5.1: Components of the Nucleus
Skills to Develop

To understand the factors that affect nuclear stability.
Although most of the known elements have at least one isotope whose atomic nucleus is stable indefinitely, all elements have isotopes that are unstable and disintegrate, or decay, at measurable rates by emitting radiation. Some elements have no stable isotopes and eventually decay to other elements. In contrast to the chemical reactions that were the main focus of earlier chapters and are due to changes in the arrangements of the valence electrons of atoms, the process of nuclear decay results in changes inside an atomic nucleus. We begin our discussion of nuclear reactions by reviewing the conventions used to describe the components of the nucleus.
The Atomic Nucleus
Each element can be represented by the notation \(^A_Z \textrm X\)
\(^A_Z \textrm X\)  \(^{16}_8 \textrm O\)  \(^{17}_8 \textrm O\)  \(^{18}_8 \textrm O\) 
\(^A \textrm X\)  \(^{16} \textrm O\)  \(^{17} \textrm O\)  \(^{18} \textrm O\) 
\(\textrm{elementA:}\)  \(\textrm{oxygen16}\)  \(\textrm{oxygen17}\)  \(\textrm{oxygen18}\) 
Because the number of neutrons is equal to A − Z, we see that the first isotope of oxygen has 8 neutrons, the second isotope 9 neutrons, and the third isotope 10 neutrons. Isotopes of all naturally occurring elements on Earth are present in nearly fixed proportions, with each proportion constituting an isotope’s natural abundance. For example, in a typical terrestrial sample of oxygen, 99.76% of the O atoms is oxygen16, 0.20% is oxygen18, and 0.04% is oxygen17.
Any nucleus that is unstable and decays spontaneously is said to be radioactive, emitting subatomic particles and electromagnetic radiation. The emissions are collectively called radioactivity and can be measured. Isotopes that emit radiation are called radioisotopes. The rate at which radioactive decay occurs is characteristic of the isotope and is generally reported as a halflife (t_{1}_{/2}), the amount of time required for half of the initial number of nuclei present to decay in a firstorder reaction. An isotope’s halflife can range from fractions of a second to billions of years and, among other applications, can be used to measure the age of ancient objects. Example \(\PageIndex{1}\) and its corresponding exercise review the calculations involving radioactive decay rates and halflives.
Example \(\PageIndex{1}\)
Fort Rock Cave in Oregon is the site where archaeologists discovered several Indian sandals, the oldest ever found in Oregon. Analysis of the ^{14}C content of the sagebrush used to make the sandals gave an average decay rate of 5.1 disintegrations per minute (dpm) per gram of carbon. The current ^{14}C/^{12}C ratio in living organisms is 1.3 × 10^{−12}, with a decay rate of 15 dpm/g C. How long ago was the sagebrush in the sandals cut? The halflife of ^{14}C is 5730 yr.
Given: radioisotope, current ^{14}C/^{12}C ratio, initial decay rate, final decay rate, and halflife
Asked for: age
Strategy:
A Use Equation 14.30 to calculate N_{0}/N, the ratio of the number of atoms of ^{14}C originally present in the sample to the number of atoms now present.
B Substitute the value for the halflife of ^{14}C into Equation 14.28 to obtain the rate constant for the reaction.
C Substitute the calculated values for N_{0}/N and the rate constant into Equation 14.32 to obtain the elapsed time t.
Solution:
We can use the integrated rate law for a firstorder nuclear reaction (Equation 14.32) to calculate the amount of time that has passed since the sagebrush was cut to make the sandals:
\(\ln \dfrac{N}{N_0} = kt\)
A From Equation 14.30, we know that A = kN. We can therefore use the initial and final activities (A_{0} = 15 and A = 5.1) to calculate N_{0}/N:
\(\dfrac{A_0}{A}=\dfrac{kN_0}{kN}=\dfrac{N_0}{N}=\dfrac{15}{5.1}\)
B Now we can calculate the rate constant k from the halflife of the reaction (5730 yr) using Equation 14.28:
\(t_{1/2}=\dfrac{0.693}{k}\)
Rearranging this equation to solve for k,
\(k=\dfrac{0.693}{t_{1/2}}=\dfrac{0.693}{\textrm{5730 yr}}=1.21×10^{−4}\textrm{ yr}^{−1}\)
C Substituting the calculated values into the equation for t,
\(t=\dfrac{\ln(N_0/N)}{k}=\dfrac{\ln(15/5.1)}{1.21×10^{−4}\textrm{ yr}^{−1}}=\textrm{8900 yr}\)
Thus the sagebrush in the sandals is about 8900 yr old.
