13.E: Homework Chapter 13 Answers
- Page ID
- 202224
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\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)Solutions, Solvents, and Solutes:
1. a.) Solution: a homogeneous mixture composed of two or more substances
b.) Solvent: the major component in a solution
c.) Solute: the minor component in a solution
3. The two substances will not mix together. Imagine mixing oil and water together, the oil will float to the top of the water, and not mix together. This would not be a solution, this would be a heterogeneous mixture.
5. Solvent: ethyl alcohol; Solute: water
7. Solvent: water; Solute: sodium hydroxide
9. c.) CH3CH2CH2CH3 *remember: “like dissolves like,” butane is nonpolar like grease*
11. 25.245g KNO3
13. 19.912 g CO2
15. 2.0812 mol Al; Aluminum is the solute.
17. The solution would be unsaturated, because at 25 degrees Celsius, the point would fall below the solubility curve, indicating that it is unsaturated.
Mass Percent Calculations:
19. = 33.7 %
21. a.) 4.52%
b.) 10.9%
c.) 9.09%
23. 107%
25. 1.8%
27. 29.7%
29. 6.08%
Molarity Calculations:
31. a.) 0778 M
b.) 0.108 M
c.) 0.0521 M
d.) 0.493 M
33. 0.255 g KCl
35. 0.752 M
37. 0.0344 M
39. 7.68 M
Dilution Calculations:
41. M2 = 7.05 M
43. V1 = 12.5 mL
45. You would need to take 3.00mL of the 10.0 M stock solution and dilute it to 15.0 mL.
47. a.) V2 = 18.0 mL
b.) V2 = 14.0 mL
c.) V2 =52.5 mL
d.) V2 = 40.0 mL
49. V2 = 18.545 L
51. V2 = 125 mL
53. a.) M1 = 5.00 M
b.) M1 = 6.00 M
c.) M1 = 7.50 M
d.) M1 = 5.7692 M
55. M1 = 3.50 M
57. V2 = 24.0 mL
Cumulative/Challenge Problems:
59. Solvent: soap; Solute: water
61. M2 = 1.67 M