8.E: Homework Chapter 8 Answer Key
- Page ID
- 202175
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\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)General Questions
1. 3 pizzas, limited by the cheese
Mole-to-Mole Conversions
3. 0.28 moles Cl2(g)
5. 3.0 moles NH3
7. 2.4 moles NaCl(aq)
9. 2NO(g) + 5H2(g) → 2NH3(g) + 2H2O(g)
2.18 moles NH3
11. 2.30 moles aluminum chloride
13. Cu2O(s) + C(s) → 2Cu(s) + CO(g)
3.2 moles carbon
Mass-to-Mass Conversions
15. 31.3 g NaCl
17. 25.1 g CH3OH
19. 2Al(s) + 3Cl2(g) → 2AlCl3(s)
0.56 g AlCl3
21. 2Fe(s) + 3S(l) → Fe2S3(s)
6.0 g Fe2S3
23. 94.2 g NO2
25. 6CO2(g) + 6H2O(l) → 6O2(g) + C6H12O6(aq)
3.8 g C6H12O6
4.1 g O2
Limiting Reactant, Theoretical Yield, and Percent Yield
27. Limiting reactant: 1.4 mol Cl2
2.8 mol KCl
29. 5.54 g H2O
18.0 g NaCl
Limiting reactant: 12.3 g NaOH
31. Limiting reactant: 0.56 mol Al
33. Limiting reactant: 1.4 g Mg
35. Limiting reactant: 21.88 g Cl2
Theoretical yield: 22.5 g HCl
54.84%
37. 4AB + C2 → 2(AB)2C
Limiting reactant: 34.5 g AB
39.2 g C2
42.9 g (AB)2C
39. C6H12O6 + 6O2 → 6CO2 + 6H2O
a. Limiting reactant: 10.5 mol O2
b. 0 Limiting reactant: 0.45 mol O2
c. 2 Limiting reactant: 13.5 g O2
d. 4 Limiting reactant: 45.654 g C6H12O6
41. SnO2 + 2H2 → Sn + 2H2O
Limiting reactant: 5.6 mol H2
3.3 x 10^2 g Sn, 11 g H2, 1.0 x 10^2 g H2O, 90. g SnO2
Challenge Problems
43. 6CO2 + 6H2O → C6H12O6 + 6O2
57.5 g C6H12O6
45. 81% CO2
57% H2O
90% NaC2H3O2
Limiting reactant: 0.99 g NaHCO3
0.52 g CO2, 0.21 g H2O, 0.97 g NaC2H3O2
47. Mg(OH)2(s) + 2HCl(aq) → MgCl2(aq) + 2H2O(l)
3.6 g Mg(OH)2