8.4: Unit 8 Practice Problems
- Page ID
- 260668
Question 1.
If the pressure inside a tank is 100. psi, what is this pressure in kPa, mPa, atm, mmHg?
- Answer
- \[\mathrm{100\: \cancel{psi.} \times \dfrac{101\: kPa}{14.7\:\cancel{psi.}}=687\: kPa}\] \[\mathrm{100\: \cancel{psi.} \times \dfrac{0.101\: MPa}{14.7\:\cancel{psi.}}=0.687\: MPa}\] \[\mathrm{100\: \cancel{psi.} \times \dfrac{1\: atm}{14.7\:\cancel{psi.}}=6.8\: atm}\] \[\mathrm{100\: \cancel{psi.} \times \dfrac{760\: mmHg}{14.7\:\cancel{psi.}}=5170\: mmHg}\]
Question 2.
A gas occupies a volume of 17.4L at 11.2 psi, what will it's volume be if the pressure is increased to 13.6psi and the temperature is held constant?
- Answer
- P1V1 = P2V2 (11.2psi)(17.4L) = (13.6psi)(V2 ) V2 = 14.3L
Question 3.
A gas has a volume of 186mL at 32°C, what will it's volume be if the temperature of the gas is increased to 104°C and the pressure is held constant?
- Answer
- V1/T1 = V2/T2 Remember that when using gas laws, temperature should always be in K. (186mL) / (305K) = (V2) / (377K) V2 = 230mL
Question 4.
A container of neon at a pressure of 550mmHg and a temp of 120°C is heated (at a constant volume) until the temperature is 360°C. What is the new pressure of the heated neon?
- Answer
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P1/T1 = P2/T2 Remember that when using gas laws, temperature should always be in K. (550mmHg) / (393K) = (P2) / (633K) P2 = 890 mmHg
Question 5.
A cylinder containing 12.0L of compressed air at 23.0atm and -20.0°C is opened and the air escapes into a room which has a pressure of 0.960atm and warms to 28.0°C, what is the final volume of the air from the cylinder?
- Answer
Question 6.
If a gas has a volume of 19.8L at standard temperature and pressure (STP), how many moles of gas are there?
- Answer
Question 7.
If 1.0 grams of a gas occupies a volume of 330mL at STP, what is the molecular weight of the gas?
- Answer
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Question 9.
A gas occupies 6.4L at 102kPa and 294K, what will the temperature of the gas be at 8.7L and 97kPa?
- Answer
Question 10.
If I have 2.6 moles of a gas at a pressure of 4.3 atm and a volume of 8.4 liters, what is the temperature? (R=0.0821 L*atm/mol*K)
- Answer