8.9: Covalent Bond Properties
- Page ID
- 169777
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Bond Order
Exercise \(\PageIndex{1}\)
Linus Pauling noticed that the energy of a polar bond is often greater than expected. He attributed the greater bond energy to
- a coulombic attraction between atoms with partially positive and negative charges.
- the greater bond lengths of the heteronuclear bonds.
- one of the many unexplainable phenomena that scientists encounter.
- the ability of heteronuclear species to form double and triple bonds.
- the greater number of valence electrons found in heteronuclear molecules.
- Answer
-
a. a coulombic attraction between atoms with partially positive and negative charges.
Exercise \(\PageIndex{2}\)
In molecules, as bond order increases,
- both bond length and bond energy increase.
- both bond length and bond energy decrease.
- bond length increases and bond energy is unchanged.
- bond length is unchanged and bond energy increases.
- bond length decreases and bond energy increases.
- Answer
-
e. bond length decreases and bond energy increases.
Exercise \(\PageIndex{3}\)
Determine the bond order of NO+?
a. 2 b. 1.5 c. 1 d. 2.5 e. 3
- Answer
-
e. 3
Exercise \(\PageIndex{4}\)
Use Lewis structures to predict the bond order for a sulfur-oxygen bond in SO32-?
a. 1 b. 4/3 c. 5/2 d. 2 e. 3/2
- Answer
-
a. 1
Exercise \(\PageIndex{5}\)
Use Lewis structures to predict the bond order for a sulfur-oxygen bond in the sulfite ion?
a. 1 b. 3/2 c. 4/3 d. 2 e. 5/2
- Answer
-
c. 4/3
Bond Energy
Exercise \(\PageIndex{6}\)
Based on the following data, what is the F-F bond energy?
H2(g) + F2(g) → HF(g); ΔrH = –272.5 kJ/mol-rxn
Bond Bond Energy (kJ/mol)
H-H 435
H-F 565
a. 500 kJ/mol b. 150 kJ/mol c. –150 kJ/mol d. –695 kJ/mol e. 695 kJ/mol
- Answer
-
b. 150 kJ/mol
Cleavage of one H-H bond, \(\Delta H_{1}= 435 kJ/mol;\)
Cleavage of one H-F bond, \(\Delta H_{2}= 565 kJ/mol;\)
Formation of two F-F bonds, \(\Delta H_{3}= ?\)
ΔHf of the reaction is = -272.5 kJ/mol = -545 kJ/2 mol
\(\Delta H_{f}=(\Delta H_{1}+\Delta H_{3})-(2*\Delta H_{2})\)
\(-545 = (435+\Delta H_{3})-(2*565)\)
\(-545 = (435+\Delta H_{3})-1130\)
\(585 = 435+\Delta H_{3}\)\(153 kJ = \Delta H_{3}\)
Exercise \(\PageIndex{7}\)
Using bond-energy data, what is ΔrH for the following reaction?
CH4(g) + 2Cl2(g) → CCl4(g) + 2H2(g)
Bond Bond Energy (kJ/mol)
C-H 413
H-H 432
Cl-Cl 242
C-Cl 328
a. –40 kJ/mol-rxn b. –150 kJ/mol-rxn c. 40 kJ/mol-rxn d. 1415 kJ/mol-rxn e. 150 kJ/mol-rxn
- Answer
-
a. –40 kJ/mol-rxn
Exercise \(\PageIndex{8}\)
Using the following data reactions:
ΔH° (kJ/mol-rxn)
H2(g) + Cl2(g) → 2HCl(g) –184
H2(g) → 2H(g) 432
Cl2(g) → 2Cl(g) 239
calculate the energy of an H-Cl bond.
a. 92 kJ/mol b. 855 kJ/mol c. 487 kJ/mol d. 428 kJ/mol e. 244 kJ/mol
- Answer
-
d. 428 kJ/mol
Exercise \(\PageIndex{9}\)
Which of the following species has the shortest carbon−nitrogen bond?
a. CH3CN b. CH3N2 c. CH2NH d. CH3CONH2 e. CH3NH3+
- Answer
-
a. CH3CN
Exercise \(\PageIndex{10}\)
Use the bond energies provided to complete the following statement.
________ when all of the bonds in acetic acid (CH3COOH) are broken.
Bond Bond Energy (kJ/mol)
C-H 413
C-O 358
O-H 463
C=O 745
C-C 348
C=C 614
- 3153 kJ/mol of energy is consumed
- 3153 kJ/mol of energy is released
- 2805 kJ/mol of energy is released
- 2805 kJ/mol of energy is consumed
- 2766 kJ/mol of energy is consumed
- Answer
-
a. 3153 kJ/mol of energy is consumed

