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- https://chem.libretexts.org/Courses/Williams_School/Chemistry_II/14%3A_Metals_and_Alloys/14.01%3A_Bonding_in_MetalsFor a hypothetical infinite chain (i.e., a 1D crystal) of Na atoms, the molecular orbitals at the bottom of the 3s band are fully bonding and the wavelength of electrons (2x the distance between nodes...For a hypothetical infinite chain (i.e., a 1D crystal) of Na atoms, the molecular orbitals at the bottom of the 3s band are fully bonding and the wavelength of electrons (2x the distance between nodes) in these orbitals is very long. Because of the parabolic relation between E and k, the density of states for a 1D metallic crystal is highest near the bottom and top of the energy band where the slope of the E vs.
- https://chem.libretexts.org/Courses/CSU_San_Bernardino/CHEM_4300%3A_Inorganic_Chemistry_(Mink)/07%3A_Metals_and_Alloys-_Structure_Bonding_Electronic_and_Magnetic_Properties/7.05%3A_Bonding_in_MetalsFor a hypothetical infinite chain (i.e., a 1D crystal) of Na atoms, the molecular orbitals at the bottom of the 3s band are fully bonding and the wavelength of electrons (2x the distance between nodes...For a hypothetical infinite chain (i.e., a 1D crystal) of Na atoms, the molecular orbitals at the bottom of the 3s band are fully bonding and the wavelength of electrons (2x the distance between nodes) in these orbitals is very long. Because of the parabolic relation between E and k, the density of states for a 1D metallic crystal is highest near the bottom and top of the energy band where the slope of the E vs.
- https://chem.libretexts.org/Courses/UW-Whitewater/Chem_260%3A_Inorganic_Chemistry_(Girard)/10%3A_Metals_and_Alloys-_Structure_Bonding_Electronic_and_Magnetic_Properties/10.05%3A_Bonding_in_MetalsFor a hypothetical infinite chain (i.e., a 1D crystal) of Na atoms, the molecular orbitals at the bottom of the 3s band are fully bonding and the wavelength of electrons (2x the distance between nodes...For a hypothetical infinite chain (i.e., a 1D crystal) of Na atoms, the molecular orbitals at the bottom of the 3s band are fully bonding and the wavelength of electrons (2x the distance between nodes) in these orbitals is very long. Because of the parabolic relation between E and k, the density of states for a 1D metallic crystal is highest near the bottom and top of the energy band where the slope of the E vs.
- https://chem.libretexts.org/Courses/Williams_School/Advanced_Chemistry/19%3A_Metals_and_Alloys/19.01%3A_Bonding_in_MetalsFor a hypothetical infinite chain (i.e., a 1D crystal) of Na atoms, the molecular orbitals at the bottom of the 3s band are fully bonding and the wavelength of electrons (2x the distance between nodes...For a hypothetical infinite chain (i.e., a 1D crystal) of Na atoms, the molecular orbitals at the bottom of the 3s band are fully bonding and the wavelength of electrons (2x the distance between nodes) in these orbitals is very long. Because of the parabolic relation between E and k, the density of states for a 1D metallic crystal is highest near the bottom and top of the energy band where the slope of the E vs.
