Skip to main content
Chemistry LibreTexts

Homework 70

  • Page ID
  • \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)


    A.Sodium Hypochlorite (bleach) has a density of 1.11 g/cm3 and a volume of 48.21 mL, what is the mass?

    B. What is the volume of 8.31 g of bleach?

    Use the correct units in your answers.


    a. m= 53.51g

    b. V= 7.49mL

    Strategy for part A

    1. Recognize the equation for density is density (d) equals mass (m) divided by volume (V)


    2. Plug in the provided information from the question above


    3. Now convert cm3 into mL using the conversion factor 1 cm3=1 mL, these units should then cancel each other out leaving only grams as the unit. (This is what mass is measured in)

    4.Now solve for m (mass).


    Strategy for part B

    1. Use the density formula from part a to plug in the information given in the question above


    2. Plug in the values from the question above


    3. To get volume in mL, convert cm3 to mL use the conversion factor 1 cm3= 1 mL (This is what volume is measured in)

    4. Solve for V



    If an electron moves from a 3p orbital to a 2p orbital, does it give off energy or gain energy? Why?


    1. Identify the location of each orbital and how this relates to their energy levels

    2. Explain why your answer is correct, referring to the movement of photons


    The 3p orbital is further away from the nucleus than the 2p orbital.The closer an electron is to the nucleus the less amount of energy it has.Thus, the electron will give off energy due to its movement from a higher level orbital to a lower level orbital releasing a photon of energy in the process. When the electron gets excited it will jump back up to a higher level orbital.

    Homework 70 is shared under a not declared license and was authored, remixed, and/or curated by LibreTexts.

    • Was this article helpful?