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- https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Chemistry_for_Allied_Health_(Soult)/06%3A_Energy_and_Properties/6.02%3A_Energy_and_Properties_(Exercises)These are homework exercises to accompany Chapter 6 of the University of Kentucky's LibreText for CHE 103 - Chemistry for Allied Health. Solutions are available below the questions.
- https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Chemistry_for_Allied_Health_(Soult)/03%3A_Compounds/3.03%3A_Compounds_(Exercises)These are homework exercises to accompany Chapter 3 of the University of Kentucky's LibreText for CHE 103 - Chemistry for Allied Health. Solutions are available below the questions.
- https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Chemistry_for_Allied_Health_(Soult)/04%3A_Structure_and_Function/4.05%3A_Structure_and_Function_(Exercises)These are homework exercises to accompany Chapter 4 of the University of Kentucky's LibreText for CHE 103 - Chemistry for Allied Health. Solutions are available below the questions.
- https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Chemistry_for_Allied_Health_(Soult)/14%3A_Biological_Molecules/14.04%3A_Biological_Molecules_(Exercises)These are homework exercises to accompany Chapter 14 of the University of Kentucky's LibreText for CHE 103 - Chemistry for Allied Health.
- https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Chemistry_for_Allied_Health_(Soult)/00%3A_Front_Matter
- https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Chemistry_for_Allied_Health_(Soult)/10%3A_Nuclear_and_Chemical_Reactions
- https://chem.libretexts.org/Courses/Modesto_Junior_College/Chemistry_143_-_Bunag/Chemistry_143_-_Introductory_Chemistry_(Bunag)/18%3A_Acids_and_Bases/18.16%3A_Calculating_pH_of_Weak_Acid_and_Base_SolutionsFirst, an ICE table is set up with the variable x used to signify the change in concentration of the substance due to ionization of the acid. The higher pH of the 2.00M nitrous acid...First, an ICE table is set up with the variable x used to signify the change in concentration of the substance due to ionization of the acid. The higher pH of the 2.00M nitrous acid is consistent with it being a weak acid and therefore not as acidic as a strong acid would be. The procedure for calculating the pH of a solution of a weak base is similar to that of the weak acid in the example.
- https://chem.libretexts.org/Courses/Modesto_Junior_College/Chemistry_143_-_Bunag/Chemistry_143_-_Introductory_Chemistry_(Bunag)/19%3A_Nuclear_Chemistry/19.04%3A_Half-LifeHalf-life is defined. Calculations involving half-life are described.
- https://chem.libretexts.org/Courses/Modesto_Junior_College/Chemistry_143_-_Bunag/Chemistry_143_-_Introductory_Chemistry_(Bunag)/18%3A_Acids_and_Bases/18.01%3A_Properties_of_AcidsThe vinegar dissolves the deposits and cleans the maker, which will speed up the brewing process back to its original rate. Acids are a distinct class of compounds because of the properties of their a...The vinegar dissolves the deposits and cleans the maker, which will speed up the brewing process back to its original rate. Acids are a distinct class of compounds because of the properties of their aqueous solutions. Metals that are above hydrogen in the activity series will replace the hydrogen from an acid in a single-replacement reaction, as shown below: When equal moles of an acid and a base are combined, the acid is neutralized by the base.
- https://chem.libretexts.org/Courses/Modesto_Junior_College/Chemistry_143_-_Bunag/Chemistry_143_-_Introductory_Chemistry_(Bunag)/13%3A_The_Behavior_of_Gases/13.15%3A_Diffusion_and_Effusion_and_Graham's_LawThe equation can be rearranged to solve for the ratio of the velocity of gas A to the velocity of gas B (vAvB). For the purposes of comparing the rates of...The equation can be rearranged to solve for the ratio of the velocity of gas A to the velocity of gas B (vAvB). For the purposes of comparing the rates of effusion or diffusion of two gases at the same temperature, the molar masses of each gas can be used in the equation for m. Graham's law states that the rate of effusion or diffusion of a gas is inversely proportional to the square root of the molar mass of the gas.
- https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Chemistry_for_Allied_Health_(Soult)/01%3A_Measurements_and_Problem-Solving/1.05%3A_Measurements_and_Problem-Solving_(Exercises)These are homework exercises to accompany Chapter 1 of the University of Kentucky's LibreText for CHE 103 - Chemistry for Allied Health. Solutions are available below the questions.
