2.E: Unsaturated and Aromatic Hydrocarbons (Exercises)
- Page ID
- 337789
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Additional Exercises
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Classify each compound as saturated or unsaturated.
- CH3C≡CCH3
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Classify each compound as saturated or unsaturated.
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Give the molecular formula for each compound.
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When three isomeric pentenes—X, Y, and Z—are hydrogenated, all three form 2-methylbutane. The addition of Cl2 to Y gives 1,2-dichloro-3-methylbutane, and the addition of Cl2 to Z gives 1,2-dichloro-2-methylbutane. Draw the original structures for X, Y, and Z.
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Pentane and 1-pentene are both colorless, low-boiling liquids. Describe a simple test that distinguishes the two compounds. Indicate what you would observe.
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Draw and name all the alkene cis-trans isomers corresponding to the molecular formula C5H10. (Hint: there are only two.)
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The complete combustion of benzene forms carbon dioxide and water:
C6H6 + O2 → CO2 + H2OBalance the equation. What mass, in grams, of carbon dioxide is formed by the complete combustion of 39.0 g of benzene?
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Describe a physiological effect of some PAHs.
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What are some of the hazards associated with the use of benzene?
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What is wrong with each name? Draw the structure and give the correct name for each compound.
- 2-methyl-4-heptene
- 2-ethyl-2-hexene
- 2,2-dimethyl-3-pentene
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What is wrong with each name?
- 2-bromobenzene
- 3,3-dichlorotoluene
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Following are line-angle formulas for three compounds. Draw the condensed structure and give the name for each.
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Following are ball-and-stick molecular models for three compounds (blue balls represent H atoms; red balls are C atoms). Write the condensed structural formula and give the name for each.
Answers
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- unsaturated
- unsaturated
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- C6H10
- C4H8
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Add bromine solution (reddish-brown) to each. Pentane will not react, and the reddish-brown color persists; 1-pentene will react, leaving a colorless solution.
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2C6H6 + 15O2 → 12CO2 + 6H2O; 132 g
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carcinogenic, flammable
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- number not needed
- can’t have two groups on one carbon atom on a benzene ring
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- CH3CH=CHCH2CH2CH3; 2-hexene