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10.8: Organometallic Coupling Reactions

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    482379
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    Many other kinds of organometallic compounds can be prepared in a manner similar to that of Grignard reagents. For instance, alkyllithium reagents, RLi, can be prepared by the reaction of an alkyl halide with lithium metal. Alkyllithiums are both nucleophiles and strong bases, and their chemistry is similar in many respects to that of alkylmagnesium halides.

    1-bromobutane reacts with 2 equivalents of lithium in pentane to form butyllithium and LiBr. C1 of butyllithium (ball-and-stick model in an electrostatic potential map) is labeled basic and nucleophilic.

    Gilman Reagents

    One particularly valuable reaction of alkyllithiums occurs when making lithium diorganocopper compounds, R2CuLi, by reaction with copper(I) iodide in diethyl ether as solvent. Often called Gilman reagents (LiR2Cu), lithium diorganocopper compounds are useful because they undergo a coupling reaction with organochlorides, bromides, and iodides (but not fluorides). One of the alkyl groups from the lithium diorganocopper reagent replaces the halogen of the organohalide, forming a new carbon–carbon bond and yielding a hydrocarbon product. Lithium dimethylcopper, for instance, reacts with 1-iododecane to give undecane in a 90% yield.

    The reaction of 2 equivalents of methyllithium with copper iodide in ether forms lithium dimethylcopper (a Gilman reagent) and lithium iodide.
    Lithium dimethylcopper and 1-iododecane in ether at 0 degrees Celcius forms undecane (90%), lithium iodide, and methyl copper.

    Example

    This organometallic coupling reaction is useful in organic synthesis because it forms carbon–carbon bonds, thereby allowing the preparation of larger molecules from smaller ones. As the following examples indicate, the coupling reaction can be carried out on aryl and vinylic halides as well as on alkyl halides.

    Trans-1-iodo-1-nonene reacts with lithium dibutylcopper to form trans-5-tridecene (71%), n-butylcopper, and LiI. Iodobenzene reacts with lithium dimethylcopper to form toluene (91%), methyl copper, and LiI.

    An organocopper coupling reaction is carried out commercially to synthesize muscalure, (9Z)-tricosene, the sex attractant secreted by the common housefly. Minute amounts of muscalure greatly increase the lure of insecticide-treated fly bait and provide an effective and species-specific means of insect control.

    The reaction of cis-1-bromo-9-octadecene with lithium dipentylcopper form muscalure (9Z-tricosene).

    Mechanism

    The mechanism of the coupling reaction involves initial formation of a triorganocopper intermediate, followed by coupling and loss of a mono-organocopper, RCu. The coupling is not a typical polar nucleophilic substitution reaction of the sort considered in the next chapter.

    Coupling mechanism.svg

    The Suzuki-Miyaura Reaction

    In addition to the coupling reaction of diorganocopper reagents with organohalides, related processes also occur with other organometallic reagents, particularly organopalladium compounds. One of the most commonly used procedures is the coupling reaction of an aromatic or vinyl substituted boronic acid [R—B(OH)2] with an aromatic or vinyl substituted organohalide in the presence of a base and a palladium catalyst. This reaction is less general than the diorganocopper reaction because it doesn’t work with alkyl substrates, but it is preferred when possible because it uses only a catalytic amount of metal rather than a full equivalent and because palladium compounds are less toxic than copper compounds. For example:

    The reaction of an aromatic substituted boronic acid and iodobenzene in the presence of palladium-tetrakis(triphenylphosphine), calcium carbonate, and tetrahydrofuran form a biaryl compound (92%).

    Called the Suzuki–Miyaura reaction, this process is particularly useful for preparing so-called biaryl compounds, which have two linked aromatic rings. A large number of commonly used drugs fit this description, so the Suzuki–Miyaura reaction is much-used in the pharmaceutical industry.

    Example

    As an example, valsartan, marketed as Diovan, is widely prescribed to treat high blood pressure, heart failure, and diabetic kidney disease. Its synthesis begins with a Suzuki–Miyaura coupling of ortho-chlorobenzonitrile with para-methylbenzeneboronic acid.

    The reaction of para-methylbenzeneboronic acid and ortho-chloro-benzonitrile in the presence of palladium catalyst and potassium carbonate forms an intermediate that further produces Valsartan (Diovan).

    Mechanism

    Shown in a simplified form in Figure \(\PageIndex{1}\), the mechanism of the Suzuki–Miyaura reaction involves initial reaction of the aromatic halide with the palladium catalyst to form an organopalladium intermediate, followed by reaction of that intermediate with the aromatic boronic acid. The resultant diorganopalladium complex then decomposes to the coupled biaryl product plus regenerated catalyst.

    Via a three-step cyclic reaction, an aromatic halide reacts with catalyst, forming an organopalladium intermediate, which reacts with aromatic boronic acid, yielding diarylpalladium intermediate. Decomposition produces a biaryl product.
    Figure \(\PageIndex{1}\): Mechanism of the Suzuki–Miyaura coupling reaction of an aromatic boronic acid with an aromatic halide to give a biaryl. The reaction takes place by (1) reaction of the aromatic halide, ArX, with the catalyst to form an organopalladium intermediate, followed by (2) reaction with the aromatic boronic acid. (3) Subsequent decomposition of the diarylpalladium intermediate gives the biaryl product.
    Exercise \(\PageIndex{1}\)

     Starting with alkyl halides containing no more than four carbon atoms, how would you synthesize each of the following alkanes?

    1. 2,5-dimethylhexane
    2. 2-methylhexane
    Answer
    Notice that in (a), both the alkyl halides are primary. This fact should ensure a good yield of product.
    10-7b-answer.png
    In (b) we have the choice of using 2-bromopropane and 1-bromobutane, or 1-bromo-2-methylpropane and 1-bromopropane. We chose the latter as it enables us to use two primary alkyl halides, and hence a simpler procedure.
    10-7a-answer.png
    Exercise \(\PageIndex{2}\)

    How would you carry out the following transformations using an organocopper coupling reaction? More than one step is required in each case.

    1. Cyclohexene reacts with an unknown reactant represented by a question mark to form 3-methyl-1-cyclohexene.
    2. 1-bromobutane reacts with an unknown reactant represented by a question mark to form octane.
    3. Pent-1-ene reacts with an unknown reactant represented by a question mark to form decane.
    Answer
    1. 1. NBS; 2. (CH3)2CuLi
    2. 1. Li; 2. CuI; 3. CH3CH2CH2CH2Br
    3. 1. BH3; 2. H2O2, NaOH; 3. PBr3; 4. Li, then CuI; 5. CH3(CH2)4Br

    This page titled 10.8: Organometallic Coupling Reactions is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by Sol Parajon Puenzo (Cañada College) via source content that was edited to the style and standards of the LibreTexts platform.