9.7.2: Practice Solution Concentration
- Page ID
- 236056
Exercise \(\PageIndex{1}\)
How many grams of glucose (molar mass = 180.18 g/mol) are dissolved in 175 mL of a 2.00 M solution?
- Answer
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63.1 g. (0.350 moles)
Exercise \(\PageIndex{1}\)
How many mL of 5.25 M HCl solution would be needed to react with 6.00 g of Zn in the reaction below?
Zn (s) + 2 HCl (aq) --> ZnCl2 (aq) + H2 (g)
- Answer
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35.0 mL (0.0350 L, 0.184 moles)
Titration Problems
Exercise \(\PageIndex{1}\)
You perform the titration below on 12.00 mL of H2SO4 solution. You find that it takes 26.44 mL of 0.4483 M NaOH to react completely. What is the concentration of the H2SO4 solution?
H2SO4 (aq) + 2 NaOH (aq) \(\rightarrow\) Na2SO4 (aq) + 2 H2O (l)
- Answer
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0.4939 M H2SO4
You perform the titration below on 20.00 mL of HCl solution. You find that it takes 18.72 mL of 0.3786 M NaOH to react completely. What is the concentration of the HCl solution?
HCl (aq) + NaOH (aq) \(\rightarrow\) NaCl (aq) + H2O (l)
- Answer
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0.3544 M HCl
You perform the titration below on 15.00 mL of HCl solution. You find that it takes 26.44 mL of 0.1352 M Ba(OH)2 to react completely. What is the concentration of the HCl solution?
2 HCl (aq) + Ba(OH)2 (aq) \(\rightarrow\) BaCl2 (aq) + 2 H2O (l)
- Answer
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0.4766 M HCl
Solution Stoichiometry
Exercise \(\PageIndex{1}\)
In the reaction below, what volume of 0.7644 M Pb(NO3)2 solution is needed in order to make 37.06 g PbCl2? (Molar mass of PbCl2 is 278.1 g/mol. NaCl is in excess.)
Pb(NO3)2 (aq) + 2 NaCl (aq) \(\rightarrow\) 2 NaNO3 (aq) + PbCl2 (s)
- Answer
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174.3 mL (0.1743 L)
In the reaction below, what volume of 0.3805 M Pb(NO3)2 solution is needed to react with 455.0 mL of 0.6322 M NaCl solution?
Pb(NO3)2 (aq) + 2 NaCl (aq) \(\rightarrow\) 2 NaNO3 (aq) + PbCl2 (s)
- Answer
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378.0 mL (0.3780 L)