6.1: Electronegativity and Polarity (Problems)
- Page ID
- 112694
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\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)PROBLEM \(\PageIndex{1}\)
Predict which of the following compounds are ionic and which are covalent, based on the location of their constituent atoms in the periodic table:
a. Cl2CO
b. MnO
c. NCl3
d. CoBr2
e. K2S
f. CO
g. CaF2
h. HI
i. CaO
j. IBr
k. CO2
- Answer a
-
covalent
- Answer b
-
ionic
- Answer c
-
covalent
- Answer d
-
ionic
- Answer e
-
ionic
- Answer f
-
covalent
- Answer g
-
ionic
- Answer h
-
covalent
- Answer i
-
ionic
- Answer j
-
covalent
- Answer k
-
covalent
PROBLEM \(\PageIndex{2}\)
Explain the difference between a nonpolar covalent bond, a polar covalent bond, and an ionic bond.
- Answer
-
nonpolar covalent: electronegativity difference is less than 0.4 (nonmetal+nonmetal close together on the periodic table)
polar covalent: electronegativity difference in between 0.4 and 2.0 (nonmetal + nonmental further apart on the periodic table)
ionic: electronegativity difference is above 2.0 (metal + nonmetal)
PROBLEM \(\PageIndex{3}\)
From its position in the periodic table, determine which atom in each pair is more electronegative:
a. Br or Cl
b. N or O
c. S or O
d. P or S
e. Si or N
f. Ba or P
g. N or K
- Answer a
-
Cl
- Answer b
-
O
- Answer c
-
O
- Answer d
-
S
- Answer e
-
N
- Answer f
-
P
- Answer g
-
N
PROBLEM \(\PageIndex{4}\)
From its position in the periodic table, determine which atom in each pair is more electronegative:
a. N or P
b. N or Ge
c. S or F
d. Cl or S
e. H or C
f. Se or P
g. C or Si
- Answer a
-
N
- Answer b
-
N
- Answer c
-
F
- Answer d
-
Cl
- Answer e
-
C
- Answer f
-
P
- Answer g
-
C
PROBLEM \(\PageIndex{5}\)
From their positions in the periodic table, arrange the atoms in each of the following series in order of increasing electronegativity:
a. C, F, H, N, O
b. Br, Cl, F, H, I
c. F, H, O, P, S
d. Al, H, Na, O, P
e. Ba, H, N, O, As
- Answer a
-
H, C, N, O, F
- Answer b
-
H, I, Br, Cl, F
- Answer c
-
H, P, S, O, F
- Answer d
-
Na, Al, H, P, O
- Answer e
-
Ba, H, As, N, O
PROBLEM \(\PageIndex{6}\)
Which is the most polar bond?
C–C; C–H; N–H; O–H; Se–H
- Answer
-
O–H
PROBLEM \(\PageIndex{7}\)
Identify the more polar bond in each of the following pairs of bonds:
a. HF or HCl
b. NO or CO
c. SH or OH
d. PCl or SCl
e. CH or NH
f. SO or PO
g. CN or NN
- Answer a
-
HF
- Answer b
-
CO
- Answer c
-
OH
- Answer d
-
PCl
- Answer e
-
NH
- Answer f
-
PO
- Answer g
-
CN
PROBLEM \(\PageIndex{8}\)
Which of the following molecules or ions contain polar bonds?
a. O3
b. \(\ce{O2^2-}\)
c. \(\ce{NO3-}\)
d. CO2
e. H2S
f. \(\ce{BH4-}\)
g. S8
- Answer
-
c, d, e, f
Contributors
Paul Flowers (University of North Carolina - Pembroke), Klaus Theopold (University of Delaware) and Richard Langley (Stephen F. Austin State University) with contributing authors. Textbook content produced by OpenStax College is licensed under a Creative Commons Attribution License 4.0 license. Download for free at http://cnx.org/contents/85abf193-2bd...a7ac8df6@9.110).
- Adelaide Clark, Oregon Institute of Technology
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