7.1: The Pauli Exclusion Principle
- Page ID
- 169578
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The Pauli Exclusion Principle
Exercise \(\PageIndex{1}\)
Which of the following statements concerning the Pauli exclusion principle is/are CORRECT?
- If two electrons occupy the same orbital they must have opposite spins.
- No two electrons in an atom can have the same four quantum numbers.
- Electrons with opposing spins are attracted to each other.
a. 1 only b. 2 only c. 3 only d. 1 and 2 e. 1,2, and 3
- Answer
-
d. 1 and 2
Quantum Numbers and Electron Configuration
Exercise \(\PageIndex{2}\)
How many electrons can be described by the following quantum numbers: n = 4, l = 2, = 2, ms = \(-1\frac{1}{2}\)?
a. 1 b. 2 c. 6 d. 10 e. 18
- Answer
-
a. 1
Exercise \(\PageIndex{3}\)
How many electrons can be described by the following quantum numbers: n = 3, l = 2, ml = 1?
a. 1 b. 2 c. 6 d. 10 e. 18
- Answer
-
b. 2
Exercise \(\PageIndex{4}\)
How many electrons can be described by the quantum numbers n= 3 and l= 2?
a. 14 b. 6 c. 2 d. 18 e. 10
- Answer
-
e. 10
Exercise \(\PageIndex{5}\)
What is the maximum number of electrons that can occupy the n = 3 shell?
a. 2 b. 8 c. 18 d. 32 e. 50
- Answer
-
a. 2
Exercise \(\PageIndex{6}\)
What is the maximum number of electrons that can occupy one s orbital?
a. 1 b. 2 c. 6 d. 10 e. 14
- Answer
-
b. 2
Exercise \(\PageIndex{7}\)
Which of the following orbital occupancy designations is incorrect?
a. 2s2 b. 3d6 c. 1s2 d. 4p3 e. 3d12
- Answer
-
e. 3d12
Exercise \(\PageIndex{8}\)
The maximum number of electrons that can be accommodated in a p subshell is
a. 10 b. 2 c. 14 d. 1 e. 6
- Answer
-
e. 6
Exercise \(\PageIndex{9}\)
Which of the following electron configurations is not allowed?
- 1s22s22p2
- 1s22s22p4
- 1s22s3
- 1s22s22p63s2
- 1s22s22p5
- Answer
-
c. 1s22s3
Exercise \(\PageIndex{10}\)
Which of the following sets of quantum numbers is allowed?
- n = 2, l = 1, = \(+\frac{1}{2}\), ms = \(-1\frac{1}{2}\)
- n = 3, l = 2, = +1, ms = +1
- n = 4, l = 1, = 0, ms = \(-1\frac{1}{2}\)
- n = 4, l = 3, = –1, ms = 0
- n = 5, l = 2, = +2, ms = –1
- Answer
-
c. n = 4, l = 1, = 0, ms = \(-1\frac{1}{2}\)

