Skip to main content
Chemistry LibreTexts

6.2: Molecular Mass and Formula Mass

  • Page ID
    289381
  • \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\)

    ⚙️ Learning Objectives

    • Define formula mass and molecular mass.
    • To determine the formula mass of an ionic compound or molecular mass of a molecular compound.


    Why is knowledge of composition important? Everything in nature is either chemically or physically combined with other substances. To find the amount of a material in a sample, you need to know what fraction of the sample it is. Some simple applications of composition are: the amount of sodium in sodium chloride for a diet, the amount of iron in iron ore for steel production, the amount of hydrogen in water for hydrogen fuel, and the amount of chlorine in freon to estimate ozone depletion.
     

    Image of a spoonful of salt next to a lemon wedge.
    Figure \(\PageIndex{1}\): How much sodium is in this spoonful of salt? (via Flickr; Gianni pepenera).


    Molecular Mass and Formula Mass

    The composition of a compound may be determined from its chemical formula and the atomic masses of the elements that make up the compound. The mass of a molecule is called its molecular mass. The molecular mass is calculated summing the masses of all the atoms shown in the chemical formula.

    Ionic compounds are not comprised of discrete molecules, but rather, ions. The smallest unit of an ionic compound that retains the identity of an ionic compound is called a formula unit. The mass of a formula unit is called its formula mass. The formula mass is calculated summing the masses of all the atoms shown in the chemical formula. In other words, the molecular mass and formula mass are both calculated in an identical manner, by summing the masses of all the atoms shown in the chemical formula.

    As you may recall, the periodic table shows the average mass of the atoms for each element. We called this mass the atomic mass. The atomic mass of sodium is 22.99 amu and the atomic mass of chlorine is 35.45 amu.

    \(\boxed{\;\overset{11}{\underset{22.99}{\mathrm{Na}}}\;}\;\;\;\boxed{\;\overset{17}{\underset{35.45}{\mathrm{Cl}}}\;}\)

    Since NaCl is an ionic compound, we could calculate its formula mass. This formula mass is the sum of the atomic masses of one sodium atom and one chlorine atom, which we find from the periodic table:

    1 Na: 22.99 amu

    1 Cl: +35.45 amu

    Total: 58.44 amu

    In other words, the formula mass of NaCl is 58.44 amu. We may also say that one formula unit of NaCl has a mass of 58.44 amu.
     

    ✅ Example \(\PageIndex{1}\)

    Calculate the molecular mass or formula mass for each compound. (Periodic Table)

    1. C12H22O11
    2. Ca(NO3)2

    Solution

      C12H22O11 Ca(NO3)2
    1. Determine how many atoms of each element are present in the compound. Multiply the number of atoms of each element by its atomic mass.
        12 C = 12(12.01) = 144.1   amu
         22 H = 22(1.008) =   22.18 amu
        11 O = 11(16.00) = 176.0   amu
    1 Ca = 1(40.08) = 40.08 amu
     2 N = 2(14.01) = 28.02 amu
     6 O = 6(16.00) = 96.00 amu
    1. Sum the masses to find the molecular mass or formula mass.
    molecular mass = 342.3 amu formula mass = 164.10 amu
    1. Explanation.
    It is called a molecular mass since C12H22O11 is a molecular compound. It is called a formula mass since Ca(NO3)2 is an ionic compound.
    1. Interpretation.
    One molecule of C12H22O11 has a mass of 342.3 amu. One formula unit of Ca(NO3)2 has a mass of 164.10 amu.

     

    ✏️ Exercise \(\PageIndex{1}\)

    Calculate the molecular mass or formula mass for each compound. (Periodic Table)

    1. TiO2
    2. C6H12O6
    3. Fe3(PO4)2
    Answer A
    The formula mass is 79.90 amu.
    Answer B
    The molecular mass is 180.16 amu.
    Answer C
    The formula mass is 357.5 amu.


    Summary

    • Formula masses of ionic compounds and molecular masses of molecular compounds can be determined from the masses of the atoms in their formulas. 

     


    This page is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by Anonymous, Lance S. Lund (Anoka-Ramsey Community College), Marisa Alviar-Agnew, and Henry Agnew. 


    6.2: Molecular Mass and Formula Mass is shared under a not declared license and was authored, remixed, and/or curated by LibreTexts.

    • Was this article helpful?