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Chemistry LibreTexts

Homework 8

  • Page ID
    28865
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    Q1.45

    Question:

    When 12 g of sodium reacts with 23.5 g of chlorine to form sodium chloride, how many grams of sodium chloride is formed? (Assume that sodium chloride is the only product).

    Solution:

    What we know: We have a chemical reaction between sodium and chlorine to form only sodium chloride. We are also given the masses of the reactants, 12 g of sodium and 23.5 g of chlorine. We also know that the Law of Conservation of Mass tells us that matter is neither created nor destroyed in a chemical reaction.

    What we're asked for: The mass, in grams, of sodium chloride formed from the reaction.

    Strategy:

    A. Find the sum of the masses of the reactants from the chemical equation.

    Solution:

    12 g + 23.5 g = 35.5 g

    35.5 g of sodium chloride is formed from the reaction.

    Q2.47

    Question:

    How many Magnesium atoms are there in 4.67 mol of Magnesium?

    Solution:

    What we know: We know that we have 4.67 mol of Magnesium.

    What we are asked for: The number of Magnesium atoms present.

    Strategy:

    A. Familiarize yourself with Avogadro's number which is 6.022 x 1023.

    B. Set up a dimensional analysis equation to convert Magnesium moles to Magnesium atoms.

    C. Carry out the equation.

    Solution:

    A. 1 mol is equal to 6.022 x 1023 of anything, but in this case Magnesium atoms.

    B. \[4.67 mol Mg \times \frac{6.022\times 10^{23} atoms Mg}{1 mol Mg}\]

    C. The "mol Mg" units cancel so you're left with:

    \[4.67 \times (6.022\times 10^{23} atoms Mg) = 2.81\times 10^{24} atoms Mg\]

    2.81 x 1024 atoms of Magnesium are in 4.67 mol of Magnesium


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