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Chemistry LibreTexts

3.4: Units in the Numerator and the Denominator

  • Page ID
    451501
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    Learning Objectives
    • Given a quantity, convert from one set of units to another using dimensional analysis showing canceling on units. This includes compound units (eg: mph to kps).

    Compound Units

    There are many units that combine a unit in the numerator with a unit in the denominator. Common examples are miles per hour, meters per second, and miles per gallon. The "per" that appears when we talk about the compound unit or when we write it in text form translates to the divider between numerator and denominator when we write it symbolically. Therefore miles per hour would be written mi/h, meters per second would be written m/s, and miles per gallon would be written mi/gal.

    For example, suppose we want to convert 0.0128 kilometers per minute to meters per hour.

    Concept Map

    when converting from km per min to m per hour use 60 min over 1 hour to get to km per hour and then 1000 m over 1 km to get to m per hour.

    Calculation

    \[ \begin{align*} \dfrac{0.0128 \; \cancel{\rm{km}}}{1\; \cancel{\rm{min}}} \times \dfrac{60 \; \cancel{\rm{min}}}{1\; \rm{h}} \times \dfrac{1,000\; \rm{m}}{1\; \cancel{\rm{km}}} & = \dfrac{768\; \rm{m}}{\rm{h}} \\ &= 768 \; \rm{m/h}\ \end{align*}\]

    Which we would write or say as 768 meters per hour.

    Example \(\PageIndex{1}\): Unit Conversion

    Convert 45 miles per gallon to kilometers per liter in one multi-step calculation.

    Solution

    Steps for Problem Solving

    Unit Conversion

    Identify the "given" information and what the problem is asking you to "find."

    Given: 45 mi/gal

    Find: km/L

    List other known quantities

    \(1 km = 0.6214 mi \)

    \(1 gal = 3.785 L \)

    Prepare a concept map.


    when converting from miles per gallon to km per liter use 1 gallon over 3.785 L to get to miles per liter and then use i km over 0.6214 miles to get to km per liter

    Calculate.

    \[ \begin{align*} \dfrac{45 \; \cancel{\rm{mi}}}{1\; \cancel{\rm{gal}}} \times \dfrac{1 \; \cancel{\rm{gal}}}{3.785\; \rm{L}} \times \dfrac{1\; \rm{km}}{0.6214\; \cancel{\rm{mi}}} & = \dfrac{19\; \rm{km}}{\rm{L}} \\ &= 19 \; \rm{km/L}\ \end{align*}\]
    Exercise \(\PageIndex{1}\)

    Convert 1.25 cm/s to in/min.

    Answer
    \(29.5\, in/min\)

    3.4: Units in the Numerator and the Denominator is shared under a not declared license and was authored, remixed, and/or curated by LibreTexts.

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