7.5.2: Practice Stoichiometry part 1
- Page ID
- 424684
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Mole to Mole Conversions
Exercise \(\PageIndex{1}\)
Fe2O3 (s) + 3 CO (g) \(\rightarrow\) 2 Fe (s) + 3 CO2 (g)
For the reaction above, how many moles of Fe would be produced from 0.877 moles Fe2O3?.
- Answer
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1.75 mol Fe
How many moles of CO2 would be produced from 0.438 moles Fe2O3?.
- Answer
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1.31 mol CO2
How many moles of Fe would be produced from 0.545 moles CO?.
- Answer
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0.363 mol Fe
Mass to Mass Conversions
Exercise \(\PageIndex{1}\)
Mg3N2 (s) + 6 H2O (l) \(\rightarrow\) 3 Mg(OH)2 (s) + 2 NH3 (g)
How many grams of H2O would react with 34.88 grams Mg3N2?
- Answer
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\(34.88 g Mg_3N_2 \times \dfrac{1 mol Mg_3N_2}{100.95 g Mg_3N_2} \times \dfrac{6 mol H_2O}{1 mol Mg_3N_2} \times \dfrac{18.02 g H_2O}{1 mol H_2O}\)
= 37.36 g H2O
How many grams of NH3 would be produced from 76.77 grams Mg3N2?.
- Answer
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\(76.77 g Mg_3N_2 \times \dfrac{1 mol Mg_3N_2}{100.95 g Mg_3N_2} \times \dfrac{2 mol NH_3}{1 mol Mg_3N_2} \times \dfrac{17.04 g NH_3}{1 mol NH_3}\)
= 25.92 g NH3
How many grams of Mg(OH)2 are produced from 46.32 g H2O?
- Answer
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\(46.32 g H_2O \times \dfrac{1 mol H_2O}{18.02 g H_2O} \times \dfrac{3 mol Mg(OH)_2}{6 mol H_2O} \times \dfrac{58.33 g Mg(OH)_2}{1 mol Mg(OH)_2}\)
= 74.97 g Mg(OH)2
Mixed Stoichiometry
Exercise \(\PageIndex{1}\)
C3H8 (g) + 5 O2 (g) \(\rightarrow\) 3 CO2 (g) + 4 H2O (g)
How many grams of O2 are needed to produce 4.22 moles of CO2?
- Answer
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225 grams of O2
How many moles of C3H8 produce 87.8 grams of H2O?
- Answer
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1.22 moles C3H8
How many grams of CO2 are produced by a reaction that also produces 2.87 moles H2O?
- Answer
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94.7 g CO2