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2.7: Conformations of Other Alkanes

  • Page ID
    221755
  • Objectives

    After completing this section, you should be able to

    1. depict the staggered and eclipsed conformers of propane (or a similar compound) using sawhorse representations and Newman projections.
    2. sketch a graph of energy versus bond rotation for propane (or a similar compound) and discuss the graph in terms of torsional strain.
    3. depict the anti, gauche, eclipsed and fully eclipsed conformers of butane (or a similar compound), using sawhorse representations and Newman projections.
    4. sketch a graph of energy versus C2-C3 bond rotation for butane (or a similar compound), and discuss it in terms of torsional and steric repulsion.
    5. assess which of two (or more) conformers of a given compound is likely to predominate at room temperature from a semi-quantitative knowledge of the energy costs of the interactions involved.
    Key Terms

    Make certain that you can define, and use in context, the key terms below.

    • anti conformation
    • gauche conformation
    • eclipsed conformation
    • steric repulsion (strain)

    In butane, there are three rotating carbon-carbon sigma bonds to consider, but we will focus on the middle bond between C2 and C3. Below are two representations of butane in a conformation which puts the two CH3 groups (C1 and C4) in the eclipsed position.

    Newman projection of eclipsed conformation of butane.

    Eclipsed interaction Energy (kcal/mol) Energy (kJ/mol)
    H-H 1.0 4.0
    H-CH3 1.4 6.0
    CH3-CH3 2.6 11.0

    The CH3-CH3 groups create the significantly larger eclipsed interaction of 11.0 kJ/mol. There are also two H-H eclipsed interactions at 4.0 kJ/mol each to create a total of 2(4.0 kJ/mol) + 11.0 kJ/mol = 19.0 kJ/mol of strain. This is the highest energy conformation for butane, due to torsional strain caused by the electrostatic repulsion of electrons in the eclipsed bonds, but also because of another type of strain called ‘steric repulsion’, between the two rather bulky methyl groups. Steric strain comes about when two large groups, such as two methyl groups, try to occupy the same space. What results is a repulsive non-covalent interaction caused by their respective electron densities.

    If we rotate the front, (blue) carbon by 60°clockwise, the butane molecule is now in a staggered conformation.

    Staggered conformation of butane with guache methyl groups.

    This is more specifically referred to as the ‘gauche’ conformation of butane. Notice that although they are staggered, the two methyl groups are not as far apart as they could possibly be. There is still significant steric repulsion between the two bulky groups.

    A further rotation of 60° gives us a second eclipsed conformation (B) in which both methyl groups are lined up with hydrogen atoms.

    Eclipsed conformation of ethane with two methyl groups eclipsing with hydrogen.

    Due to steric repulsion between methyl and hydrogen substituents, this eclipsed conformation B is higher in energy than the gauche conformation. However, because there is no methyl-to-methyl eclipsing, it is lower in energy than eclipsed conformation A. One more 60° rotation produces the ‘anti’ conformation, where the two methyl groups are positioned opposite each other and steric repulsion is minimized.

    Staggered conformation of butane with anti methyl groups.

    The anti conformation is the lowest energy conformation for butane. The diagram below summarizes the relative energies for the various eclipsed, staggered, and gauche conformations.

    Interactive Element

    Figure \(\PageIndex{1}\): A 3D Structure of the Anti Butane Conformer.

    Graph of relative energy against degrees of rotation about the C2-C3 bond.
    Figure \(\PageIndex{2}\): Potential curve vs dihedral angle of the C2-C3 bond of butane.
    Figure \(\PageIndex{2}\): Newman projections of butane conformations & their relative energy differences (not total energies). Conformations form when butane rotates about one of its single covalent bond. Torsional/dihedral angle is shown on x-axis. Torsional/dihedral angle is shown on x-axis. Conformation names (according to IUPAC): A: anti-periplanar, anti or trans B: synclinal or gauche C: anticlinal or eclipsed D: syn-periplanar or cis. Source for conformation names & conformer classification: Pure & Appl. Chem., Vol. 68, No. 12, pp. 2193-2222, 1996. (Public Domain; Keministi).

    At room temperature, butane is most likely to be in the lowest-energy anti conformation at any given moment in time, although the energy barrier between the anti and eclipsed conformations is not high enough to prevent constant rotation except at very low temperatures. For this reason (and also simply for ease of drawing), it is conventional to draw straight-chain alkanes in a zigzag form, which implies the anti conformation at all carbon-carbon bonds. For example octane is commonly drawn as:

    Wedge-dash structure and bond line drawing of octane.

    Drawing Newman Projections

    Newman projections are a valuable method for viewing the relative positions of groups within molecule. Being able to draw the Newman projection for a given molecule is a valuable skill and will be used repeatedly throughout organic chemistry. Because organic molecules often contain multiple carbon-carbon bonds it is important to precisely know which bond and which direction is being sighted for the Newman projection. The details of the Newman projection change given the molecule but for typical alkanes a full conformational analysis involves a full 360o rotation in 60o increments. This will produce three staggered conformers and three eclipsed conformers. Typically, the staggered conformers are more stable and the eclipsed conformers are less stable. The least stable conformer will have the largest groups eclipsed while the most stable conformer will have the largest groups anti (180o) to each other.

    Example

    Draw the Newman projection of 2,3 dimethylbutane along the C2-C3 bond. Then determine the least stable conformation.

    First draw the molecule and locate the indicated bond:

    Looking down the C2-C3 bond of 2,3-dimethylbutane.

    Because the question asks for the least stable conformation, focus on the three possible eclipsed Newman projections. Draw out three eclipsed Newman projections as a template. Because it is difficult to draw a true staggered Newman projection, it is common to show the bonds slightly askew.

    Three possible eclipsed Newman projection with no groups place on it yet.

    Place the substituents attached to the second carbon (C3) on the back bonds of all three Newman projections. In this example they are 2 CH3s and an H. Place the substituents in the same position on all three Newman projections.

    The groups are filled in on the three Newman projections.

    Then place the substituents attached to the first carbon (C2) on the front bonds of the Newman projection. In this example, the substituents are also 2 CH3s and an H. Move the substituents through two 60o rotations to create the remaining two eclipsed Newman projections. Leave the substituents on the back carbon in place. Attempting to rotate the front and back carbons simultaneously is a common mistake and often leads to incorrect Newman projections.

    The groups are filled in on the three Newman projections.

    Compare the Newman projections by looking the eclipsed interactions. Remember that the order of torsional strain interactions are CH3-CH3 > CH3-H > H-H. The third structure has two CH3-CH3 torsional interactions which will make it the least stable conformer of 2,3 dimethyl butane.

    Least stable conformer of 2,3-dimethylbutane.

    Example \(\PageIndex{1}\)

    Draw Newman projections of the eclipsed and staggered conformations of propane, as if viewed down the C1-C2 bond.

    Answer
    The eclipsed Newman projection has the highest energy while the staggered Newman projection has the lowest energy.
    Example \(\PageIndex{2}\)

    Draw a Newman projection, looking down the C2-C3 bond, of 1-butene in the conformation shown below.

    Wedge-dash structure of 1-butene.

    Answer
    Newman project down the C2-C3 bond.

    Exercises

    Questions

    Q3.7.1

    Draw the energy diagram for the rotation of the bond highlighted in pentane.

    Solutions

    S3.7.1

    Contributors and Attributions

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