Exercise \(\PageIndex{1}\)
While trying to find a suitable way to protect his own burial chamber, the ancient Egyptian pharaoh Sneferu developed the pyramid, a burial structure that protected desert graves from thieves and exposure to wind. Analysis of the ^{14}C content of several items in pyramids built during his reign gave an average decay rate of 8.6 dpm/g C. When were the objects in the chamber created?
Answer:
Approximately 4600 yr ago, or about 2600 BC
Nuclear Stability
The nucleus of an atom occupies a tiny fraction of the volume of an atom and contains the number of protons and neutrons that is characteristic of a given isotope. Electrostatic repulsions would normally cause the positively charged protons to repel each other, but the nucleus does not fly apart because of the strong nuclear force, an extremely powerful but very shortrange attractive force between nucleons (Figure \(\PageIndex{1}\)). All stable nuclei except the hydrogen1 nucleus (^{1}H) contain at least one neutron to overcome the electrostatic repulsion between protons. As the number of protons in the nucleus increases, the number of neutrons needed for a stable nucleus increases even more rapidly. Too many protons (or too few neutrons) in the nucleus result in an imbalance between forces, which leads to nuclear instability.
Figure \(\PageIndex{1}\): Competing Interactions within the Atomic Nucleus. Electrostatic repulsions between positively charged protons would normally cause the nuclei of atoms (except H) to fly apart. In stable atomic nuclei, these repulsions are overcome by the strong nuclear force, a shortrange but powerful attractive interaction between nucleons. If the attractive interactions due to the strong nuclear force are weaker than the electrostatic repulsions between protons, the nucleus is unstable, and it will eventually decay.
The relationship between the number of protons and the number of neutrons in stable nuclei, arbitrarily defined as having a halflife longer than 10 times the age of Earth, is shown graphically in Figure \(\PageIndex{2}\). The stable isotopes form a “peninsula of stability” in a “sea of instability.” Only two stable isotopes, ^{1}H and ^{3}He, have a neutrontoproton ratio less than 1. Several stable isotopes of light atoms have a neutrontoproton ratio equal to 1 (e.g.,
Figure \(\PageIndex{2}\): The Relationship between Nuclear Stability and the NeutrontoProton Ratio. In this plot of the number of neutrons versus the number of protons, each black point corresponds to a stable nucleus. In this classification, a stable nucleus is arbitrarily defined as one with a halflife longer than 46 billion years (10 times the age of Earth). As the number of protons (the atomic number) increases, the number of neutrons required for a stable nucleus increases even more rapidly. Isotopes shown in red, yellow, green, and blue are progressively less stable and more radioactive; the farther an isotope is from the diagonal band of stable isotopes, the shorter its halflife. The purple dots indicate superheavy nuclei that are predicted to be relatively stable, meaning that they are expected to be radioactive but to have relatively long halflives. In most cases, these elements have not yet been observed or synthesized. Data source: National Nuclear Data Center, Brookhaven National Laboratory, Evaluated Nuclear Structure Data File (ENSDF), Chart of Nuclides, http://www.nndc.bnl.gov/chart.
As shown in Figure \(\PageIndex{3}\), more than half of the stable nuclei (166 out of 279) have even numbers of both neutrons and protons; only 6 of the 279 stable nuclei do not have odd numbers of both. Moreover, certain numbers of neutrons or protons result in especially stable nuclei; these are the socalled magic numbers 2, 8, 20, 50, 82, and 126. For example, tin (Z = 50) has 10 stable isotopes, but the elements on either side of tin in the periodic table, indium (Z = 49) and antimony (Z = 51), have only 2 stable isotopes each. Nuclei with magic numbers of both protons and neutrons are said to be “doubly magic” and are even more stable. Examples of elements with doubly magic nuclei are \(^4_2 \textrm{He}\)
Figure \(\PageIndex{3}\): The Relationship between the Number of Protons and the Number of Neutrons and Nuclear Stability.
Most stable nuclei contain even numbers of both neutrons and protons
The pattern of stability suggested by the magic numbers of nucleons is reminiscent of the stability associated with the closedshell electron configurations of the noble gases in group 18 and has led to the hypothesis that the nucleus contains shells of nucleons that are in some ways analogous to the shells occupied by electrons in an atom. As shown in Figure \(\PageIndex{2}\), the “peninsula” of stable isotopes is surrounded by a “reef” of radioactive isotopes, which are stable enough to exist for varying lengths of time before they eventually decay to produce other nuclei.
