Jbc, and its average value is about 15 Hz. Finally, when they are cis to each other (not the case in the above structure), the coupling constant average would be about 10Hz.
At the same time that we also consider the probable chemical shift (delta) values. For an aldehyde proton such as Ha, the average chemical shift is about 9-10ppm. For vinylic protons such as Hb and Hc the average chemical shift is about 6-7 ppm. We expect Hb to be closer to 7 because of the effect of the carbonyl group, and we expect Hc to be even higher, maybe greater than 8, because of the effect of the benzene ring. Finally, the protons in the benzene ring itself have an average chemical shift of about 7-8 ppm. Thus there might be overlap between Hc and the benzene ring signals.
We typically don't try to predict the pattern of benzene ring protons because it can follow complex factors whose study is beyond the scope of this course. Therefore we will simply accept that they will appear somewhere between 7-8ppm, but can never be sure about teh degree of complexity or the shape of the multiplet.
On the following page we have the predicted proton NMR spectrum according to the above guidelines. In reality, a spectrum may or may not appear as predicted, but the predicted pattern is a starting point towards the elucidation of the structure and eventual assignment of the signals actually observed.
Predicted Spectrum (by decreasing chemical shift):
Ha: 9-10 ppm, doublet, Jab ~ 6Hz
Benzene cluster: 7-8ppm, multiplet
Hc: 7-8 ppm, doublet, Jbc ~15Hz
Hb: 6-7 ppm, doublet of doublets, Jbc ~ 15Hz, Jab ~ 6Hz
Structure B hardly requires any discussion. Once again, we simply expect a multiplet around 7-8 ppm integrating to hydrogens for the benzene ring. We also expect the aldehyde proton around 9-10 ppm, expect that this time it's going to be a singlet because there are no adjecent protons.
The only other group present is the isopropyl group. Thus we expect to see the isopropyl group pattern (refer to p. 581 in the Wade textbook, 6th ed.). The methyl group doublet will probably appear between 1-2ppm (alkane region), whereas the septet, or multiplet, will be deshielded by the benzene ring, appearing around 2-3 ppm (benzyl group region). Since the benzene ring contains an electron withdrawing group at the para-position (the aldehyde group), we expect further deshielding of the benzyl protons Hb to where they might appear closer to 3ppm.
Structure C is a little more challenging. When we face this situation we try to predict the easiest patterns first. Once again, our benzene cluster will be around 7-8 ppm, except that now we expect it to integrate to only 3 hydrogens, since the benzene ring is trisubstituted. Likewise, the methyl protons (He) will appear as a singlet around 3-4 ppm, which is the region assigned to ethers, and they are further deshielded by the benzene ring. Hf is the next easiest to predict. It will be a single multiplet, but hydrogen bonding signals such as alcohol protons can fluctuate in a wide range of chemical shift values, maybe between 3-6ppm, and they could appear either as sharp or broad signals. It will obviously integrate to 1 hydrogen.
Hd protons only have one neighbor (Hc) to couple with. They are deshielded by the benzene ring and the double bond, so we expect them to appear in the allylic region, which is normally around 2ppm (table 13.3, p. 568 in Wade), but shifted downfield to maybe 3-4 ppm. We expect it to be a doublet integrating to 2 hydrogens, with a coupling constant Jdc of about 7 Hz.
Protons, Ha, Hb, and Hc, are even more challenging. For one thing they are all vinylic protons that will appear close together, but ocupled to their neighbors with different coupling constants.
Hc will probably appear separate from Ha and Hb further downfield because it's closer to the benzene ring. Its signal will be split once by Hb with a coupling constant of about 10 Hz because they are cis to each other. Then it will be split twice by Hd because there are two of them, with coupling constant of about 7 Hz. Thus we can predict a pattern such as the following.
However, be warned that there might be complicating effects such as long range coupling to far away protons, and others not uncommon in this type of spectrum. This can distort the appearance of the predicted pattern. Nonetheless, Hc will appear as a complex multiplet around 6ppm integrating to 1 hydrogen.
Ha and Hb are nonequivalent (one is cis to Hc while the other is trans) but will probably appear very close together, perhaps around 5ppm. The coupling constant between the two is very small- about 2 Hz- since they are geminal (see p. 583 of Wade). Thus, we might predict a kind of triplet such as might be the following:
However, once again, there might be complicating effects that may distort the appearance of the predicted pattern. Nonetheless, this cluster will appear as a multiplet around 5 ppm integrating to 1 hydrogen as well.
At this point you should be able to predict the appearance and chemical shifts of the methyl groups Hc and Hd, and of proton Ha, based on the precious discussions for the other molecules containing similar types of hydrogens.
Ha will probably appear as a doublet around 6-7 ppm with Jab of about 15 Hz for cis coupling and integrating to 1 hydrogen.
This leaves us with Hb. This will probably appear as a multiplet around 6-7 ppm (very close to Ha), split once by Ha with JabI of about 15 Hz, and three times by Hc with Jab of about 7 Hz. Needless to say, it will probably the most complex multiplet in the spectrum (along with the benzene ring), very close to Ha and integrating to 1 hydrogren. The tree below shows the spectrum (along with the benzene ring), very close to Ha and integrating to 1 hydrogen. The tree below shows the predicted pattern, but again, we expect that the actual appearance could be distorted due to additional effects.
Let's consider first of all that we have several sets of allylic protons here, namely Ha, Hc, He, and Hi. All of these protons will probably appear close together in the allylic region, 2-3 ppm. However, the methyl groups Ha and He should stand out as singlets, since technically they don't have neighboring protons on adjacent carbons to couple to. However they could exhibit long range coupling to far away protons and show some fine splitting.
Protons Hd and Hh might also appear close together and could overlap with the allylic protons, creating a highly complex multiplet. However, the methyl groups should be highly visible and should integrate to a total of 6 hydrogens. Likewise, the integral for the complex multiplet will indicate how many hydrogens it represents. Beyond these remarks we cannot say much more about the pattern of all these protons.
Next we have the vinylic protons, whose typical range is between 5-7 ppm (table 13-3, p. 568, Wade). First we look at the geminal protons Hf and Hg. They are nonequivalent, since one is cis and the other trans to the methyl group. They should be singlets, although probably close together, integrating to 1 hydrogen each.
Finally, proton Hb will also appear in the vinylic region, but it will be coupled to protons Hc and possibly long range coupled to other allylic protons, creating a multiplet which also integrates to 1 hydrogen.