Skip to main content
Chemistry LibreTexts

1.5.2: Comprehension Check

  • Page ID
    235822
  • \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\)

    Exercise \(\PageIndex{1}\)

    A reported value of 45.35 g implies that the mass is between ___ and ___.

    Answer

    Mass is between 45.34 g and 45.36 g. It is 45.35 g plus or minus 0.01 g.

    Is it possible for a number to have NO uncertainty?

    Answer

    A defined value or a number of counted items could be exact and therefore have no uncertainty.

    Which of the following could be used to measure the precision of a set of numbers?

    a) average (mean)

    b) percent error

    c) standard deviation

    d) median

    Answer

    c) standard deviation (It tells how close a group of values are to each other. The other choices do not do that.)

    Exercise \(\PageIndex{1}\)

    You perform an experiment to determine the density of copper, and you obtain a value of 8.62 g/mL. Your reference lists the accepted value as 8.96 g/mL. What is the percent error of your measured value?

    Answer

    It is 3.8%.

    The difference between the values, 0.34 g/mL, is divided by the accepted value of 8.96 g/mL. The result is 0.038. This is multiplied by 100% to give 3.8%.

    Exercise \(\PageIndex{1}\)

    You are measuring the liquid that is dispensed by a pump that is supposed to dispense 25.00 mL. You measure the following amounts: 24.72 mL, 24.88 mL, 24.85 mL and 24.77 mL. Calculate the average, standard deviation, and percent error.

    Answer

    Average = 24.81 mL. Standard deviation = 0.07 mL. Percent error = 0.76 %


    1.5.2: Comprehension Check is shared under a not declared license and was authored, remixed, and/or curated by LibreTexts.

    • Was this article helpful?