Example \(\PageIndex{1}\)
Classify each nuclide as stable or radioactive.
 \(_{15}^{30} \textrm P\)
 \(_{43}^{98} \textrm{Tc}\)
 tin118
 \(_{94}^{239} \textrm{Pu}\)
Given: mass number and atomic number
Asked for: predicted nuclear stability
Strategy:
Use the number of protons, the neutrontoproton ratio, and the presence of even or odd numbers of neutrons and protons to predict the stability or radioactivity of each nuclide.
Solution:
a. This isotope of phosphorus has 15 neutrons and 15 protons, giving a neutrontoproton ratio of 1.0. Although the atomic number, 15, is much less than the value of 83 above which all nuclides are unstable, the neutrontoproton ratio is less than that expected for stability for an element with this mass. As shown in Figure 5.1.2, its neutrontoproton ratio should be greater than 1. Moreover, this isotope has an odd number of both neutrons and protons, which also tends to make a nuclide unstable. Consequently, \(_{15}^{30} \textrm P\) is predicted to be radioactive, and it is.
b. This isotope of technetium has 55 neutrons and 43 protons, giving a neutrontoproton ratio of 1.28, which places \(_{43}^{98} \textrm{Tc}\) near the edge of the band of stability. The atomic number, 55, is much less than the value of 83 above which all isotopes are unstable. These facts suggest that \(_{43}^{98} \textrm{Tc}\) might be stable. However, \(_{43}^{98} \textrm{Tc}\) has an odd number of both neutrons and protons, a combination that seldom gives a stable nucleus. Consequently, \(_{43}^{98} \textrm{Tc}\) is predicted to be radioactive, and it is.
c. Tin118 has 68 neutrons and 50 protons, for a neutrontoproton ratio of 1.36. As in part b, this value and the atomic number both suggest stability. In addition, the isotope has an even number of both neutrons and protons, which tends to increase nuclear stability. Most important, the nucleus has 50 protons, and 50 is one of the magic numbers associated with especially stable nuclei. Thus \(_{50}^{118} \textrm{Sn}\)should be particularly stable.
d. This nuclide has an atomic number of 94. Because all nuclei with Z > 83 are unstable, \(_{94}^{239} \textrm{Pu}\) must be radioactive.
Exercise
Classify each nuclide as stable or radioactive.
 \(_{90}^{232} \textrm{Th}\)
 \(_{20}^{40} \textrm{Ca}\)
 \(_8^{15} \textrm{O}\)
 \(_{57}^{139} \textrm{La}\)
Answer:
 radioactive
 stable
 radioactive
 stable
Superheavy Elements
In addition to the “peninsula of stability” there is a small “island of stability” that is predicted to exist in the upper right corner. This island corresponds to the superheavy elements, with atomic numbers near the magic number 126. Because the next magic number for neutrons should be 184, it was suggested that an element with 114 protons and 184 neutrons might be stable enough to exist in nature. Although these claims were met with skepticism for many years, since 1999 a few atoms of isotopes with Z = 114 and Z = 116 have been prepared and found to be surprisingly stable. One isotope of element 114 lasts 2.7 seconds before decaying, described as an “eternity” by nuclear chemists. Moreover, there is recent evidence for the existence of a nucleus with A = 292 that was found in ^{232}Th. With an estimated halflife greater than 10^{8} years, the isotope is particularly stable. Its measured mass is consistent with predictions for the mass of an isotope with Z = 122. Thus a number of relatively longlived nuclei may well be accessible among the superheavy elements.
Summary
Subatomic particles of the nucleus (protons and neutrons) are called nucleons. A nuclide is an atom with a particular number of protons and neutrons. An unstable nucleus that decays spontaneously is radioactive, and its emissions are collectively called radioactivity. Isotopes that emit radiation are called radioisotopes. Each nucleon is attracted to other nucleons by the strong nuclear force. Stable nuclei generally have even numbers of both protons and neutrons and a neutrontoproton ratio of at least 1. Nuclei that contain magic numbers of protons and neutrons are often especially stable. Superheavy elements, with atomic numbers near 126, may even be stable enough to exist in nature.
Key Takeaway
 Nuclei with magic numbers of neutrons or protons are especially stable, as are those nuclei that are doubly magic.Contributors
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