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4.9: Halogenation, Sulfonation, and Nitration of Aromatic Compounds

  • Page ID
    221791
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    Objectives

    After completing this section, you should be able to

    1. write a balanced equation for the halogenation (F, Cl, Br, I) of benzene in the presence of a suitable catalyst or promoter.
    2. draw the resonance contributors for the carbocation which is formed during the reaction of chlorine or bromine with benzene.
    3. write the equation for the nitration and sulfonation of benzene.
    4. write the detailed mechanism for the nitration and sulfonation of benzene.
    5. write the equation for the reduction of an aromatic nitro compound to an amine.
    6. identify aromatic sulfonation as being a reversible process, and describe the conditions under which the forward and reverse reactions are favoured.
    7. write the equation for the desulfonation of an aromatic sulfonic acid.
    8. identify aromatic sulfonic acids as being key intermediates in the manufacture of sulfa drugs.
    Key Terms

    Make certain that you can define, and use in context, the key term below.

    • nitronium ion, (NO+2)
    Study Notes

    You should be careful to remember that iodine and fluorine cannot be introduced into an aromatic ring by the method used for bromine and chlorine. On its own, iodine is unreactive with aromatic rings, but one method for aromatic iodination is treatment in the presence of a copper salt such as copper(II)chloride where I2 is oxidized to the more electrophilic species I+.

    synthesis of iodobenzene from benzene

    In contrast, fluorine is too reactive, so it cannot be used directly for aromatic flourination. However, fluorinating agents like 1-(chloromethyl)-4-fluoro-1,4-diazoniabicyclo[2.2.2]octane ditetrafluoroborate (also known as F-TEDA-BF4) sold commercially as Sectfluor® offer convenient sources of “F+” for this type of reaction.

    fluorinating agent F-TEDA-BF4

    F-TEDA-BF4

    synthesis of fluorobenzene from benzene

    The overall equation for the formation of nitronium ions by the action of sulfuric acid on nitric acid is

    $\ce{\sf{HNO3 + 2H2SO4 <=> H3O+ + NO2+ + HSO4- }}$

    The ability of compounds such as nitronium tetrafluoroborate to bring about the nitration of aromatic compounds is good evidence in support of the proposed mechanism.

    The nitration of an aromatic ring is an important synthetic pathway to generating arylamines. The reaction below shows one common method of reducing the nitro group. (Amines are examined in more detail in Chapter 24.)

    reduction of nitrobenzene to aniline

    Halogenation of Benzene

    Halogenation is an example of electrophillic aromatic substitution. In electrophilic aromatic substitutions, a benzene is attacked by an electrophile which results in substition of hydrogens. However, halogens are not electrophillic enough to break the aromaticity of benzenes, which require a catalyst to activate.

    Activation of Halogen

    (where X= Br or Cl, we will discuss further in detail later why other members of the halogen family Flourine and Iodine are not used in halogenation of benzenes)

    There is no reaction

    Hence, Halogen needs the help and aid of Lewis Acidic Catalysts to activate it to become a very strong electrophile. Examples of these activated halogens are Ferric Hallides (FeX3) Aluminum Halides (AlX3) where X= Br or Cl. In the following examples, the halogen we will look at is Bromine.

    In the example of bromine, in order to make bromine electrophillic enough to react with benzene, we use the aid of an aluminum halide such as aluminum bromide.

    Bond line drawing of aluminum bromide.

    With aluminum bromide as a Lewis acid, we can mix Br2 with AlBr3 to give us Br+. The presence of Br+ is a much better electrophile than Br2 alone. Bromination is acheived with the help of AlBr3 (Lewis acid catalysts) as it polarizes the Br-Br bond. The polarization causes polarization causes the bromine atoms within the Br-Br bond to become more electrophillic. The presence of Br+ compared to Br2 alone is a much better electrophille that can then react with benzene.

    Reaction between Br2 and aluminum bromide.

    As the bromine has now become more electrophillic after activation of a catalyst, an electrophillic attack by the benzene occurs at the terminal bromine of Br-Br-AlBr3. This allows the other bromine atom to leave with the AlBr3 as a good leaving group, AlBr4-.

    Mechanism for benzene reacting with Br2 and aluminum bromide.

    Reaction of benzene, Br2 and aluminum bromide.

    After the electrophilic attack of bromide to the benzene, the hydrogen on the same carbon as bromine substitutes the carbocation in which resulted from the attack. Hence it being an electrophilic aromatic SUBSTITUTION. Since the by-product aluminum tetrabromide is a strong nucleophile, it pulls of a proton from the Hydrogen on the same carbon as bromine.

    The final produce is bromobenzene, HBr, and aluminum bromide.

    In the end, AlBr3was not consumed by the reaction and is regenerated. It serves as our catalyst in the halogenation of benzenes.

    Dissociation Energies of Halogens and its Effect on Halogenation of Benzenes

    The electrophillic bromination of benzenes is an exothermic reaction. Considering the exothermic rates of aromatic halogenation decreasing down the periodic table in the Halogen family. Flourination is the most exothermic and Iodination would be the least. Being so exothermic, a reaction of flourine with benzene is explosive! For iodine, electrophillic iodination is generally endothermic, hence a reaction is often not possible. Similar to bromide, chlorination would require the aid of an activating presence such as Alumnium Chloride or Ferric Chloride. The mechanism of this reaction is the same as with Bromination of benzene.

    Nitration and sulfonation of benzene are two examples of electrophilic aromatic substitution. The nitronium ion (NO2+) and sulfur trioxide (SO3) are the electrophiles and individually react with benzene to give nitrobenzene and benzenesulfonic acid respectively.

    Nitration of Benzene

    The source of the nitronium ion is through the protonation of nitric acid by sulfuric acid, which causes the loss of a water molecule and formation of a nitronium ion.

    Benzene reacts with NHO3 and H2SO4 to produce nitrobenzene.

    Sulfuric Acid Activation of Nitric Acid

    The first step in the nitration of benzene is to activate HNO3with sulfuric acid to produce a stronger electrophile, the nitronium ion.

    Mechanism showing sulfuric acid activating nitric acid.

    Because the nitronium ion is a good electrophile, it is attacked by benzene to produce Nitrobenzene.

    Mechanism

    Mechanism of aromatic nitration. The intermediate has three resonance structures.

    (Resonance forms of the intermediate can be seen in the generalized electrophilic aromatic substitution)

    Sulfonation of Benzene

    Sulfonation is a reversible reaction that produces benzenesulfonic acid by adding sulfur trioxide and fuming sulfuric acid. The reaction is reversed by adding hot aqueous acid to benzenesulfonic acid to produce benzene.

    Benzene reacts with SO3 and H2SO4 to produce benzenesulfonic acid.

    Mechanism

    To produce benzenesulfonic acid from benzene, fuming sulfuric acid and sulfur trioxide are added. Fuming sulfuric acid, also refered to as oleum, is a concentrated solution of dissolved sulfur trioxide in sulfuric acid. The sulfur in sulfur trioxide is electrophilic because the oxygens pull electrons away from it because oxygen is very electronegative. The benzene attacks the sulfur (and subsequent proton transfers occur) to produce benzenesulfonic acid.

    Mechanism of aromatic sulfonation.

    Reverse Sulfonation

    Sulfonation of benzene is a reversible reaction. Sulfur trioxide readily reacts with water to produce sulfuric acid and heat. Therefore, by adding heat to benzenesulfonic acid in diluted aqueous sulfuric acid the reaction is reversed.

    Benzenesulfonic acid reacts with water, heat, and sulfuric acid to produce benzene.

    Further Applications of Nitration and Sulfonation

    Nitration is used to add nitrogen to a benzene ring, which can be used further in substitution reactions. The nitro group acts as a ring deactivator. Having nitrogen present in a ring is very useful because it can be used as a directing group as well as a masked amino group. The products of aromatic nitrations are very important intermediates in industrial chemistry.

    Because sulfonation is a reversible reaction, it can also be used in further substitution reactions in the form of a directing blocking group because it can be easily removed. The sulfonic group blocks the carbon from being attacked by other substituents and after the reaction is completed it can be removed by reverse sulfonation. Benzenesulfonic acids are also used in the synthesis of detergents, dyes, and sulfa drugs. Bezenesulfonyl Chloride is a precursor to sulfonamides, which are used in chemotherapy.

    Exercises

    Exercise \(\PageIndex{1}\)

    1. What is/are the required reagent(s)for the following reaction:

    Benzene becomes benzenesulfonic acid.

    Answer

    SO3 and H2SO4 (fuming)

    Exercise \(\PageIndex{2}\)

    What is the product of the following reaction:

    Benzenesulfonic acid reacts with water, heat, and catalytic sulfuric acid.

    Answer

    16_2_2_Answer.svg

    Exercise \(\PageIndex{3}\)

    Why is it important that the nitration of benzene by nitric acid occurs in sulfuric acid?

    Answer

    Sulfuric acid is needed in order for a good electrophile to form. Sulfuric acid protonates nitric acid to form the nitronium ion (water molecule is lost). The nitronium ion is a very good electrophile and is open to attack by benzene. Without sulfuric acid the reaction would not occur.

    Exercise \(\PageIndex{4}\)

    Write a detailed mechanism for the sulfonation of benzene, including all resonance forms.

    Answer

    16_2_4_Answer.svg

    Exercise \(\PageIndex{5}\)

    Draw an energy diagram for the nitration of benzene. Draw the intermediates, starting materials, and products. Label the transition states.

    Answer

    16_2_5_Answer.svg

    Exercise \(\PageIndex{6}\)

    In each case, how many products would be possible for the bromination of p-xylene, o-xylene, and m-xylene?

    Answer

    16_2_6_Answer.svg

    Exercise \(\PageIndex{7}\)

    If toluene is treated with D2SO4 all the hydrogen’s are replaced with deuterium. Explain.

    Answer

    The deuterium is added to the ring. When the ring “re-aromatizes” the base scavenges the hydrogen before the deuterium and therefore is left on the ring. Continues for the rest of the hydrogen on the ring.

    16_2_7_Answer.svg

    References

    1. Laali, Kenneth K., and Volkar J. Gettwert. “Electrophilic Nitration of Aromatics in Ionic Liquid Solvents.” The Journal of Organic Chemistry 66 (Dec. 2000): 35-40. American Chemical Society.
    2. Malhotra, Ripudaman, Subhash C. Narang, and George A. Olah. Nitration: Methods and Mechanisms. New York: VCH Publishers, Inc., 1989.
    3. Sauls, Thomas W., Walter H. Rueggeberg, and Samuel L. Norwood. “On the Mechanism of Sulfonation of the Aromatic Nucleus and Sulfone Formation.” The Journal of Organic Chemistry 66 (1955): 455-465. American Chemical Society.
    4. Vollhardt, Peter. Organic Chemistry : Structure and Function. 5th ed. Boston: W. H. Freeman & Company, 2007.

    4.9: Halogenation, Sulfonation, and Nitration of Aromatic Compounds is shared under a not declared license and was authored, remixed, and/or curated by LibreTexts.